\(4,7\div0,25+5,3\times4\)

\(=18,8+21,2\)

\(=40\)

\(3\times\left(a-2\right)+150=240\)

\(3\times\left(a-2\right)=90\)

\(a-2=30\)

\(a=32\)

\(\dfrac{1}{9}+a+\dfrac{7}{12}=\dfrac{17}{18}\)

\(\dfrac{1}{9}+a=\dfrac{13}{36}\)

\(a=\dfrac{1}{4}\)

\(\left(\dfrac{1}{2}\times\dfrac{1}{3}+\dfrac{1}{3}\times\dfrac{1}{4}+\dfrac{1}{4}\times\dfrac{1}{5}+\dfrac{1}{5}\times\dfrac{1}{6}+\dfrac{1}{6}\times\dfrac{1}{7}+\dfrac{1}{7}\times\dfrac{1}{8}\right)\times a=\dfrac{9}{16}\)

\(\left(\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+\dfrac{1}{4\times5}+\dfrac{1}{5\times6}+\dfrac{1}{6\times7}+\dfrac{1}{7\times8}\right)\times a=\dfrac{9}{16}\)

\(\left(\dfrac{1}{2}-\dfrac{1}{8}\right)\times a=\dfrac{9}{16}\)

\(\dfrac{3}{8}\times a=\dfrac{9}{16}\)

\(a=\dfrac{3}{2}\)

Lời giải:
$\frac{x}{3}=\frac{2}{3}+\frac{-1}{7}=\frac{14}{21}+\frac{-3}{21}=\frac{11}{21}$

$x=3.\frac{11}{21}=\frac{11}{7}$

ỜM HAI PẠN ƠI CHO MIK HỎI CÁI NÀY ĐƯỢC KHUM

tùy thui bẹn hỏi ik

toán 5 mà khó thế bn

\(A=\dfrac{1}{2}\times\left(\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+...+\dfrac{1}{2011}-\dfrac{1}{2013}\right)=\dfrac{1}{2}\times\left(\dfrac{1}{5}-\dfrac{1}{2013}\right)=\dfrac{1004}{10065}\)

\(\left(123\text{ ×}0,25+123\text{ ×}0,75\right)\text{ ×}\left(11\text{ ×}9-900\text{ ×}0,1-9\right)\)

\(=\left(123\text{×}0,25+123\text{×}0,75\right)\text{ ×}\left(11\text{×}9-9\text{×}100\text{×}0,1-9\text{×}1\right)\)

\(=\left(123\text{×}0,25+123\text{×}0,75\right)\text{ ×}\left(11\text{×}9-9\text{×}10-9\text{×}1\right)\)

\(=\left[123\left(0,25+0,75\right)\right]\text{×}\left[9\text{×}\left(11-10-1\right)\right]\)

\(=\left(123\text{×}1\right)\text{×}\left(9\text{×}0\right)=123\text{×}0=0\)

$\left(123\text{ ×}0,25+123\text{ ×}0,75\right)\text{ ×}\left(11\text{ ×}9-900\text{ ×}0,1-9\right)$

$=\left(123\text{×}0,25+123\text{×}0,75\right)\text{ ×}\left(11\text{×}9-9\text{×}100\text{×}0,1-9\text{×}1\right)$

$=\left(123\text{×}0,25+123\text{×}0,75\right)\text{ ×}\left(11\text{×}9-9\text{×}10-9\text{×}1\right)$

$=\left[123\left(0,25+0,75\right)\right]\text{×}\left[9\text{×}\left(11-10-1\right)\right]$

$=\left(123\text{×}1\right)\text{×}\left(9\text{×}0\right)$

$=123\text{×}0$

$=0$

$=\left(123\text{×}0,25+123\text{×}0,75\right)\text{ ×}\left(11\text{×}9-9\text{×}100\text{×}0,1-9\text{×}1\right)$

$=\left(123\text{×}0,25+123\text{×}0,75\right)\text{ ×}\left(11\text{×}9-9\text{×}10-9\text{×}1\right)$

$=\left[123\left(0,25+0,75\right)\right]\text{×}\left[9\text{×}\left(11-10-1\right)\right]$

$=\left(123\text{×}1\right)\text{×}\left(9\text{×}0\right)=123\text{×}0=0\; (nhớ\; tick\; cho\; mình\; nha:3)$

15 - 3/7 rồi bạn tự tính nha

\(15-\dfrac{x}{2}=\dfrac{3}{7}\)

\(\dfrac{x}{2}=15-\dfrac{3}{7}=\dfrac{15\cdot7-3}{7}=\dfrac{102}{7}\)

\(x=\dfrac{102}{7}\cdot2=\dfrac{204}{7}\)

\(15-\dfrac{x}{2}=\dfrac{3}{7}\)

\(\dfrac{x}{2}=15-\dfrac{3}{7}\)

\(\dfrac{x}{2}=\dfrac{102}{7}\)

\(x\times7=102\times2\)

\(x\times7=204\)

\(x=204\div7\)

\(x=\dfrac{204}{7}\)

\(\dfrac{-7}{x+1}=\dfrac{6}{x+27}\)

\(\Rightarrow-7x-189=6x+6\)

\(\Rightarrow-7x-6x=6+189\)

\(\Rightarrow-13x=195\)

\(\Rightarrow x=-15\)

Vay x = -15

\(\dfrac{-7}{x+1}=\dfrac{6}{x+27}\)

\(\Rightarrow-7\left(x+27\right)=6\left(x+1\right)\)

\(\Rightarrow-7x-189=6x+6\)

\(\Rightarrow-7x-6x=6+189\)

\(\Rightarrow-13x=195\)

\(\Rightarrow x=-15\)

Vậy x=-15

a) 234 + 876 x 345          b) ( 987 - 234 ) x 869         

 = 234 + 302220               = 753 x 869

= 302454                          = 654357

c) 585 : 5 + 679 x 876

= 117 + 594804

= 594921

a, 234 + 876 x 345

=  234 + 302220

= 302454

b,( 987 – 234) x 869

=    753           x 869

=     654357

c , 585 : 5 + 679 x 876

=  117       + 594804

=  594921

`a)234+876xx345`

`=234+30220`

`=302454`

___________________

`b)(987-234)xx869` 
`=753xx869`

`=654357`

___________________

`c)585:5+679xx867`

`=117+588693`

`=588810`

`@An`

Lời giải:

Gọi $d=ƯCLN(3n+2, 2n+3)$

$\Rightarrow 3n+2\vdots d; 2n+3\vdots d$

$\Rightarrow 3(2n+3)-2(3n+2)\vdots d$

$\Rightarrow 5\vdots d$

$\Rightarrow d=1$ hoặc $d=5$.

Để ps đã cho là tối giản thì $d\neq 5$. Nghĩa là $2n+3\not\vdots 5$

$\Rightarrow 2n-2\not\vdots 5$

$\Rightarrow 2(n-1)\not\vdots 5$

$\Rightarrow n-1\not\vdots 5$

$\Rightarrow n\neq 5k+1$ với $k$ tự nhiên.

11: 0,25

= 44

44

= 44