\(A=\frac{11}{21.10^2+10^2}=\frac{11}{10^2.\left(21+1\right)}=\frac{11}{10^2.22}=\frac{11}{10^2.11.2}=\frac{1}{10^2.2}\)

\(B=\frac{3.5.7.11.13.37-10101}{1313130+20202}=\frac{\left(3.5.7.11.13.37\right).5-10101.1}{130.10101+10101.2}=\frac{10101.\left(5-1\right)}{10101.\left(130+2\right)}=\frac{4}{132}=\frac{1}{33}\)

Ta có:  \(B=\frac{3.5.7.11.13.17-10101}{1313130+20202}\)

\(\Rightarrow B=\frac{255255-10101}{1313130+20202}\)

\(\Rightarrow B=\frac{1001.255-10101}{10101.13.10+10101.2}\)

\(\Rightarrow B=\frac{1001.255-10101}{10101.\left(13.10+2\right)}\)

\(\Rightarrow B=\frac{1001.255-10101}{10101.132}\)

\(\Rightarrow B=\frac{10101.255-19201}{10101.132}\)

Hình ở tử là 27 phải ko

4218/5627

\(\frac{10101}{20202}\)=\(\frac{1}{2}\)

\(\frac{10101}{20202}=\frac{1}{2}\)

k mk

\(\frac{10101}{20202}=\frac{1}{2}\)

\(\frac{2}{3}\)

\(\frac{3.7.13.37.19-10101}{505050+70707}\)=\(\frac{10101.39-10101}{10101.50+10101.7}\)=\(\frac{10101.\left(39-1\right)}{10101.\left(50+7\right)}\)=\(\frac{38}{57}\)=\(\frac{2}{3}\)

\(\frac{3.7.13.37.39-10101}{505050+70707}\)

\(=\frac{\left(3.7.13.37\right).39-10101}{50.10101+7.10101}\)

\(=\frac{10101.39-10101.1}{\left(50+7\right).10101}\)

\(=\frac{\left(39-1\right).10101}{57.10101}\)

\(=\frac{38.10101}{57.10101}\)

\(=\frac{38}{57}=\frac{38:19}{57:19}=\frac{2}{3}\)

mk đang cần gấp hẫy giúp mk trả lời đi

kết quả là 65 trên 12 hoặc  65 phần 12

=5/1-5/2+5/3+5/4

=60-30+20+15/12

=65/12

\(10101.\left(\frac{5}{10101}-\frac{5}{20202}+\frac{5}{30303}+\frac{5}{40404}\right)\)

\(=10101.\frac{5}{10101}-10101.\frac{5}{20202}+10101.\frac{5}{30303}+10101.\frac{5}{40404}\)

\(=5-\frac{5}{2}+\frac{5}{3}+\frac{5}{4}\)

\(=\frac{60}{12}-\frac{30}{12}+\frac{20}{12}+\frac{15}{12}\)

\(=\frac{60-30+20+15}{12}\)

\(=\frac{65}{12}\)

giải giúp mình cách làm còn kết quả thì ra 65/42

banj điên à tự giải đi biết kết quả rồi mà