so sanh
a)-22/45 va -51/101
b)so sanh A=\(\frac{^{2009^{2009}}+1}{^{2009^{20010}}+1}\)va B=\(\frac{2009^{2010}-2}{2009^{2011}-2}\)
Bai 1.Tim x, y biet :
2x(3y-2)+(3y-2) = -55
Bai 2 .a) So sanh : -22/45 va -51/103
b) So sanh A = 2009^2009 +1 / 2009^2010 va B = 2009^2010-2/2009^2011-2
Bai 3 :
a)Tim so tu nhien co 3 chu so , biet rang khi chia so do cho cac so 25, 28,35thi duoc cac so du lan luot la 5,8,15
b)Tim x: (x+1)+(x+2)+(x+3)+...+(x+100)=205550
So sanh : U = \(\frac{2009^{2005}+1}{2009^{2010}+1}\)va V = \(\frac{2009^{2010}+2}{2009^{2011}+2}\)
So sanh :2009^2009+1/2009^2010+1 va 2009^2010-2/2009^2011-2
so sánh \(\frac{-22}{45}\)và\(\frac{-51}{103}\)
so sánh \(\frac{2009^{2009}+1}{2009^{2010}+1}\)và\(\frac{2009^{2010}-2}{2009^{2011}-2}\)
2. So sánhA=\(\frac{2009^{2009}+1}{2009^{2010}+1}\) VÀ B=\(\frac{2009^{2010}-2}{2009^{2011}-2}\)
so sanh: A=2009^2009+1/2009^2010+1 và B=2009^2010-2/2009^2011-2
So sanh 2 phan so
2009×2009+2008/2009×2009+2009 va 2009×2009+2009/2009×2009+2010
So sánh hai phân số :
\(\frac{2009.2009+2008}{2009.2009+2009}\)và \(\frac{2009.2009+2009}{2009.2009+2010}\)
So sánh:
A=\(\frac{2009^{2009}+1}{2009^{2010}+1}\)và B=\(\frac{2009^{2010}-2}{2009^{2011}-2}\)
\(B=\frac{2009^{2010}-2}{2009^{2011}-2}< 1\)
\(\Rightarrow B=\frac{2009^{2010}-2}{2009^{2011}-2}< \frac{2009^{2010}-2+2011}{2009^{2011}-2+2011}=\frac{2009^{2010}+2009}{2009^{2011}+2009}\)\(=\frac{2009.\left(2009^{2009}+1\right)}{2009.\left(2009^{2010}+1\right)}=\frac{2009^{2009}+1}{2009^{2010}+1}\)
Suy ra : \(\frac{2009^{2010}-2}{2009^{2011}-2}< \frac{2009^{2009}+1}{2009^{2010}+1}\) hay \(B< A\)
Vậy \(A>B\)
so sánh A=\(\frac{2009^{2009}+1}{2009^{2010}+1}\)B=\(\frac{2009^{2010}-2}{2009^{2011}-2}\)
Do 2009\(^{2010}\)-2 < 2009\(^{2011}\)-2 \(\Rightarrow\)B<1
Theo đề bài ta có:
B= \(\frac{2009^{2010}-2}{2009^{2011}-2}\)< \(\frac{2009^{2010}-2+2011}{2009^{2011}-2+2011}\)= \(\frac{2009^{2010}+2009}{2009^{2011}+2009}\)= \(\frac{2009.\left(1+2009^{2009}\right)}{2009.\left(1+2009^{2010}\right)}\)= \(\frac{2009^{2009}+1}{2009^{2010}+1}\)= A \(\Rightarrow\)B<A