ta co:

     \(\frac{11.12+22.24+44.48}{33.36+66.72+132.144}\)

   \(=\frac{11.12+11.2.12.2+11.4.12.4}{33.36+33.2.36.2+33.4.36.4}\)

   \(=\frac{11.12.\left(1+2.2+4.4\right)}{33.36.\left(1+2.2+4.4\right)}\)

   \(=\frac{11.12}{36.33}\)

   \(=\frac{1}{3.3}\)

\(=\frac{1}{9}\)

a) 5

b) -10/7

c) 1/9

11 . 12 + 33 . 36 + 55 . 60

= 11 . 12 + 11 . 3 . 12 . 3 + 11 . 5 . 12 . 5

= (11 + 12) . 1 . (11 + 12) . 3 . (11 + 12) . 5

= 23 . 1 . 23 . 3 . 23 . 5

= 23 . (1 + 3 + 5)

= 23 . 9

= 207

\(11\cdot12+33\cdot36+55\cdot60\) 

\(=11\cdot12+3\cdot11\cdot3\cdot12+5\cdot11\cdot5\cdot12\) 

\(=11\cdot12\left(1+9+25\right)\) 

\(=132\cdot35\) 

\(=4620\)

\(\frac{11.12+33.36+55.60}{22.24+66.72+110.120}=\frac{11.12+33.36+55.60}{2.11.2.12+2.33.2.36+2.55.2.60}=\frac{11.12+33.36+55.60}{4.11.12+4.33.36+4.55.60}=\frac{11.12+33.36+55.60}{4.\left(11.12+33.36+55.60\right)}=\frac{1}{4.1}=\frac{1}{4}\)

\(\frac{10.11+55.60+70.77}{11.12+55.60+77.84}=\frac{10.11+5.11.6.10+7.10.7.11}{11.12+5.11.5.12+7.11.7.12}=\frac{10.11+30.10.11+49.10.11}{11.12+25.11.12+49.11.12}=\frac{10.11\left(1+30+49\right)}{11.12\left(1+25+49\right)}=\frac{5.80}{6.75}=\frac{8}{9}\)