Ta có :

\(\frac{x-3}{97}+\frac{x-27}{73}+\frac{x-67}{33}+\frac{x-73}{27}=4\)

\(\Leftrightarrow\left(\frac{x-3}{97}-1\right)+\left(\frac{x-27}{73}-1\right)+\left(\frac{x-67}{33}-1\right)+\left(\frac{x-73}{27}-1\right)=0\)

\(\Leftrightarrow\frac{x-100}{97}+\frac{x-100}{73}+\frac{x-100}{33}+\frac{x-100}{27}=0\)

\(\Leftrightarrow\left(x-100\right)\left(\frac{1}{97}+\frac{1}{73}+\frac{1}{33}+\frac{1}{27}\right)=0\)

Vì \(\frac{1}{97}+\frac{1}{73}+\frac{1}{33}+\frac{1}{27}>0\) Nên \(x-100=0\)

\(\Leftrightarrow x=100\)

Vậy \(x=100\)

\(\Leftrightarrow\frac{x-3}{87}+\frac{x-27}{79}+\frac{x-67}{33}+\frac{x-73}{27}-4=0\)

\(\Leftrightarrow\left(\frac{x-3}{97}-1\right)+\left(\frac{x-27}{73}-1\right)+\left(\frac{x-67}{33}-1\right)+\left(\frac{x-73}{27}-1\right)=0\)

\(\Leftrightarrow\left(\frac{x-3-97}{97}\right)+\left(\frac{x-27-73}{73}\right)+\left(\frac{x-67-33}{33}\right)+\left(\frac{x-73-27}{27}\right)=0\)

\(\Leftrightarrow\frac{x-100}{97}+\frac{x-100}{73}+\frac{x-100}{33}+\frac{x-100}{27}=0\)

\(\Leftrightarrow\left(x-100\right)\left(\frac{1}{97}+\frac{1}{73}+\frac{1}{33}+\frac{1}{27}\right)=0\)

Vì \(\frac{1}{97}+\frac{1}{73}+\frac{1}{33}+\frac{1}{27}\ne0\)

\(\Rightarrow x-100=0\Leftrightarrow x=100\)

\(\frac{x-3}{97}+\frac{x-27}{73}+\frac{x-67}{33}+\frac{x-73}{27}=4\)    

\(\frac{x-3}{97}-1+\frac{x-27}{73}-1+\frac{x-67}{33}-1+\frac{x-73}{27}-1=4-1-1-1-1\)     

\(\frac{x-100}{97}+\frac{x-100}{73}+\frac{x-100}{33}+\frac{x-100}{27}=0\)    

\(\left(x-100\right)\left(\frac{1}{97}+\frac{1}{73}+\frac{1}{33}+\frac{1}{27}\right)=0\)   

\(x-100=0\) 

\(x=100\)

giúp mình với

a) (x + 5) / 95 + (x +10)/90 + (x + 15)/85 + (x + 20)/80 = -4

<=> (x + 5)/95 + (x + 5)/90 + 5/90 + (x + 5)/85 + 10/85+ (x + 5)/80 + 15/80 = -4

<=> (x + 5)(1/95+1/90+1/85+1/80) =-4 -5/90-10/85-15/85

<=> (x + 5)(1/95+1/90+1/85+1/80)= -1-(1 + 5/90 )-(1 + 10/85)  - (1 + 15/80)

<=>(x + 5)(1/95+1/90+1/85+1/80) = -1 - 95/90 - 95/85 - 95/80

<=>(x + 5)(1/95+1/90+1/85+1/80) = -95 (1/95+1/90+1/85+1/80)

<=> x + 5 = -95 => x = -100

b) Làm tương tự phần a => Kết quả x = 100

(x-13)/87+(x-27)/73+(x-67)/33+(x-73)/27=4

=>(x-13-87)/87+(x-27-73)/73+(x-67-33)/33+(x-73-27)/27=4-1-1-1-1

=>(x-100)/87+(x-100)/73+(x-100)/33+(x-100)/27=0

=>(x-100)*(1/87+1/73+1/33+1/27)=0

=>x-100=0

=>x=100

\(\dfrac{x-13}{87}+\dfrac{x-27}{73}+\dfrac{x-67}{83}+\dfrac{x-73}{27}=4\)

<=>\(\dfrac{x-13}{87}-1+\dfrac{x-27}{73}-1+\dfrac{x-67}{83}-1+\dfrac{x-73}{27}-1=0\)

