tính tổng sau: A=1/2+1/2^2+1/2^3 +...+1/2^2015+1/2^2016
Tính tổng sau
A = 1/2 + 1/2^2 + 1/2^3 +.....+ 1/2^2015 + 1/2^2016
Tính tổng sau:
A=1/2+1/22+1/23+.......+1/22015+1/22016
\(A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{2015}}+\frac{1}{2^{2016}}\)
\(\Rightarrow\)\(2A=1+\frac{1}{2}+\frac{1}{2^2}+....+\frac{1}{2^{2014}}+\frac{1}{2^{2015}}\)
\(\Rightarrow\)\(2A-A=\left(1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{2014}}+\frac{1}{2^{2015}}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{2016}}\right)\)
\(\Rightarrow\)\(A=1-\frac{1}{2^{2016}}\)
Tính tổng sau:
A=\(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+..............+\frac{1}{2^{2015}}+\frac{1}{2^{2016}}\)
\(A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{2015}}+\frac{1}{2^{2016}}\)
\(\Leftrightarrow\)\(2A=1+\frac{1}{2}+\frac{1}{2^2}+....+\frac{1}{2^{2014}}+\frac{1}{2^{2015}}\)
\(\Leftrightarrow\)\(2A-A=\left(1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{2015}}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{2016}}\right)\)
\(\Leftrightarrow\)\(A=1-\frac{1}{2^{2016}}\)
\(A=\frac{1}{2}+\frac{1}{2^2}+......+\frac{1}{2^{2016}}\)
\(2A=1+\frac{1}{2}+.........+\frac{1}{2^{2015}}\)
\(2A-A=\left(1+\frac{1}{2}+.....+\frac{1}{2^{2015}}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+.....+\frac{1}{2^{2016}}\right)\)
\(A=1-\frac{1}{2^{2016}}\)
2A= 1+ 1/2 + 1/2^2+....+1/2^2015
2A -A= (1+1/2+1/2^2+...+1/2^2015)-(1/2+1/2^2+...+1/2^2016)
A= 1-\(\frac{1}{2^{2016}}\)
Đáp số: A=1-\(\frac{1}{2^{2016}}\)
Tính tổng sau:
\(A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{2015}}+\frac{1}{2^{2016}}\)
A=1/2+1/2^2+1/2^3+...+1/2^2016 (1)
2A=1+1/2+1/2^2+...+1/2^2015 (2)
Lấy (2)-(1) được:
A=1+1/2+1/2^2+...+1/2^2015-(1/2+1/2^2+1/2^3+...+1/2^2016)
A=1+1/2+1/2^2+...+1/2^2015-1/2-1/2^2-1/2^3-...-1/2^2016
A=1-1/2^2016
Vậy A=1-1/2^2016
Tính tổng S= 2015 + 2015/1+2 + 2015/1+2+3 + ... + 2015/1+2+3+...+2016
viết lại đề cho rõ phân số đi bn
Tính tổng S=2015+2015/1+2+2015/1+2+3+..........+2015/1+2+3+........+2016
Tính các tổng sau:
a) A=1+(-2) + 3 +(-4) + ...+(- 2014) + 2015;
b) B= (-2) + 4 +(-6) + 8 ... +(-2014) + 2016;
c) 1+(-3) + 5 +(-7) + ... + 2013 +(-2015);
d) (-2015) + (-2014) + (-2013)+ ... + 2015 + 2016
\(A=\left[1+\left(-2\right)\right]+\left[3+\left(-4\right)\right]+....+\left[2013+\left(-2014\right)+2015\right]\)
\(A=\left(-1\right)+\left(-1\right)+....+\left(-1\right)+2015\left(\text{1007 số hạng }\left(-1\right)\right)=1008\)
\(B=\left(-2\right)+4+\left(-6\right)+8+\left(-10\right)+,...+\left(-2014\right)+2016\)
\(B=2+2+....+2\left(\text{504 số hạng 2}\right)=1008\)
c) 1 + ( -3 ) +5 + ( -7 ) + ...........+ 2013 + ( -2015 )
[ 1 + (-3 ) ] + [ 5 + -7 ] + .......... + [ 2013 + ( - 2015 ) ]
có số cặp là : [ ( 2015 - 1 ) : 2 + 1 ] : 2 = 504 ( cặp )
= -2 + -2 + -2 +..........+ -2
= -2 x 504
= -1008
Tinh tổng sau ;
A=1/2+1/2^2+1/3^3+.....+1/2^2015+1/2^2016
A=1/2+1/2^2+1/2^3+...+1/2^2015+1/2^2016
tính tổng trên:
Có : 2A = 1 + 1/2 + 1/2^2 +.....+ 1/2^2015
A = 2A - A = (1+1/2+1/2^2+.....+1/2^2015)-(1/2+1/2^2+.....+1/2^2016)
= 1 - 1/2^2016
Tk mk nha
\(A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{2015}}+\frac{1}{2^{2016}}\)
\(2A=1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{2014}}+\frac{1}{2^{2015}}\)
\(2A-A=\left(1+\frac{1}{2}+\frac{1}{2^2}+....+\frac{1}{2^{2014}}+\frac{1}{2^{2015}}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+....+\frac{1}{2^{2015}}+\frac{1}{2^{2016}}\right)\)
\(A=1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{2015}}+\frac{1}{2^{2016}}-\frac{1}{2}-\frac{1}{2^2}-...-\frac{1}{2^{2015}}-\frac{1}{2^{2016}}\)
\(A=1-\frac{1}{2^{2016}}\)