i don't care :))

9/4.7/17+2

=63/68+2

=63/68+136/68=199/68

1/4.3/1-21/4.13/17

=1/4.3/17-21/4.14/17

=3/68-273/68=-270/68=-135/68

các bn lm đến đâu cx dc miễn là lm hộ mk cái ạ, ai đang lm vào nhắn tin vs mk để mk bít nha

a; \(-\dfrac{8}{3}+\dfrac{7}{5}-\dfrac{71}{15}< x< -\dfrac{13}{7}+\dfrac{19}{14}-\dfrac{7}{2}\)

              -\(\dfrac{19}{15}\) - \(\dfrac{71}{15}\) < \(x\) < -\(\dfrac{1}{2}\) - \(\dfrac{7}{2}\)

              -6 < \(x\) < -4

             vì \(x\) \(\in\) Z nên \(x\) = -5

- \(\dfrac{19}{6}+\dfrac{-15}{2}+\dfrac{11}{3}\) < \(x\) < - \(\dfrac{5}{4}\) + \(\dfrac{19}{12}\) - \(\dfrac{10}{3}\)

- \(\dfrac{32}{3}+\dfrac{11}{3}< x< \) \(\dfrac{1}{3}\) - \(\dfrac{10}{3}\)

-7 < \(x\) < - 3

Vì \(x\in\) Z nên \(x\in\) {-6;-5;-4}

`3/7xx14/5+32/5xx3/7+3/7xx9/5`

`=3/7xx(14/5+32/5+9/5)`

`=3/7xx55/5`

`=3/7xx5`

`=15/7`

\(=\frac{3}{7}\times[\frac{14}{5}+\frac{32}{5}+\frac{9}{5}]=\frac{3}{7}\times\frac{55}{5}=\frac{3}{7}\times11=\frac{33}{7}\)

\(a,-\dfrac{12}{16}-\left(\dfrac{3}{4}-x\right)=-\dfrac{5}{3}\)

\(\dfrac{3}{4}-x=-\dfrac{12}{16}-\left(-\dfrac{5}{3}\right)\)

\(\dfrac{3}{4}-x=\dfrac{11}{12}\)

\(x=\dfrac{3}{4}-\dfrac{11}{12}\)

\(x=-\dfrac{1}{6}\)

\(b,x-\dfrac{3}{7}:\dfrac{9}{14}=-\dfrac{7}{3}\)

\(x-\dfrac{3}{7}=-\dfrac{7}{3}\times\dfrac{9}{14}\)

\(x-\dfrac{3}{7}=-\dfrac{3}{2}\)

\(x=-\dfrac{3}{2}+\dfrac{3}{7}\)

\(x=-\dfrac{15}{14}\)

\(c,-\dfrac{3}{4}x+\dfrac{5}{8}x=\dfrac{1}{3}\)

\(\left(-\dfrac{3}{4}+\dfrac{5}{8}\right)x=\dfrac{1}{3}\)

\(-\dfrac{1}{8}x=\dfrac{1}{3}\)

\(x=\dfrac{1}{3}:\left(-\dfrac{1}{8}\right)\)

\(x=-\dfrac{8}{3}\)

`-12/16 - ( 3/4 - x ) = -5/3`

`=> 3/4 - x=-12/16 -(-5/3)`

`=> 3/4 - x=-12/16 +5/3`

`=> 3/4 - x=11/12`

`=> x= 3/4-11/12`

`=> x=9/12 -11/12`

`=> x=-1/6`

__

`x - 3/7 : 9/14 = - 7/3`

`=>x - 3/7=-7/3 xx 9/14`

`=>x - 3/7=-3/2`

`=>x= -3/2 + 3/7`

`=>x=-15/14`

__

`-3/4 x + 5/8 x =1/3`

`=> (-3/4 + 5/8) x =1/3`

`=> ( -6/8+ 5/8) x =1/3`

`=> -1/8 x=1/3`

`=>x= 1/3 : (-1/8)`

`=> x= 1/3 xx (-8)`

`=>x= -8/3`

kết quả

=6017

tích tui tui tích lại

555 + 5455 + 3 + 4 

= 6017

Xin hãy nhớ Đúng 0

555 + 5455 + 3 + 4 = 6017

a) 17 - 14( x + 1 ) = 13 - 4( x + 1 ) - 5( x - 3 )

