\(\frac{5}{\frac{\frac{19}{3}}{19}-}-\frac{5}{\frac{14}{\frac{3}{14}+\frac{3}{11}}}+\frac{5}{11}\)
Những câu hỏi liên quan
B=\(\frac{5}{7}.\frac{14}{11}-\frac{5}{7}.\frac{5}{11}-\frac{5}{11}.\frac{2}{7}\)
C=\(1+\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+\frac{2}{30}+\frac{2}{42}\)
D=\(\frac{0,75-0,6+\frac{3}{19}+\frac{3}{19}}{2,75-2,2+\frac{11}{19}+\frac{11}{91}}\)
\(\frac{2}{7}.5\frac{1}{4}-\frac{2}{7}.3\frac{1}{4}\)
\(11\frac{3}{13}\)\(11\frac{3}{13}-\left(2\frac{4}{7}+5\frac{3}{13}\right)\)
\(3\frac{14}{19}+\frac{13}{17}+\frac{35}{43}+6\frac{5}{19}+\frac{8}{43}\)
\(\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+1\frac{5}{7}\)
Bài 1: tính nhanha)6frac{4}{5}-left(1frac{2}{3}+3frac{4}{5}right)b)left(frac{-4}{5}+frac{4}{3}right)+left(frac{-5}{4}+frac{14}{5}right)-frac{7}{3}c)frac{8}{3}.frac{2}{5}.frac{3}{8}.10frac{19}{92}d)frac{-5}{7}.frac{2}{11}+frac{-5}{7}.frac{9}{14}+1frac{5}{7}e)frac{12}{19}.frac{7}{15}.frac{-13}{17}.frac{19}{12}.frac{17}{13}
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Bài 1: tính nhanh
a)\(6\frac{4}{5}-\left(1\frac{2}{3}+3\frac{4}{5}\right)\)
b)\(\left(\frac{-4}{5}+\frac{4}{3}\right)+\left(\frac{-5}{4}+\frac{14}{5}\right)-\frac{7}{3}\)
c)\(\frac{8}{3}.\frac{2}{5}.\frac{3}{8}.10\frac{19}{92}\)
d)\(\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{14}+1\frac{5}{7}\)
e)\(\frac{12}{19}.\frac{7}{15}.\frac{-13}{17}.\frac{19}{12}.\frac{17}{13}\)
Tính hợp lí:
A = \(\left(\frac{-4}{5}+\frac{4}{3}\right)+\left(\frac{-5}{4}+\frac{14}{5}\right)-\frac{7}{3}\)
B= \(\frac{8}{3}.\frac{2}{5}.\frac{3}{8}.10.\frac{19}{92}\)
C= \(\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{14}+1\frac{5}{7}\)
A= (-4/5+4/3)+(-5/4+14/5)-7/3
= 8/15+31/20-7/3
= 25/12-7/3
= -1/4
B= 8/3.2/5.3/8.10.19/92
= 16/15.3/8.10.19/92
= 2/5.10.19/92
= 4.19/92
= 19/23
C= \(\frac{-5}{7}\).\(\frac{2}{11}\)+\(\frac{-5}{7}\).\(\frac{9}{14}\)+1\(\frac{5}{7}\)
=\(\frac{-5}{7}\).\(\frac{2}{11}\)+\(\frac{-5}{7}\).\(\frac{9}{14}\)+\(\frac{12}{7}\)
= \(\frac{-10}{77}\)+\(\frac{-5}{7}\).\(\frac{9}{14}\)+\(\frac{12}{7}\)
= \(\frac{-10}{77}\)+\(\frac{-45}{98}\)+\(\frac{12}{7}\)
= \(\frac{-635}{1078}\)+\(\frac{12}{7}\)
= \(\frac{1213}{1078}\)
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9 tháng 2 2019 lúc 9:09
Giải giùm mk zới mn~~~~tặng người đầu tiên làm 4 tick nha(đảm bảo lên 4 điểm 100%)a)frac{-4}{9}.frac{7}{15}+frac{4}{-9}.frac{8}{15}b)frac{5}{-4}.frac{16}{25}+frac{-5}{4}.frac{9}{25}.c)4frac{11}{23}-frac{9}{14}+2frac{12}{23}-frac{5}{4}.d)2frac{13}{27}-frac{7}{15}+3frac{14}{27}-frac{8}{15}e)11frac{1}{4}-left{2frac{5}{7}+5frac{1}{4}right}g)frac{7}{19}.frac{8}{11}+frac{7}{19}.frac{3}{11}+frac{12}{19}
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Giải giùm mk zới mn~~~~tặng người đầu tiên làm 4 tick nha(đảm bảo lên 4 điểm 100%)
a)\(\frac{-4}{9}.\frac{7}{15}+\frac{4}{-9}.\frac{8}{15}\)
b)\(\frac{5}{-4}.\frac{16}{25}+\frac{-5}{4}.\frac{9}{25}.\)
c)\(4\frac{11}{23}-\frac{9}{14}+2\frac{12}{23}-\frac{5}{4}.\)
d)\(2\frac{13}{27}-\frac{7}{15}+3\frac{14}{27}-\frac{8}{15}\)
e)\(11\frac{1}{4}-\left\{2\frac{5}{7}+5\frac{1}{4}\right\}\)
g)\(\frac{7}{19}.\frac{8}{11}+\frac{7}{19}.\frac{3}{11}+\frac{12}{19}\)
â, -4/9(7/15+8/15)=-4/9
b,-5/4(16/25+9/25)=-5/4
,.....
