1\(\frac{1}{2}\)x1\(\frac{1}{3}\)x1\(\frac{1}{4}\)x.....x\(\frac{1}{1963}\)
a)\(\left(1-\frac{1}{2}\right)x\left(1-\frac{1}{3}\right)x\left(1-\frac{1}{4}\right)x\left(1-\frac{1}{5}\right)x......x\left(1-\frac{1}{18}\right)x\left(1-\frac{1}{19}\right)x\left(1-\frac{1}{20}\right)\)
b)\(1\frac{1}{2}x1\frac{1}{3}x1\frac{1}{4}x1\frac{1}{5}x......x1\frac{1}{2005}x1\frac{1}{2006}x1\frac{1}{2007}\)
\(x\)là dấu nhân hả bạn? Nếu vậy thì mk làm cho nhé
\(A=\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot....\cdot\left(1-\frac{1}{20}\right)\)
\(A=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot.......\cdot\frac{17}{18}\cdot\frac{18}{19}\cdot\frac{19}{20}=\frac{1}{20}\)
Vậy \(A=\frac{1}{20}\)
\(B=1\frac{1}{2}\cdot1\frac{1}{3}\cdot1\frac{1}{4}\cdot........\cdot1\frac{1}{2005}\cdot1\frac{1}{2006}\cdot1\frac{1}{2007}\)
\(B=\frac{3}{2}\cdot\frac{4}{3}\cdot\frac{5}{4}\cdot......\cdot\frac{2006}{2005}\cdot\frac{2007}{2006}\cdot\frac{2008}{2007}=\frac{2008}{2}=1004\)
Vậy \(B=1004\)
DẤU CHẤM LÀ DẤU NHÂN
a,
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}....\frac{19}{20}=\frac{1}{20}\)
b, \(1\frac{1}{2}.1\frac{1}{3}....1\frac{1}{2017}=\frac{3}{2}.\frac{4}{3}....\frac{2018}{2017}=\frac{2018}{2}=1009\)
1\(\frac{1}{2}\)x1\(\frac{1}{3}\)x1\(\frac{1}{4}\)x1\(\frac{1}{5}\)x1\(\frac{1}{6}\)x1\(\frac{1}{7}\)x1\(\frac{1}{7}\)x1\(\frac{1}{8}\)x 1\(\frac{1}{9}\)x 1\(\frac{1}{10}\)tính bằng cách thuận tiện nhất
let P(x) be a polynomial of degree 3 and x1, x2, x3 are the solutions of P(x)=0. let \(\frac{P\left(\frac{1}{3}\right)-P\left(\frac{-1}{3}\right)}{P\left(0\right)}=8,\frac{P\left(\frac{1}{4}\right)-P\left(\frac{-1}{4}\right)}{P\left(0\right)}=9\)and x1+x2+x3 = 35. find the value of \(\frac{x2+x3}{x1}+\frac{x1+x3}{x2}+\frac{x1+x2}{x3}\)
\(1\frac{1}{3}x1\frac{1}{8}x1\frac{1}{15}x..........x1\frac{1}{9800}\)
#)Giải :
\(1\frac{1}{3}\times1\frac{1}{8}\times1\frac{1}{15}\times...\times1\frac{1}{9800}\)
\(=\frac{4}{3}\times\frac{9}{8}\times\frac{16}{15}\times...\times\frac{9801}{9800}\)
\(=\frac{2.2}{1.3}\times\frac{3.3}{2.4}\times\frac{4.4}{3.5}\times...\times\frac{99.99}{98.100}\)
\(=\frac{2.3.4.....99}{1.2.3.....98}\times\frac{2.3.4.....99}{3.4.5.....100}\)
\(=99\times\frac{2}{100}=\frac{198}{100}=\frac{99}{50}\)
\(=\frac{4}{3}\times\frac{9}{8}\times\frac{16}{15}\times...\times\frac{9801}{9800}\)
\(=\frac{2.2}{1.3}\times\frac{3.3}{2.4}\times\frac{4.4}{3.5}\times...\times\frac{99.99}{98.100}\)
\(=\frac{2.3.4.5.....99}{1.2.3.4....98}\times\frac{2.3.4.5.....99}{3.4.5.6.....100}\)
\(=\frac{99}{1}\times\frac{2}{100}\)
\(=\frac{99}{50}\)
\(1\frac{1}{3}\times1\frac{1}{8}\times1\frac{1}{15}\times........\times1\frac{1}{9800}\)
\(=\frac{4}{3}\times\frac{9}{8}\times\frac{16}{15}\times.......\times\frac{9801}{9800}\)
\(=\frac{2\times2}{1\times3}\times\frac{3\times3}{2\times4}\times\frac{4\times4}{3\times5}\times......\times\frac{99\times99}{98\times100}\)
\(=2\times\left(\frac{2}{3}\times\frac{3}{2}\times\frac{3}{4}\times\frac{4}{3}\times.....\times\frac{99}{98}\times\frac{99}{100}\right)\)
\(=2\times\frac{99}{100}\)
\(=\frac{198}{100}=\frac{99}{50}\)
Rút gọn biểu thức A = 1\(\frac{1}{2}\)x 1\(\frac{1}{3}\)x1\(\frac{1}{4}\)x....x1\(\frac{1}{2015}\)ta được A = ...
