15/90 × 94 + 15/94 × 98 + 15/98 × 102 + ... + 15/146 × 150

= 15/4 × (4/90×94 + 4/94×98 + 4/98×102 + ... + 4/146×150)

= 15/4 × (1/90 - 1/94 + 1/94 - 1/98 + 1/98 - 1/102 + ... + 1/146 - 1/150)

= 15/4 × (1/90 - 1/150)

= 15/4 × 1/30 × (1/3 - 1/5)

= 1/8 × 2/15

= 1/60

Ta có: \(\frac{15}{90.94}+\frac{15}{94.98}+\frac{15}{98.102}+...+\frac{15}{146.150}\)

= \(15.\left(\frac{1}{90.94}+\frac{1}{94.98}+\frac{1}{98.102}+...+\frac{1}{146+150}\right)\)

= \(15.\left[\frac{1}{4}.\left(\frac{4}{90.94}+\frac{4}{94.98}+\frac{4}{98.102}+...+\frac{4}{146+150}\right)\right]\)

= \(15.\left[\frac{1}{4}.\left(\frac{1}{90}-\frac{1}{94}+\frac{1}{94}-\frac{1}{98}+\frac{1}{98}-\frac{1}{102}+...+\frac{1}{146}-\frac{1}{150}\right)\right]\)

= \(15.\left[\frac{1}{4}.\left(\frac{1}{90}-\frac{1}{150}\right)\right]\)

= \(15.\left(\frac{1}{4}.\frac{1}{225}\right)\)

= \(=\frac{1}{60}\)

Bài làm

   \(\frac{15}{90.94}+\frac{15}{94.98}+\frac{15}{98.102}+...+\frac{15}{146.150}\)

= \(15.\frac{1}{90.94}+15.\frac{1}{94.98}+15.\frac{1}{98.102}+...+15.\frac{1}{146.150}\)

= \(15.\left(\frac{1}{90.94}+\frac{1}{94.98}+\frac{1}{98.102}+...+\frac{1}{146.150}\right)\)

= \(15.\left(\frac{1}{90}-\frac{1}{94}+\frac{1}{94}-\frac{1}{98}+\frac{1}{98}-\frac{1}{102}+...+\frac{1}{146}-\frac{1}{150}\right)\)

= \(15.\left(\frac{1}{90}-\frac{1}{150}\right)\)

= \(15.\left(\frac{5}{450}-\frac{3}{450}\right)\)

= \(15.\frac{2}{450}\)

= \(\frac{2}{30}\)

# Chúc bạn học tốt #

 \(\frac{15}{90.94}+\frac{15}{94.98}+...+\frac{15}{146.150}\)

\(=15\left(\frac{1}{90.94}+\frac{1}{94.98}+...+\frac{1}{146.150}\right)\)

\(=15.\frac{1}{4}\left(\frac{4}{90.94}+\frac{4}{94.98}+...+\frac{4}{146.150}\right)\)

\(=\frac{15}{4}\left(\frac{1}{90}-\frac{1}{94}+\frac{1}{94}-\frac{1}{98}+...+\frac{1}{146}-\frac{1}{150}\right)\)

\(=\frac{15}{4}.\left(\frac{1}{90}-\frac{1}{150}\right)\)

\(=\frac{15}{4}.\frac{1}{225}=\frac{1}{60}\)

=\(\frac{15}{4}.\left(\frac{4}{90.94}+\frac{4}{94.98}+...+\frac{4}{146.150}\right)\)

=\(\frac{15}{4}.\left(\frac{1}{90}-\frac{1}{94}+\frac{1}{94}-\frac{1}{98}+...+\frac{1}{146}-\frac{1}{150}\right)\)

=\(\frac{15}{4}.\left(\frac{1}{90}-\frac{1}{150}\right)\)

=\(\frac{15}{4}.\frac{2}{450}\)

=\(\frac{1}{60}\)

\(dungthikkothithoithanks\)

Thanh you

Đề là gì bạn

duyệt đi

Đề là Hãy rút gọn rồi quy đồng mẫu các phân số >< Bạn giúp mình nhá

a)  \(\frac{x-90}{10}+\frac{x-76}{12}+\frac{x-58}{14}+\frac{x-36}{16}+\frac{x-15}{17}=15\)

\(\Leftrightarrow\frac{x-90}{10}-1+\frac{x-76}{12}-2+\frac{x-58}{14}-3+\frac{x-36}{16}-4+\frac{x-1}{17}-5=0\)

\(\Leftrightarrow\frac{x-90-10}{10}+\frac{x-76-2.12}{12}+\frac{x-58-3.14}{14}+\frac{x-36-4.16}{16}+\frac{x-15-5.17}{17}=0\)

\(\Leftrightarrow\frac{x-100}{10}+\frac{x-100}{12}+\frac{x-100}{14}+\frac{x-100}{16}+\frac{x-100}{17}=0\)

