viet ket qua phep tinh duoi dang mot luy thua
a4:a
viet ket qua phep tinh duoi dang mot luy thua
(ab)*(ab)2
(ab) x (ab)2
= (ab)1 x (ab)2
= (ab)1+2
=(ab)3
hok tốt..........
viet ket qua cac phep tinh sau duoi dang luy thua 329:64
\(32^9:64=\left(2^5\right)^9:2^6=2^{45}:2^6=2^{45-6}=2^{39}\)
Viet ket qua moi phep tinh sau duoi dang mot luy thua
a 11^8:11^3
b 17^11:17^9
c 4^3:2^2
d a^5:a(a khac 0)
viet ket qua phep tinh duoi dang luy thua
a, 4^2-8^5
b, 27^3.9^4
c, 64^3.167
Giải:
a) \(4^2.8^5=\left(2^2\right)^2.\left(2^3\right)^5=2^4.2^{15}=2^{19}\)
b) \(27^3.9^4=\left(3^3\right)^3.\left(3^2\right)^4=3^9.3^8=3^{17}\)
c) \(64^3.16^7=\left(4^3\right)^3.\left(4^2\right)^7=4^9.4^{14}=4^{23}\)
viet ket qua phep tinh duoi dang luy thua
a, 4^2-8^5
b, 27^3.9^4
c, 64^3.167
viet ket qua cac phep tinh sau duoi dang 1 luy thua
5 mũ 13 : 5 mũ 7
a mũ 9 . a .a mũ 5
513: 57 = 5 13-7=56=15625
a9.a.a5=a9+1+5=a15
Trả lời :
513 : 57 = 513-7 = 56
a9 . a . a5 = a9+1+5 = a15
~~Học tốt~~
\(5^{13}:5^7=5^{13-7}=5^6\)
\(a^9\cdot a\cdot a^5=a^{9+1+5}=a^{15}\)
viet ket qua phep tinh duoi dang 1 luy thua
9 mũ 5 : 3 mũ 7
8 mũ 6: 4 mũ 8
25 mũ 7:125 mũ 3
\(9^5:3^7=\left(3^2\right)^5:3^7=3^{10}:3^7=3^3\)
\(8^6:4^8=\left(2^3\right)^6:\left(2^2\right)^8=2^{18}:2^{16}=2^2\)
\(25^7:125^3=\left(5^2\right)^7:\left(5^3\right)^3=5^{14}:5^9=5^5\)
Chúc bạn học tốt !
Viet ket qua cac phep tinh sau duoi dang mot luy thua:
a)153÷15 b)25÷22
c)37÷32 d)73÷7
a) 153 : 15 = 152
b) 25 : 22 = 23
c) 37 : 32 = 35
d) 73 : 7 = 72
Ủng hộ mk nha ^_-
a) \(15^3:15=15^{3-1}=15^2=225\)
b) \(2^5:2^2=2^{5-2}=2^3=8\)
c) \(3^7:3^2=3^{7-2}=3^5=243\)
d) \(7^3:7=7^{3-1}=7^2=49\)
nha m.n. Thanks
a) 153 : 15 = 152
b) 25 : 22 = 23
c) 37 : 32 = 35
d) 73 : 7 = 72
viet ket qua phep tinh sau duoi dang 1 luy thua
a, 2008^2000 : 2008^100
b, 2000^2001 : 2000
c, 16^2002 : 4^2
d, (2^2009 × 2^2001): ( 2^2008× 2^2000)
a) 20082000 : 2008100 = 20082000-100 = 20081900
b) 20002001 : 2000 = 20002001 : 20001 = 20002001-1 = 20002000
c) 162002 : 42 = (42)2002 : 42 = 44004 : 42 = 44004-2 = 44002
d) (22009.22001):(22008.22000) = (22009+2001):(22008+2000) = 24010 : 24008 = 24010-4008 = 22
a . 20082000-100
20081900
b. 20002001-1
20002000
c. 162002 : 4*4
162000 : 16
162000-1
161999
d.( 22009+2001 ) : ( 22008+2000 )
24010 : 24008
24010-4008
22