Tính A=1+3+32+...+39+310 sao cho 2A+1 duoi dang luy thua
Hay viet 2A + 1 duoi dang mot luy thua
Cho A= 1 + 3 + 32 + ..... + 32007
A = 1 + 3 + 32 + ... + 32007
3A = 3 + 32 + 33 + ... + 32008
3A - A = (3 + 32 + 33 + ... + 32008) - (1 + 3 + 32 + ... + 32007)
2A = 32008 - 1
2A + 1 = 32008 là lũy thừa của 3
A = 1 + 3 + 32 + ... + 32007
3A = 3 + 32 + 33 + ... + 32008
3A - A = (3 + 32 + 33 + ... + 32008) - (1 + 3 + 32 + ... + 32007)
2A = 32008 - 1
2A + 1 = 32008 là lũy thừa của 3
Cho A=1+3+3^2+...+3^10.Hay viet :
2A +1 duoi dang luy thua
Giúp mình voi ,mình đang cần gấp
A = 1 + 3 + 32 + ... + 310
3A = 3 + 32 + 33 + ... + 311
3A - A = (3 + 32 + 33 + ... + 311) - (1 + 3 + 32 + ... + 310)
2A = 311 - 1
2A + 1 = 311
viet cac tich sau duoi dang luy 1 luy thua
82.324=?
273.94.243=?
\(8^2.32^4=\left(2^3\right)^2.\left(2^5\right)^4=2^6.2^{20}=2^{26}\)
273.94.243\(=\left(3^3\right)^3.\left(3^2\right)^4.\left(3.2^3\right)^3=3^9.3^8.3^3.2^9=3^{20}.2^9\)
cho A=1+2+2^2 +2^3 +...+2^200 .hay viet A+1 duoi dang mot luy thua
A=1+2+22+23+...+2100
=>2A=2+22+23+24+...+2101
=>2A-A=(2+22+23+24+...+2101)-(1+2+22+23+...+2100)
=>A=2101-1
=>A+1=2101-1+1=2101
A = 1+2+22+23+...+2100
2A = 2+22+23+24+...+2100
2A - A = 2100 - 1
=> A = 2100 - 1
=> A + 1 = 2100
A=1+2+2^2 +2^3 +...+2^200
2A = 2+2^2 + 2^3 + ...+2^200 + 2^201
2A - A =( 2+2^2 + 2^3 + ...+2^200 + 2^201)-(1+2+2^2 + 2^3 + ...+2^200 )
=> A = 2^201 - 1
=> A+1 = 2^201
cho a =1+2+22+23+.....+2200.hay tinh A+1 duoi dang 1 luy thua
viet ket qua cac phep tinh sau duoi dang luy thua 329:64
\(32^9:64=\left(2^5\right)^9:2^6=2^{45}:2^6=2^{45-6}=2^{39}\)
viet so 729 duoi dang 1 luy thua voi 3 co so khac nhau ( so mu > 1)
Viet cac tich sau duoi dang 1 luy thua
2.2.2.3.3.6^2.3
\(\left(2\cdot2\cdot2\cdot3\cdot3\cdot6\right)^{2\cdot3}\)
\(=432^6\)
hok tốt
2.2.2.3.3.6^2 . 3 = 23 . 32 . 36 . 3
= 23 . 32 . 22 . 32 . 3
= 24 . 35
viet cac tich sau duoi dang 1 luy thua
a/ -8 . -3 . +125
b/ 27 . -23 . -7 .+49