<=>\(\dfrac{x-100}{87}+\dfrac{x-100}{73}+\dfrac{x-100}{83}+\dfrac{x-100}{27}=0\)

<=>\(\left(x-100\right)\left(\dfrac{1}{87}+\dfrac{1}{73}+\dfrac{1}{83}+\dfrac{1}{27}\right)=0\)

Do \(\dfrac{1}{87}+\dfrac{1}{73}+\dfrac{1}{83}+\dfrac{1}{27}>0\)

=>x-100=0

<=>x=100

\(\dfrac{x-13}{87}+\dfrac{x-27}{73}+\dfrac{x-67}{83}+\dfrac{x-73}{27}=4\)

\(\Rightarrow\left(\dfrac{x-13}{87}-1\right)+\left(\dfrac{x-27}{73}-1\right)+\left(\dfrac{x-67}{83}-1\right)+\left(\dfrac{x-73}{27}\right)=0\)

\(\Rightarrow\dfrac{x-100}{87}+\dfrac{x-100}{73}+\dfrac{x-100}{83}+\dfrac{x-100}{27}=0\)

\(\Rightarrow\left(x-100\right)\left(\dfrac{1}{87}+\dfrac{1}{73}+\dfrac{1}{83}+\dfrac{1}{27}\right)=0\)

\(\Rightarrow x-100=0\Rightarrow x=100\)

\(a,\)\(9-25=\left(7-x\right)-\left(25+7\right)\)

\(-16=\left(7-x\right)-32\)

\(7-x=-16+32\)

\(7-x=16\)

\(x=7-16=-9\)

\(b,-7624+\left(1543+7624\right)-x=25\)

\(-7624+9167-x=25\)

\(1543-x=25\)

\(x=1543-25\)

\(x=1518\)

\(c,\left(27-514\right)-\left(486-73\right)+x=7\)

\(-487-413+x=7\)

\(-900+x=7\)

\(x=7+900\)

\(x=907\)

a, \(\left(-236\right).41+236.\left(-59\right)=\left(-236\right).\left(41+59\right)=\left(-236\right).100=-23600\)

b,\(138.\left(-125\right)-\left(-138\right).25=138.\left[\left(-125\right)-\left(-25\right)\right]=138.100=13800\)

c, \(\left(-271\right).\left(-159\right)+271.\left(-59\right)=271.\left[159+\left(-59\right)\right]=217.100=27100\) 

d, \(129.\left(-73\right)+\left(-129\right).27=129.\left(-73-27\right)=129.\left(-100\right)=-12900\)

e, \(256.\left(-57\right)-\left(-256\right).\left(-43\right)=256.\left(-57-43\right)=256.\left(-100\right)=-25600\)

f, \(\left(-234\right).67+234.\left(-33\right)=234.\left(-67-33\right)=234.\left(-100\right)=-23400\)

ko cần chép đề nha

a. 236x(-41)+236x(-59)

=236x[(-41)+(-59)]

=236x(-100)

=-23600

b.-138x125-(-138)x25

=(-138)x(125-25)

=(-138)x100

=-13800

c.câu này mik giải thích là khi chuyển dấu "-" của -59 sang -271 thì -- sẽ biến thành +

c. 271x159+271x(-59)

=271x(159+(-59))

=271x100

=27100

d(-129)x73+(-129)x27

=(-129)x(73+27)

=(-129)x100

=-12900

e. (-256)x57-(-256)x(-43)

=(-256)x[57-(-43)]

=-256x100

=-25600

Cảm ơn bạn nha

x=50 thư chị hà

bài dễ ợt,mỗi vế trừ đi 2

Bạn thử làm coi , theo cách của bạn ấy !

a, 45 x 46 + 45 x 45 - 30 - 15= 45x( 46+45) -30 -15= 45 x 91 - 30 - 15= 4095 - 30 - 15= 4050

b, 891 x 29 + 29 x 8+ 29= 29 x ( 891 + 8+ 1)= 29 x 900= 26100

c, 73 x ( 84+17) + 27 x (74+27)= 73 x 101 + 27 x 101= 101 x ( 73+27)= 101 x 100= 10100

d, chịu

d, đề bài= 13 x ( 99 + 2) + 13 x 1001+ 11 x 1300= 13 x 101 + 13 x 1001+ 13 x 1100= 13 x ( 101 + 1001 + 1100) = 13 x 2202= 28626