B = 1 - 3/2×10 - 3/4×15 - 3/6×20 - ... - 3/198×500

B = 1 - (3/2×10 + 3/4×15 + 3/6×20 + ... + 3/198×500)

B = 1 - 3/2×5 × (1/1×2 + 1/2×3 + 1/3×4 + ... + 1/99×100)

B = 1 - 3/10 × (1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/99 - 1/100)

B = 1 - 3/10 × (1 - 1/100)

B = 1 - 3/10 × 99/100

B = 1 - 297/1000

B = 703/1000

\(1-\frac{3}{2.10}-\frac{3}{4.15}-\frac{3}{6.20}-\frac{3}{8.25}-...-\frac{3}{198.500}\)

\(=1-\left(\frac{3}{2.10}+\frac{3}{4.15}+\frac{3}{6.20}+...+\frac{3}{198.500}\right)\)

  \(=1-\frac{3}{2.5}.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\right)\)

\(=1-\frac{3}{10}.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\right)\)

\(=1-\frac{3}{10}.\left(1-\frac{1}{100}\right)\)

\(=1-\frac{3}{10}.\frac{99}{100}\)

\(=1-\frac{297}{1000}\)

\(=\frac{703}{1000}\)

P/s : Không biết đúng hông nha, làm đại

\(A=1-\left(\frac{3}{2.10}+\frac{3}{4.15}+\frac{3}{6.20}+....+\frac{3}{198.500}\right)\)

  \(=1-\frac{3}{2.5}\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\right)\)

   \(=1-\frac{3}{25}\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\right)\)

   \(=1-\frac{3}{25}\left(1-\frac{1}{100}\right)\)

\(=1-\frac{3.99}{25.100}=\frac{703}{1000}\)