\(\frac{-216}{-217}=\frac{216}{217}>\frac{-15}{16}\)

\(\frac{-216}{-217}=\frac{216}{217}>0\left(1\right)\)

\(\frac{-15}{16}< 0\left(2\right)\)

\(\text{Từ (1) và (2) }\Rightarrow\frac{-216}{-217}>\frac{-15}{16}\)

Ta có: 9/16=27/48

         : -13/-24=13/24=26/48

 Mà:27>26=>27/48>26/48

Nên 9/16>-13/-24

NO Never

Em tham khảo nhé !!

\(3^{200}=\left(3^2\right)^{100}=9^{100}\)

\(2^{300}=\left(2^3\right)^{100}=8^{100}\)

Vì \(8< 9\Rightarrow8^{100}< 9^{100}\Rightarrow2^{300}< 3^{200}\)

Ta có : 3²⁰⁰ = (3²)¹⁰⁰ = 9¹⁰⁰

2³⁰⁰ = ( 2³ )¹⁰⁰ = 8¹⁰⁰

Vì 8<9 => 3²⁰⁰ .>2³⁰⁰

\(3^{200}=3^{2.100}=\left(3^2\right)^{100}\)

\(2^{300}=2^{3.100}=\left(2^3\right)^{100}\)

vi \(2^3=8< 3^2=9\) => \(2^{300}< 3^{200}\)

Chuc ban hoc tot

ta có

\(\frac{12}{35}\)> \(\frac{12}{36}\)=> \(\frac{12}{35}\)> \(\frac{1}{3}\)

\(\frac{20}{61}\)< \(\frac{20}{60}\)=> \(\frac{20}{61}\) < \(\frac{1}{3}\)

\(\frac{20}{61}\),< \(\frac{1}{3}\) < \(\frac{12}{35}\)

vậy \(\frac{20}{61}\) < \(\frac{12}{35}\)

nhớ k nha

Ta có\(71^{50}=71^{2.25}=\left(71^2\right)^{25}=5041^{25}\) 

\(37^{75}=37^{3.25}=\left(37^3\right)^{25}=50653^{25}\)

Mà 50653²⁵ > 5041²⁵

suy ra \(37^{75}>71^{50}\)

Ta có : 71⁵⁰ = 71^{2 . 25} = (71²) ²⁵ = 5041²⁵

          37⁷⁵ = 37 ^{3 . 25} = (37³ ) ²⁵ = 50653²⁵

Vì 5041²⁵ < 50653²⁵

nên  71⁵⁰ < 37⁷⁵

           Vậy 71⁵⁰ < 37⁷⁵

#HOK TỐT#

\(37^{75}>32^{75}=\left(2^5\right)^{75}=2^{375}>2^{350}=128^{50}>71^{50}\)

Ta có: \(A=2019.2021=\left(2020-1\right)\left(2020+1\right)=2020^2-1\)

\(B=2020^2\)

=> A <  B

A=2019.2021

A=(2020-1)(2020+1)

A=2020²-1

Vậy: A<B

TA CÓ \(A=2019.2020\)

\(=\left(2020-1\right)\left(2020+1\right)\)

\(=2020^2-1\)

\(B=2020^2\)

\(\Leftrightarrow A\le B\)

HOK TỐT