tìm x
x+30=50
tìm X
X : 50 = 218
TÌM X:75%xX+3/4xX+X=30
\(75\%x+\frac{3}{4}x+x=30\)
\(\Leftrightarrow\left(75\%+\frac{3}{4}+1\right)x=30\)
\(\Leftrightarrow\frac{5}{2}x=30\)
\(\Leftrightarrow x=30:\frac{5}{2}\)
\(\Leftrightarrow x=12\)
Tìm X biết : 75%xX+3/4xX+X=30
đổi 75%=3/4.Ta có:
3/4xX+3/4xX+X=30
(3/4+3/4+1)xX=30
5/2 x X=30
X = 30:5/2
X = 12
\(75\%\times x+\frac{3}{4}\times x+x=30\)
\(\frac{3}{4}\times x+\frac{3}{4}\times x+1\times x=30\)
\(\left(\frac{3}{4}+\frac{3}{4}+1\right)\times x=30\)
\(\frac{5}{2}\times x=30\)
\(x=30\div\frac{5}{2}\)
\(x=12\)
giá xăng từ 20 000 đồng lên 21 000 đồng 1 lít . hỏi giá xăng tăng bao nhiêu phần trăm?
Tìm số nguyên xx thỏa mãn:
-3x + 30/21 = 6/7
\(\Rightarrow-3x=\dfrac{6}{7}-\dfrac{30}{21}\\ \Rightarrow-3x=\dfrac{18}{21}-\dfrac{30}{21}\\\Rightarrow-3x=\dfrac{-12}{21}\\ \Rightarrow x=\dfrac{-12}{21}:3\\ \Rightarrow x=\dfrac{-12}{63}=\dfrac{-4}{21} \)
-3x+\(\dfrac{30}{21}=\dfrac{6}{7}\)
=>-3x=\(\dfrac{6}{7}-\dfrac{30}{21}\)
=>-3x=\(\dfrac{18-30}{21}\)
=>-3x=\(\dfrac{-12}{21}\)
=>x=\(\dfrac{-12}{21}.\dfrac{1}{3}\)
=>x=\(\dfrac{-12}{63}=\dfrac{-4}{21}\)
Vậy ......
Tìm x biết
30%xX+X=52
(30% + 1) x X = 52
130% x X = 52
X = 52 : 130%
X = 40
75%xX+3/4xX+X=30
tìm X
0,75 x X + 0,75 x X + X = 30
X x ( 0,75 + 0,75 + 1 ) = 30
X x 2,5 = 30
X = 30 : 2,5
X = 12
75%xX+3/4xX+X=30
<=>3/4xX+3/4xX+X=30
<=>10/4xX=30
<=>10xX=120
<=>X=120/10=12
Vậy X=12
75%xX+3/4xX+x=30
toán tìm X
0,75x + 0,75x = 30
0,75 . 2x = 30
2x = 40
x = 20
\(75\%\cdot x+\frac{3}{4}\cdot x+x=30\)
\(x\cdot\left(\frac{3}{4}+\frac{3}{4}+1\right)=30\)
\(x\cdot\frac{5}{2}=30\)
\(x=30\cdot\frac{2}{5}\)
\(x=12\)
\(75\%\cdot x+\frac{3}{4}\cdot x+x=30\)
\(\frac{3}{4}\cdot x+\frac{3}{4}\cdot x+x=30\)
\(\left(\frac{3}{4}+\frac{3}{4}\right)\cdot x+x=30\)
\(\frac{3}{2}\cdot x+x=30\)
\(\frac{3}{2}\cdot x+\frac{1}{1}\cdot x=30\)
\(\left(\frac{3}{2}+\frac{1}{1}\right)\cdot x=30\)
\(\frac{5}{2}\cdot x=30\)
\(x=30\text{ : }\frac{5}{2}\)
\(x=12\)
`lim(50 xx frac{1 - (4/5)^{n}}{1 - 4/5} + 4/5 xx 50 xx frac{1- (4/5)^{n-1}}{1 - 4/5})`
\(lim\left(50.\dfrac{1-\left(\dfrac{4}{5}\right)^n}{1-\dfrac{4}{5}}+\dfrac{4}{5}.50.\dfrac{1-\left(\dfrac{4}{5}\right)^{n-1}}{1-\dfrac{4}{5}}\right)\) \(=50.\dfrac{1}{\dfrac{1}{5}}+\dfrac{4}{5}.50.\dfrac{1}{\dfrac{1}{5}}=450\)
Tìm x
x+30%.x=-1,3
Giải thích rõ vì sao lại làm như vậy
cảm ơn nhé
x+ \(\dfrac{30}{100}\)x=-1,3
x(1+\(\dfrac{30}{100}\))= -1,3
x. 1,3= -1,3
x = -1
cho 2 đường thẳng xx' và yy'cắt nhau biết xOy-yOx'=50 độ TÌM SỐ ĐO CÁC GÓC SAU: xOy,yOx',x'Oy',y'Ox'