\(\Leftrightarrow\left(x-100\right)\left(\frac{1}{10}+\frac{1}{12}+\frac{1}{14}+\frac{1}{16}+\frac{1}{17}\right)=0\)

         \(\Leftrightarrow x-100=0\Leftrightarrow x=100\)

Vậy  \(S=\left\{100\right\}\)

b)  \(\frac{x+2011}{2013}+\frac{x+2012}{2012}=\frac{x+2010}{2014}+\frac{x+2013}{2011}\)

\(\Leftrightarrow\frac{x+2011}{2013}+1+\frac{x+2012}{2012}+1=\frac{x+2010}{2014}+1+\frac{x+2013}{2011}+1\)

\(\Leftrightarrow\frac{x+2011+2013}{2013}+\frac{x+2012+2012}{2012}=\frac{x+2010+2014}{2014}+\frac{x+2013+2011}{2011}\)

\(\Leftrightarrow\frac{x+4024}{2013}+\frac{x+4024}{2012}-\frac{x+4024}{2014}-\frac{x+4024}{2011}=0\)

\(\Leftrightarrow\left(x+4024\right)\left(\frac{1}{2013}+\frac{1}{2012}-\frac{1}{2014}-\frac{1}{2011}\right)=0\)

        \(\Leftrightarrow x+4024=0\Leftrightarrow x=-4024\)

Vậy  \(S=\left\{-4024\right\}\)

Phương trình a bạn trừ phân thức đầu tiên cho 1, phân thức thứ hai cho 2, phân thức thứ ba cho 3, phân thức thứ tư cho 4, phân thức thứ năm cho 5, vế còn lại trừ đi 15. Tiếp theo bạn đặt x -100 làm nhân tử chung. Cuối cùng tìm được x= 100

Phương trình b bạn chỉ cần chuyển vế sang rồi giải tương tự phương trình a kết quả là x=-4024

\(Tìmx:\)

\(a.x:3\frac{1}{15}=1\frac{1}{12}.\)

        \(x:\frac{46}{15}=\frac{13}{12}.\)

                 \(x=\frac{13}{12}.\frac{46}{15}.\)

                  \(x=\frac{299}{90}.\)          

\(Tính:\)

\(a.\frac{41}{42}+\frac{55}{56}+\frac{71}{72}+\frac{89}{90}BCNN=2520.\)  \(=\frac{2460}{2520}+\frac{2475}{2520}+\frac{2485}{2520}+\frac{2492}{2520}.\)

\(=\frac{9912}{2520}.\)

\(=\frac{59}{15}.\)

CÂU B CỦA BÀI TÌM X MÌNH CHƯA HỌC NÊN KO BÍT LÀM!

a) x : \(3\frac{1}{5}=1\frac{1}{12}\)

x : \(\frac{16}{5}=\frac{13}{12}\)

x = \(\frac{13}{12}.\)\(\frac{16}{5}\)

x = \(\frac{208}{60}=\frac{52}{15}\)

b) x + 15% . x = 115

x + \(\frac{3}{20}\).x = 115

x.1 + \(\frac{3}{20}.x=115\)

x. (1+\(\frac{3}{20}\))=115

x. \(\frac{23}{20}=115\)

x = \(115:\frac{23}{20}\)

x=100

a)     5/30+15/90+25/150+35/210+45/270

       =1/6+1/6+1/6+1/6+1/6

       =1/6 x 5

       =5/6

b)     1/2+1/6+1/12+1/20+....+1/56

        =1/1x2+1/2x3+1/3x4+1/4x5+.....1/7x8

        =1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+.......-1/7+1/7-1/8

        =1/1-1/8

         =7/8

c)     mình chịu

thank you bn nhìu nha

chịu,khó quá,nhất là câu c ý

a. \(-\frac{15}{90}=-\frac{1}{6};\frac{120}{600}=\frac{1}{5};-\frac{75}{150}=-\frac{1}{2}\)

Mẫu chung: 30

\(-\frac{1}{6}=-\frac{5}{30};\frac{1}{5}=\frac{6}{30};-\frac{1}{2}=-\frac{15}{30}\)

b. \(\frac{54}{-90}=\frac{3}{-5}=-\frac{3}{5};-\frac{180}{288}=-\frac{5}{8};\frac{60}{-135}=\frac{4}{-9}=-\frac{4}{9}\)

Mẫu chung: 360

\(-\frac{3}{5}=-\frac{216}{360};-\frac{5}{8}=-\frac{225}{360};-\frac{4}{9}=-\frac{160}{360}\).

ko biet gi ca

anh ko biet

KQ= -73/420

Cách lm dài wa mik lười... mik nka

=\(\frac{3}{5}\)nha bạn nhớ k nha