`Answer:`

\(A=\frac{-5x}{21}+\frac{-5y}{21}+\frac{-5z}{21}\)

\(=\frac{-5x-5y-5z}{21}\)

\(=\frac{-5\left(x+y\right)-5z}{21}\)

\(=\frac{-5\left(-z\right)-5z}{21}\)

\(=\frac{5z-5z}{21}\)

\(=\frac{0}{21}\)

\(=0\)

Cảm ơn bạn nha

bài 1:rất dễ,nhân chéo sẽ giải đc

bài 2: x+y=-x

=>x+y+z=0

Ta có: \(A=\frac{-5x}{21}+\frac{-5y}{21}+\frac{-5z}{21}=\frac{\left(-5x\right)+\left(-5y\right)+\left(-5z\right)}{21}=\frac{-5.\left(x+y+z\right)}{21}=\frac{0}{21}=0\)

bài 1:

\(\frac{1}{2a^2+1}:x=2\)

\(\Leftrightarrow\frac{1}{2a^2+1}.\frac{1}{x}=2\)

\(\Leftrightarrow\frac{1}{\left(2a^2+1\right).x}=2\)

\(\Leftrightarrow x=\frac{1}{\frac{\left(2a^2+1\right)}{2}}=\frac{1}{2a^2+1}.\frac{1}{2}=\frac{1}{\left(2a^2+1\right).2}=\frac{1}{4a^2+2}\)

A = \(\frac{-5x}{21}\)+  \(\frac{-5y}{21}\)+ \(\frac{-5x}{21}\)

    = \(\frac{\left(-5x\right)+\left(-5y\right)+\left(-5x\right)}{21}\)

    vì x + y là số dõi của z 

=> x + y + z = 0 

=> \(\frac{5.\left(x+y+z\right)}{21}\)

= \(\frac{-5}{21}\).  0 = 0 

=> A = 0 

hok tốt !

Thay -z=x+y vào biểu thức A ta có A=-5x/21+(-5y/21)+[5(x+y)/21] =>-5x/21 +(-5y/21)+(5x+5y)/21=>-5x/21+(-5y/21)+5x/21+5y/21 => A = 0

Theo đầu bài ta có:
\(A=\frac{-5x}{21}+\frac{-5y}{21}+\frac{-5z}{21}\)
\(=\frac{-5x+-5y+-5z}{21}\)
\(=\frac{-5\left(x+y+z\right)}{21}\)
\(=\frac{-5\left(-z+z\right)}{21}\)
\(=\frac{-5\cdot0}{21}\)
\(=\frac{0}{21}=0\)

\(A=\frac{-5x}{21}+\frac{-5y}{21}+\frac{-5z}{21}\)

=>\(A=\frac{\left(-5x\right)+\left(-5y\right)+\left(-5z\right)}{21}\)

=>\(A=\frac{\left(-5\right)\left(x+y+z\right)}{21}\)

=>\(A=\frac{\left(-5\right)\left(-z+z\right)}{21}\)

=>\(A=\frac{\left(-5\right).0}{21}\)

=>\(A=\frac{0}{21}\)

=>A=0

A=\(\frac{-5x}{21}+\frac{-5y}{21}+\frac{-5z}{21}\)=\(\frac{\left(-5x\right)+\left(-5y\right)+\left(-5z\right)}{21}=\frac{-5.\left(x+y+z\right)}{21}\)vì x+y=z \(\Rightarrow\)x+y là số đối của z

\(\Rightarrow\)x+y+z=0

\(\Rightarrow\frac{-5}{21}.x+y+z=\frac{-5}{21}.0=0\)

\(\Rightarrow\)A=0

Ngu từng mà ko biết

minh nghi la khong tinh ra mot phan so duoc dau:

A= -5x/21 + -5y/21 + -5z/21

=> A= -5x/21 + -5y/21 + -5(x+y)/21

A= -5x/21 + -5y/21 + -5x-5y/21

A= -10x/21 + -10y/21

A= -10(x+y)/21

A= -10z/21

1.

A=\(\frac{-5x+-5y+-5z}{21}=\frac{-5\left(x+y+z\right)}{21}=\frac{-5}{21}.x+y+z\)

A= -z+z=0

<p style="padding: 10000000000000000px;" class="alert success"></p>

ai tích mình mình tích lại cho

=  \(\frac{-10z}{21} + \frac{-5z}{21} \)  = \(\frac{-15z}{21} \)

Ta có : 

A = \(\frac{-5.x}{21}+\frac{-5.y}{21}+\frac{-5.z}{21}\)

   = \(\frac{-5}{21}.\left(x+y+z\right)\)

   = \(\frac{-5}{21}.\left(-z+z\right)\)

   = \(\frac{-5}{21}.0\)

    = 0

Vậy A = 0

A=-5(x+y+z)/21

A=-5(-z+z)/21

A=-5x0/21

A=0