9999999999x9999999999=99999999980000000001

9999999999 x 9999999999 = 9999999999^2

9999999999 x 9999999999 =9999999999^2

= 5555555555

5555555555

5555555555 k nha

=5555555555

k nha!

8888888888 - 3333333333 = 5555555555

kb đi mình k

= 11111111110

11111111110 nha kick minh

2222222222+8888888888=11111111110

tk cho mk nhe

mk nhanh nhat

mk tk lai cho 3 diem hoi dap

\(A=\frac{\text{9999999999}}{2}-\frac{\text{9999999999}}{3}-\frac{\text{9999999999}}{6}\)

\(A=\text{9999999999}\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)

\(A=\text{9999999999}.0\)

\(A=0\)

Vậy A = B 

A = 0 nhé bạn tôi thề là đúng luôn

bạn ko cần cảm ơn đâu cho 1 k là ok

12/25

3623/50000

64

mik làm đầu tiên

k mik nhé

4 : 23  x 3

= 4/23  x 3

= 12/23

6 : 1 + ? = 70

6 + ? = 70

? = 70 - 6

? = 64

tk mk nha

mà vô '' khách sạn '' làm gì thế bạn ??????

8982489971

1 + 1 + 4 + 53 + 8888888888 + 92823252 + 777772

= 8982489971.

=8982489971

hok tốt

kb ko

\(\frac{9999999999}{2}+\frac{9999999999}{3}+\frac{9999999999}{6}\)

\(=9999999999\cdot\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{6}\right)\)

\(=9999999999\cdot1\)

\(=9999999999\)

Nhân xét biểu thức A, ta thấy:

   \(\frac{9999999999}{2}>\frac{9999999999}{3}>\frac{9999999999}{6}>0\)

=> \(A>0\left(đpcm\right)\)

ta có 9999999999/2=9999999999*3/2*3

9999999999/3=9999999999*2/3*2

suy ra 9999999999*3/2*3 - 9999999999*2/3*2=9999999999*3-9999999999*2/6=9999999999/6

suy ra A=9999999999/6-9999999999/6=0

vậy A=0

\(A=9999999999.\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)

\(A=9999999999.0=0\)

Vậy A=0