2011 x 2012 x 2013 x 2014 x 1005
2010 x 2011 x 2012 x 2013 x 1007
ai giai duoc minh ket ban nhe
tìm x biết (x+2014)/2011 + (x+2013)/2012 = (x+2012)/2013 + (x+2011)/2014
Giai cac Phuong trinh sau: x+1 / 2014 +x+2 / 2013=x+3 / 2012 +x+4 / 2011
Tìm x biết (2012/1+2011/2+...+1/2012)/(1/2+1/3+...+1/2013):x=-2013/2014
x-1/2011+x-2/2012+x-3/2013+x-4/2014=x+2016
/x-2011/+/x-2012/+/x-2013/+/x-2014/+/x-2015/
x-1/2014+x-2/2013=x-3/2012+x-4/2011
\(\dfrac{x-1}{2014}+\dfrac{x-2}{2013}=\dfrac{x-3}{2012}+\dfrac{x-4}{2011}\)
\(\Leftrightarrow\text{}\text{}\text{}\dfrac{x-1}{2014}-1+\dfrac{x-2}{2013}-1=\dfrac{x-3}{2012}-1+\dfrac{x-4}{2011}-1\)
\(\Leftrightarrow\dfrac{x-2015}{2014}+\dfrac{x-2015}{2013}-\dfrac{x-2015}{2012}-\dfrac{x-2015}{2011}=0\)
\(\Leftrightarrow\left(x-2015\right)\left(\dfrac{1}{2014}+\dfrac{1}{2013}-\dfrac{1}{2012}-\dfrac{1}{2011}\right)=0\)
mà \(\dfrac{1}{2014}+\dfrac{1}{2013}-\dfrac{1}{2012}-\dfrac{1}{2011}\ne0\)
nên \(x-2015=0\)
\(\Leftrightarrow x=2015\)
X+1/2014+x+2/2013=x+3/2012+x+4/2011
x+1/2014 + x+2/2013 = x+3/2012 + x+4/2011
=> x+1/2014 + 1 + x+2/2013 + 1 = x+3/2012 + 1 + x+4/2011 + 1
=> x+2015/2014 + x+2015/2013 = x+2015/2012 + x+2015/2011
=> x+2015/2012 + x+2015/2011 - x+2015/2013 - x+2015/2014 = 0
=> (x + 2015).(1/2012 + 1/2011 - 1/2013 - 1/2014) = 0
Vì 1/2011 > 1/2013; 1/2012 > 1/2014
=> 1/2012 + 1/2011 - 1/2013 - 1/2014 khác 0
=> x + 2015 = 0
=> x = -2015
tìm GTNN của |x-2011|+|x-2012|-|y+2013|+|x-2014|