126 : 3 + 231 : 3 + 543 : 3

= ( 126 + 231 + 543 ) : 3

= 900 : 3

= 300

126 : 3 + 231 : 3 + 543 : 3

= \(126.\frac{1}{3}+231.\frac{1}{3}+543.\frac{1}{3}\)

=\(\frac{1}{3}\left(126+231+543\right)=\frac{1}{3}.900=300\)

126 : 3 + 231 : 3 + 543 : 3

= ( 126 + 231 + 543 ) : 3

= 900 : 3 = 300

P/s : Hình thức câu mới à Bonking ( -_- )

Câu này nghĩa là gì vậy bạn

Có phải là lấy 49 nhân cho 100 rồi chia 37 hay là biểu thức  \(\frac{54\times50+49\times100}{37\times38+126\times19}\)vậy 

TL

= (3⁹ (3 -1)) : 2⁹ : 3¹⁰ = 2 : 2⁹ x 1/3 = 1/2⁸ x 1/3

Khi nào rảnh vào kênh H-EDITOR xem vid nha!!! Thanks!

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=> 201,ab : 126 = 1ab 126 x 1ab = 20 100  + ab 126 x ab = 7500 + ab

125 x ab = 7500 ab 

= 7500  : 125 ab = 60

Vậy a = 6 ; b = 0.

a=6 ;b=0

a=6     b=0

tìm minx max của biểu thức ạ

X x 3        "chỗ này bị thiếu dấu"          Y: 0,5 = 14,7 

3I = 3¹ + 3² + 3³ + 3⁴ + ... + 3¹⁰¹

3I - I = (3¹ + 3² + 3³ + 3⁴ + ... + 3¹⁰¹) - (3⁰ + 3¹ + 3² + 3³ + ... + 3¹⁰⁰)

2I = 3¹⁰¹ - 3⁰

2I = 3¹⁰¹ - 1

\(I=\frac{3^{101}-1}{2}\)

Gọi số thứ nhất, hai , ba theo thứ tự đề bài là a, b và c. 

Theo đề bài, ta có (a+b+c):3 = 126 ; a - b = 15 suy ra a = b+15 ; b - c =9 suy ra c = b - 9

Do đó \(\frac{a+b+c}{3}=126\Rightarrow b+15+b+b-9=378\Rightarrow3b=372\Rightarrow b=124\Rightarrow c=124-9=115\)

Vậy số thứ ba là 115

BẠN ƠI ĐỀ BÀI YÊU CẦU TÌM BA SỐ ĐÓ CƠ MÀ !

À cho mình xin lỗi, mình đọc nhầm thành tìm số thứ 3, vậy bạn có thể suy ra số thứ nhất dễ dàng mà