tim x biet
4./x-5/-54=-34
259-51./4x+3/=(-100).3+10
1.4.|x-5|-54=-34
2.|x-1|+(-5)=2
3.32-8.|2x-9|=24
4.259-51.|4x+3|=(-10)^2.3+10^1
1.4./x-5/-54=-34
4./x-5/=-34+54
4./x-5/=20
/x-5/=20:4
/x-5/=5
=>x-5=5 va x-5=-5
TH1:x-5=-5
=>x=0
TH2:x-5=5
=>x=10
2. /x-1/+(-5)=2
/x-1/=2-(-5)
/x-1/=7
=>x-1=7 va x-1=-7
TH1: x-1=7
=>x=8
TH2:x-1=-7
=>x=-6
vay x=-6 hoac x=8
3. 32-8./2x-9/=24
8./2x-9/=32-24=8
/2x-9/=8:8=1
=>2x-9=1 hoac 2x-9=-1
TH1: 2x-9=1
=>x=(1+9):2=5
TH2: 2X-9=-1
=>x=(-1+9):2=4
vay x=4 hoac x=5
tìm x\(\in\)Z biết
1.-10-|5-x|=-12
2.4.|x-5|-54=-34
3.|x-1|+(-5)=2
4.32-8.|2x-9|=24
5.259-51.|4x+3|=(-10)^2.3+10^1
1) (-10)-|5-x|=(-12)
|5-x|=(-10)-(-12)
|5-x|=2
\(\Rightarrow\left[{}\begin{matrix}5-x=2\\5-x=\left(-2\right)\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=7\end{matrix}\right.\)
Vậy:............
tim x: a.4/(x^2+2x+1)+3/(x^2+2x+3)=3/2
b.4x/(x^2+4x+5)+7x/(x^2-4x+5)=39/10
a) Đặt x^2+2x+2=t
\(\frac{4}{t-1}+\frac{3}{t+1}=\frac{3}{2}\Leftrightarrow\frac{4t+4+3t-3}{t^2-1}=\frac{7t+1}{t^2-1}=\frac{3}{2}\)
\(\Leftrightarrow14t+2=3t^2-3\Leftrightarrow3t^2-14t-5=3t\left(t-5\right)+t-5=0\)\(\Leftrightarrow\left(t-5\right)\left(3t+1\right)=0\Rightarrow\left[\begin{matrix}t=5\\t=-\frac{1}{3}\left(loai\right)\end{matrix}\right.\)
Với t=5 ta có (x+1)^2=4\(\Rightarrow\left[\begin{matrix}x+1=2\\x+1=-2\end{matrix}\right.\Rightarrow\left\{\begin{matrix}x=1\\x=-3\end{matrix}\right.\)
Tim X
(4x - 3) – ( x + 5) = 3(10 - x)
help me plss
(4x−3)−(x+5)=3(10−x)
⇒4x−3−x−5=30−3x
⇒3x−8=30−3x
⇒6x=38
3
Vậy 3
Lời giải:
$(4x-3)-(x+5)=3(10-x)$
$4x-3-x-5=30-3x$
$3x-8=30-3x$
$3x+3x=30+8$
$6x=38$
$x=\frac{38}{6}=\frac{19}{3}$
Tim x biet(4x-3)-(x+5)=(x+2)-2×(x-10)
mình không biết cách làm, nhưng mình biết x = 7,5
\(4x-3-x-5-=x+2-2x+2.10\)
\(3x-8=x+2-2x+20\)
\(3x=x+10-2x+20\)
\(3x=-x+30\)
\(4x=30\)
\(x=\frac{30}{4}=7,5\)
Cam on cac b mk cx ra ket qua la 7,5
Tim x
(2x+ 5/4)^3=-27
(3-4x /5)^2=100/49
Ta có
(2x+5/4)3=-27=-33
=> 2x+5/4=-3
=>2x=-3-5/4
=>x=-17/4:2=-17/2
KL
(3-4x/5)2=100/49=(10/7)2
=>3-4x/5=10/7
=>3-4x=50/7
=>4x=-29/7
=>x=-29/28
KL
tim X
a) X-1/8= 2va1/3 nhan 5 va 1/4
b) X:3/2 =1/4
c) 10 va 3/10- x= 4/5
d)x:4/17 = 51
lam nhanh nhanh giup minh
a) x - \(\frac{1}{8}\)= \(\frac{7}{3}\)x \(\frac{21}{4}\)
x - \(\frac{1}{8}\)= \(\frac{49}{4}\)
x = \(\frac{49}{4}\)+ \(\frac{1}{8}\)
x = 98
b) x : \(\frac{3}{2}\) = \(\frac{1}{4}\)
x = \(\frac{1}{4}\)x \(\frac{3}{2}\)
x = \(\frac{3}{8}\)
c) \(\frac{103}{10}\) - x = \(\frac{4}{5}\)
x = \(\frac{103}{10}\)- \(\frac{4}{5}\)
x = \(\frac{19}{5}\)
d) x = 51 x \(\frac{4}{17}\)
x = \(12\)
Vậy chị kết luận ngắn gọn là:
a)=98
b)=3/8
c)=19/5
d)=12
tim x biet : (2x-1)+(4x-1)+...+(400x-200)=5+10+...+100
cho mình sửa đề 1 chút:
Tìm số nguyên x biết: ( 2x - 1) + ( 4x - 2) + ( 6x - 3) + .............+( 400x - 200) = 5 + 10 + 15 + .......+ 1000 .
x = 0
1: Tìm x€ Z, biết :
a: (-5)^2-(5x-3)=4
b: 259-51|4x+3|=(-10)^2.3+10^1
c: 7.(x-3)-5.(3-x) =11-5
Làm giúp mk nha!!!
a) 25-5x+3-4=0
=> 24-5x=0
=> 5x=24
=> x=\(\dfrac{24}{5}\)
b) 259-51/4x+3/=100.3+10=310
=> -51/4x+3/=310-259=51
=> /4x+3/=-51 (1)
Vi /4x+3/≥0 (2)
Tu (1)(2) => pt vo nghiem
c) 7x-21-15+5x=6
=> 12x-36-6=0
=> 12x-42=0
=> 12x=42
=> x=\(\dfrac{42}{12}=\dfrac{7}{2}\)