\(1\frac{1}{2}.1\frac{1}{3}.1\frac{1}{4}.....1\frac{1}{2015}\)
\(=\frac{3}{2}.\frac{4}{3}.\frac{5}{4}........\frac{2016}{2015}\)
\(=\frac{3.4.5.....2016}{2.3.4....2015}=\frac{2016}{2}=1008\)
\(A=\frac{3}{2}.\frac{4}{3}.\frac{5}{4}...\frac{2016}{2015}\)
\(A=\frac{2016}{2}=1008\)
Xong nhé bạn!
tính nhanh:
\(1\frac{1}{10}x1\frac{1}{11}x1\frac{1}{12}x1\frac{1}{13}x1\frac{1}{14}x1\frac{1}{15}x1\frac{1}{16}\)
dấu x là phép nhân nhé! ai xong sẽ có tích.
= \(\frac{11}{10}\cdot\frac{12}{11}\cdot\frac{13}{12}\cdot\frac{14}{13}\cdot\frac{15}{14}\cdot\frac{16}{15}\cdot\frac{17}{16}\)
=11/10 x 12/11 x 13/12 x 14/13 x 15/14 x 16/15 x 17/16
= \(\frac{17}{10}\)
=\(\frac{11}{10}\)x \(\frac{12}{11}\)x .......... x \(\frac{16}{15}\)x\(\frac{17}{16}\)
= \(\frac{11^1x12^1x......x16^1x17}{10x11^1x...x15^1x16^1}\)( những số có số nhỏ ở trên là rút gọn với số khác VD:11 rút gọn cho 11 )
=\(\frac{1x1x......x1x17}{10x1x.......x1x1}\)
=\(\frac{17}{10}\)
= 1,7
Bài giải
\(1\frac{1}{10}\text{ x }1\frac{1}{11}\text{ x }1\frac{1}{12}\text{ x }1\frac{1}{13}\text{ x }1\frac{1}{14}\text{ x }1\frac{1}{15}\text{ x }1\frac{1}{16}\)
\(=\frac{11}{10}\text{ x }\frac{12}{11}\text{ x }\frac{13}{12}\text{ x }\frac{14}{13}\text{ x }\frac{15}{14}\text{ x }\frac{16}{15}\text{ x }\frac{17}{16}\)
\(=\frac{11\text{ x }12\text{ x }13\text{ x }14\text{ x }15\text{ x }16\text{ x }17}{10\text{ x }11\text{ x }12\text{ x }13\text{ x }14\text{ x }15\text{ x }16}\)
\(=\frac{17}{10}\)
\(1\frac{1}{13}x1\frac{1}{14}x1\frac{1}{15}x......x1\frac{1}{2013}x1\frac{1}{2014}\)bài tính nhanh
1 1/13x1 1/14x....x1 1/2013x1 1/2014
=14/13x15/14x....x2014/2013x2015/2014
=14x15x....x2014x2015/13x14x....x2013x2014
=2015/13
=155
\(1\frac{1}{13}.1\frac{1}{14}.1\frac{1}{15}.....1\frac{1}{2013}.1\frac{1}{2014}\)
\(=\frac{14}{13}.\frac{15}{14}.\frac{16}{15}......\frac{2014}{2013}.\frac{2015}{2014}\)
\(=\frac{14.15.16.....2014.2015}{13.14.15.....2013.2014}\)
\(=\frac{2015}{13}\)
\(=155\)
chúc bạn học tốt !!!
Tìm m để phương trình :(x^2-1)(x+3)(x+5)=m có 4 nghiệm phân biệt thỏa mãn \(\frac{1}{x1}+\frac{1}{x2}+\frac{1}{x3}+\frac{1}{x4}=-1\)
tính tích của 10 hỗn số đầu tiên trong dãy các hỗn số sau :
\(1\frac{1}{3}x1\frac{1}{8}x1\frac{1}{15}x1\frac{1}{24}x1\frac{1}{35}x........\)