<=> 17 - 14x - 14 = 13 - 4x - 4 - 5x + 15

<=> 17 - 14 - 13 + 4 - 15 = -4x - 5x + 14x 

<=> -21 = 5x

<=> x = -21/5

b) 7( 4x + 3 ) - 4( x - 1 ) = 15( x + 0, 75 ) + 7

<=> 28x + 21 - 4x + 4 = 15x + 45/4 + 7

<=> 28x - 4x - 15x = 45/4 + 7 - 21 - 4

<=> 9x = -27/4

<=> x = -3/4

c) 3x( x + 1 ) - 2x( x + 2 ) = x² - 1

<=> 3x² + 3x - 2x² - 4x = x² - 1

<=> 3x² + 3x - 2x² - 4x - x² = -1

<=> -x = -1

<=> x = 1 

a, \(17-14\left(x+1\right)=13-4\left(x+1\right)-5\left(x-3\right)\)

\(\Leftrightarrow17-14x-14=13-4x-4-5x+15\)

\(\Leftrightarrow3-14x=24-9x\Leftrightarrow3-14x-24+9x=0\)

\(\Leftrightarrow-21-5x=0\Leftrightarrow5x=-21\Leftrightarrow x=-\frac{21}{5}\)

b, \(7\left(4x+3\right)-4\left(x-1\right)=15\left(x+0,75\right)+7\)

\(\Leftrightarrow28x+21-4x+1=15x+\frac{45}{4}+7\)

\(\Leftrightarrow9x=-\frac{27}{4}\Leftrightarrow x=-\frac{3}{4}\)

c, \(3x\left(x+1\right)-2x\left(x+2\right)=x^2-1\)

\(\Leftrightarrow3x^2+3x-2x^2-4x=x^2-1\)

\(\Leftrightarrow x^2-x=x^2-1\Leftrightarrow x=1\)

17/12

LÀ 7/12 NHÉ

\(\frac{17}{14}:\frac{x}{y}=1-\frac{1}{7}\)

\(\frac{17}{14}:\frac{x}{y}=\frac{6}{7}\)

\(\frac{x}{y}=\frac{17}{14}:\frac{6}{7}\)

\(\frac{x}{y}=\frac{17}{12}\)

a, 2/3 - 2/9 + 7/9 = 6/9 - 2/9 + 7/9 = 10/9
b, 7/6 + 3/5 : 6 = 7/6 + 3/5 x 1/6 = 7/6 + 1/10 = 70/60 + 6/10 = 76/10 = 38/5
c, x : 6/25 = 18

x = 18 x 6/25

x = 36/25
d, ( 2/5 + 4/7) : x = 17/5

29/35 : x = 17/5

x = 29/35 : 17/5

x = 29/119

\(a.\dfrac{2}{3}-\dfrac{2}{9}+\dfrac{7}{9}=\dfrac{6}{9}-\dfrac{2}{9}+\dfrac{7}{9}=\dfrac{4}{9}+\dfrac{7}{9}=\dfrac{11}{9}\\ b.\dfrac{7}{6}+\dfrac{3}{5}:6=\dfrac{7}{6}+\dfrac{3}{5}\times\dfrac{1}{6}=\dfrac{7}{6}+\dfrac{1}{10}=\dfrac{70}{60}+\dfrac{6}{60}=\dfrac{76}{60}=\dfrac{19}{15}\\ c.x:\dfrac{6}{25}=18\\ x=18\times\dfrac{6}{25}\\ x=\dfrac{108}{25}\\ d.\left(\dfrac{2}{5}+\dfrac{4}{7}\right):x=\dfrac{17}{5}\\ \dfrac{34}{35}:x=\dfrac{7}{5}\\ x=\dfrac{34}{35}:\dfrac{7}{5}\\ x=\dfrac{34}{49}\)