(10^2+11^2+12^2) : (13^2+14^2)
Những câu hỏi liên quan
tìm x sao cho x+2/10^10+x+2/11^11+x+2/12^12=x+2/13^13+x+2/14^14
1/2+2/3+3/4+4/5+5/6+6/7+7/8+8/9+9/10+10/11+11/12+12/13+13/14+14/15=?
\(\dfrac{10^2+11^2+12^2}{13^2+14^2}\)
Lời giải:
\(\frac{10^2+11^2+12^2}{13^2+14^2}=\frac{365}{365}=1\)
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(-2/11+ 3/12 +-4/13 +5/14) : (-4/11 + 6/12+ -8/13 +10/14)
(-2/11+ 3/12 +-4/13 +5/14) : (-4/11 + 6/12+ -8/13 +10/14)0000000000000000000000000000000000000= 0
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(10^2+11^2+12^2):(13^2+14^2)
10^2+11^2+12^2/13^2+14^2
(10^2+11^2+12^2):(13^2+14^2)
10^2+11^2+12^2/13^2+14^2
\(\frac{10^2+11^2+12^2}{13^2+14^2}=\frac{100+121+144}{169+196}=\frac{365}{365}=1\)
~Học tốt~
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(10^2 + 11^2 + 12^2) - (13^2 + 14^2) = ?