Tìm x biết :
\(\frac{11}{13}\)-(\(\frac{5}{42}\)-x)=-(\(\frac{15}{28}\)-\(\frac{11}{13}\))
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Bài 2 : Tìm x, biết :
\(a.\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)
\(b.\left(\frac{7}{12}+x\right)-\frac{11}{12}=\frac{2}{3}\)
\(\frac{11}{13}-(\frac{5}{42}-x)-(\frac{15}{28}-\frac{11}{13})\)
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\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)
\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{5}{28}-\frac{11}{13}\right)\)
\(\frac{11}{13}-\frac{5}{42}+x=-\frac{5}{28}+\frac{11}{13}\)
\(x=-\frac{5}{28}+\frac{11}{13}-\frac{11}{13}+\frac{5}{42}\)
\(x=\left(\frac{11}{13}-\frac{11}{13}\right)-\left(\frac{5}{28}-\frac{5}{42}\right)\)
\(x=-\left(\frac{15}{84}-\frac{10}{84}\right)\)
\(x=-\frac{5}{84}\)
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Tìm x biết:
a) \(\frac{11}{3}\)- (\(\frac{5}{42}\)- x ) = - (\(\frac{15}{28}\) - \(\frac{11}{13}\))
b) | x + \(\frac{4}{15}\)| - | -3,75| = -(-2,15)
\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{5}{28}-\frac{11}{13}\right)\)
11/13-(5/42-x)= 243/364
5/42-x=243/364- 11/13
5/42-x= -5/28
x=5/42-(-5/28)
x=25/84
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\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{5}{28}-\frac{11}{13}\right)\)
\(\frac{11}{13}-\frac{5}{42}+x=-\frac{5}{28}+\frac{11}{13}\)
=> \(x=-\frac{5}{28}+\frac{11}{13}-\frac{11}{13}+\frac{5}{42}\)
=> \(x=-\frac{5}{28}+\frac{5}{42}\)
=> \(x=-\frac{210}{1176}+\frac{140}{1176}=\frac{-70}{1176}=\frac{-5}{84}\)
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\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{5}{28}-\frac{11}{13}\right)\)
\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=\frac{243}{364}\)
\(\frac{5}{42}-x=\frac{11}{13}-\frac{243}{364}\)
\(\frac{5}{42}-x=\frac{5}{28}\)
\(x=\frac{5}{42}-\frac{5}{28}\)
\(x=-\frac{5}{84}\)
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tìm x biết a) \(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)
b) \(\)/ x + \(\frac{4}{15}\)/ - / -37,5 / = - / -2,15 /
Tìm x,biết:
1.\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)
2. \(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
3. \(\left|4.x\right|-\left|-13.5\right|=\left|2\frac{1}{4}\right|\)
Nhanh hộ em với ạ !!
làm tiếp cái trước(ấn nhầm)
\(x=\frac{5}{42}-\frac{15}{28}\)
\(x=\frac{5.4}{6.4.7}-\frac{15.6}{4.7.6}\)
\(x=\frac{20}{168}-\frac{90}{168}\)
\(x=\frac{-70}{168}\)
\(x=\frac{-5}{12}\)
2.
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1.
\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)
\(\frac{11}{13}-\frac{5}{42}+x=-\frac{15}{28}+\frac{11}{13}\)
\(\frac{11}{13}-\frac{11}{13}-\frac{5}{42}+\frac{15}{28}=-x\)
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/x+\(\frac{4}{15}\)/ \(-\)\(3,75\)\(=\)\(-2,15\)
/ \(x+\frac{4}{15}\)/ \(=\)\(-2,15+3,75\)
/ \(x+\frac{4}{15}\)/ \(=\)\(\frac{8}{5}\)
TH1: \(x+\frac{4}{15}=\frac{8}{5}\) TH2: \(x+\frac{4}{15}=-\frac{8}{5}\)
\(=>x=\frac{8}{5}-\frac{4}{15}\) \(=>x=-\frac{8}{5}-\frac{4}{15}\)
\(=>x=\frac{24}{15}-\frac{4}{15}\) \(=>x=-\frac{24}{15}-\frac{4}{15}\)
\(=>x=\frac{20}{15}\) \(=>x=-\frac{28}{15}\)
\(=>x=\frac{4}{3}\)
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\(\frac{11}{13}\) - ( \(\frac{5}{42}\) - x ) = - ( \(\frac{15}{28}\) - \(\frac{11}{13}\) )
\(\Leftrightarrow\frac{11}{13}-\frac{5}{42}+x=-\left(-\frac{113}{364}\right)\)
\(\Leftrightarrow\frac{397}{546}+x=\frac{113}{364}\)
\(\Leftrightarrow x=\frac{113}{364}-\frac{397}{546}=-\frac{5}{12}\)
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\(\Rightarrow\frac{5}{42}-x=\frac{11}{13}+\left(\frac{15}{28}-\frac{11}{13}\right)\)
\(\Rightarrow\frac{5}{42}-x=\frac{15}{28}\)
\(\Rightarrow x=\frac{5}{42}-\frac{15}{28}=-\frac{5}{12}\)
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\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)
\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=\frac{113}{364}\)
\(\left(\frac{5}{42}-x\right)=\frac{11}{13}-\frac{113}{364}\)
\(\left(\frac{5}{42}-x\right)=\frac{15}{28}\)
\(x=\frac{5}{42}-\frac{15}{28}\)
\(=-\frac{5}{12}\)
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Tìm x, biết:
\(x=\left(2-\frac{5}{3}+\frac{7}{6}-\frac{9}{10}+\frac{11}{15}-\frac{13}{21}+\frac{15}{28}-\frac{17}{36}+\frac{19}{45}\right)\times\frac{5}{3}\)
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