\(\frac{16}{45}\)

\(\frac{16}{45}\)

\(\Rightarrow x=\frac{16}{45}\)

\(\left[0,\left(37\right)+0,\left(7\right)\right]x=0,1\left(6\right)\)

\(\Rightarrow\left[\frac{37}{99}+\frac{7}{9}\right]x=0,1+0,0\left(6\right)\)

\(\Rightarrow\frac{38}{33}.x=\frac{1}{10}+\frac{6}{90}\)

\(\Rightarrow\frac{38}{33}.x=\frac{1}{6}\)

\(\Rightarrow x=\frac{1}{6}:\frac{38}{33}=\frac{1}{6}.\frac{33}{38}\)

\(\Rightarrow x=\frac{11}{76}\)

Vậy \(x=\frac{11}{76}\)

\(\frac{16}{45}\)

0,(12) =4/33

1,(6) = 5/3

11.0,(4) =11.4/9 =44/9

\(\frac{\frac{4}{33}}{\frac{5}{3}}=\frac{x}{\frac{44}{9}}\Leftrightarrow x=\frac{4.3}{33.5}.\frac{44}{9}=\frac{16}{45}\)

\(\frac{x+1}{x-1}=\frac{7}{3}\)

=> \(3.\left(x+1\right)=7.\left(x-1\right)\)

=> \(3x+3=7x-7\)

=> \(3x+10=7x\)

=> \(4x=10\)

=> \(x=\frac{10}{4}=\frac{5}{2}\)

Vậy \(x=\frac{5}{2}\)

\(\frac{x+1}{x-1}=\frac{7}{3}\)

\(\Rightarrow3\left(x+1\right)=7\left(x-1\right)\)

\(\Leftrightarrow3x+3=7x-7\)

\(\Leftrightarrow-4x=-10\)

\(\Leftrightarrow x=\frac{5}{2}\)

~~~!!!

\(\frac{x+1}{x-1}=\frac{7}{3}\)

\(\Leftrightarrow3x+3=7x-7\)

\(\Leftrightarrow3x=7x-7-3\)

\(\Leftrightarrow-4x=-10\)

\(\Rightarrow x=\frac{5}{2}\)

Vì \(\hept{\begin{cases}\left(2x+1\right)^2\ge0\\\left|y-1,2\right|\ge0\end{cases}}\)nên  \(\left(2x+1\right)^2+\left|y-1,2\right|=0\)khi và chỉ khi:

\(\hept{\begin{cases}\left(2x+1\right)^2=0\\\left|y-1,2\right|=0\end{cases}\Leftrightarrow}\hept{\begin{cases}2x+1=0\\y-1,2=0\end{cases}\Leftrightarrow}\hept{\begin{cases}x=-\frac{1}{2}\\y=1,2\end{cases}}\)

=>Giá trị của x+y là: \(-\frac{1}{2}+1,2=0,7\)

Vậy x+y=0,7

thank you