dài quá mik làm ko hết
hok tốt
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\([\frac{1\frac{11}{31}.4\frac{3}{7}-\left(15-6\frac{1}{3}.\frac{2}{19}\right)}{4\frac{5}{6}+\frac{1}{6}\left(12-5\frac{1}{3}\right)}.\left(-1\frac{14}{93}\right)].\frac{31}{50}\)
[\(\frac{-75}{59}\).\(\frac{-107}{93}\)]\(\frac{31}{50}\)=\(\frac{2675}{1829}\).\(\frac{31}{50}\)=\(\frac{107}{118}\)
\(\left[\frac{1\frac{11}{31}\cdot4\frac{3}{7}-\left(15-6\frac{1}{3}\cdot\frac{2}{19}\right)}{4\frac{5}{6}+\frac{1}{6}\left(12-5\frac{1}{3}\right)}\cdot\left(-1\frac{14}{93}\right)\right]\cdot\frac{31}{50}\)
\(=\left[\frac{\frac{42}{31}\cdot\frac{31}{7}-\left(15-\frac{19}{3}\cdot\frac{2}{19}\right)}{4\frac{5}{6}+\frac{1}{6}\left(12-\frac{16}{3}\right)}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(=\left[\frac{6-\left(15-\frac{2}{3}\right)}{\frac{29}{6}+\frac{1}{6}\cdot\frac{20}{3}}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(=\left[\frac{6-15+\frac{2}{3}}{\frac{29}{6}+\frac{10}{9}}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(=\left[\frac{-\frac{25}{3}}{\frac{107}{18}}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(=\left[\left(-\frac{150}{107}\right)\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}=\frac{50}{31}\cdot\frac{31}{50}=1\)
Tính
\(\frac{1\frac{11}{31}.4\frac{3}{7}-\left(15.6\frac{1}{3}.\frac{2}{19}\right)}{-4\frac{5}{6}+\frac{1}{6}.\left(12-5\frac{1}{3}\right)}.\left(-1\frac{14}{93}\right).\frac{31}{56}\)
tính nhanh
A= \(\frac{19}{23}\cdot\frac{-4}{7}-\frac{4}{23}\cdot\frac{2}{7}\)
B= \(\frac{3}{5}+\frac{2}{5}\cdot\frac{-11}{3}+\frac{2}{3}\cdot\frac{-2}{5}+\frac{14}{15}\)
a) A = \(\frac{19}{23}.\frac{-4}{27}-\frac{4}{23}.\frac{2}{7}\)
= \(\frac{19}{7}.\frac{-4}{23}+\frac{-4}{23}.\frac{2}{7}\)
= \(\frac{-4}{23}.\left(\frac{19}{7}+\frac{2}{7}\right)\)
= \(\frac{-4}{23}.3\)
= \(\frac{-12}{23}\)
b) B = \(\frac{3}{5}+\frac{2}{5}.\frac{-11}{3}+\frac{2}{3}.\frac{-2}{5}+\frac{14}{15}\)
= \(\frac{9+14}{15}+\frac{2}{5}.\frac{-11}{3}+\frac{-2}{3}.\frac{2}{5}\)
= \(\frac{23}{15}+\frac{2}{5}\left(\frac{-11}{3}+\frac{-2}{3}\right)\)
= \(\frac{23}{15}+\frac{2}{5}.\frac{-13}{3}\)
= \(\frac{23}{15}+\frac{-26}{15}\)
= \(\frac{-3}{15}=\frac{-1}{5}\)
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Bỏ ngoặc rồi tính :a, frac{6}{7} + left(frac{2}{11}-frac{6}{7}right)- left(frac{13}{11}+1right)b, frac{-5}{11}- left(frac{17}{19}-frac{5}{11}right)- left(frac{17}{19}-2right)c, -left(frac{11}{14}-frac{8}{9}right)+ left(frac{-3}{14}-frac{8}{19}right)d, frac{3}{2} - left[left(frac{-4}{7}right)-left(frac{1}{2}+frac{5}{8}right)right]
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Bỏ ngoặc rồi tính :
a, \(\frac{6}{7}\) + \(\left(\frac{2}{11}-\frac{6}{7}\right)\)- \(\left(\frac{13}{11}+1\right)\)
b, \(\frac{-5}{11}\)- \(\left(\frac{17}{19}-\frac{5}{11}\right)\)- \(\left(\frac{17}{19}-2\right)\)
c, \(-\left(\frac{11}{14}-\frac{8}{9}\right)\)+ \(\left(\frac{-3}{14}-\frac{8}{19}\right)\)
d, \(\frac{3}{2}\) - \(\left[\left(\frac{-4}{7}\right)-\left(\frac{1}{2}+\frac{5}{8}\right)\right]\)
a, 6/7 + (2/11 - 6/7) - (13/11 + 1)
= 6/7 + 2/11 - 6/7 - 13/11 - 1
= (6/7 - 6/7) - (13/11 - 2/11) - 1
= 0 - 1 - 1
= -2
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