x+100=150-20
tìm x biết:
x-{150-[30+20.(100:20)]}= 30
làm hộ tui
x-{150-[30+20.(100:20)]}=30
x={150-[30+20.5]}=30
x={150-[20+100]}=30
x={150-120}=30
x=30
Vậy x=30
x - { 150 - [30 + 20 . ( 100.20 )}} = 30
X = {150 - [30 + 20 . 5 ]} = 30
X= [150 - 130 ] = 30
X - 20 = 30
x = 30 + 20
X = 50
XONG RÙI K MÌNH NHA
120 + ( 50 +x) =180
140 + (20- x )=150
100 - ( 25+ x )=40
130 - (100 + x) =25
174 -( 143 +x ) =22
a)50 + x = 180 - 120
50 + x = 60
x = 60-50
x = 10
b)20-x = 150-140
20-x = 10
x = 20-10
x = 10
c) 25+x = 100-40
25+x=60
x= 60-25
x=35
d) 100+x =130-25
100+x = 105
x = 105-100
x = 5
e) 143+x = 174-22
143+x = 152
x = 152-143
x = 9
ỦNG HỘ MK NHÁ
120 + ( 50 + x ) = 180
50 + x = 180 - 120
50 + x = 60
x = 60 - 50
x = 10
140 + ( 20 - x ) = 150
20 - x = 150 - 140
20 - x = 10
x = 20 - 10
x = 10
100 - ( 25 + x ) = 40
25 + x = 100 - 40
25 + x = 60
x = 60 - 25
x = 35
130 - ( 100 + x ) = 25
100 + x = 130 - 25
100 + x = 105
x = 105 - 100
x = 5
174 - ( 143 + x ) = 22
143 + x = 174 - 22
143 + x = 152
x = 152 - 143
x = 9
k mk nha
Thanks nhìu
\(120+\left(50+x\right)=180\)
\(\Rightarrow50+x=180-120\)
\(\Rightarrow50+x=60\)
\(\Rightarrow x=60-50=10\)
Vậy x = 10
\(140+\left(20-x\right)=150\)
\(\Rightarrow20-x=150-140\)
\(\Rightarrow20-x=10\)
\(\Rightarrow x=20-10=10\)
Vậy x =x10
\(100-\left(25+x\right)=40\)
\(\Rightarrow25+x=100-40\)
\(\Rightarrow25+x=60\)
\(\Rightarrow x=60-25=35\)
Vậy x = 35
\(130-\left(100+x\right)=25\)
\(\Rightarrow100+x=130-25\)
\(\Rightarrow100+x=105\)
\(\Rightarrow x=105-100=5\)
Vậy x = 5
\(174-\left(143+x\right)=22\)
\(\Rightarrow143+x=174-22\)
\(\Rightarrow143+x=152\)
\(\Rightarrow x=152-143=9\)
Vậy x = 9
1 . Tìm x :
a ) \(\frac{1}{2}x+\frac{9}{4}-\frac{8}{20}=\frac{77}{20}\)
b ) \(\frac{28}{100}x+\frac{4}{25}+\frac{10}{4}=\frac{203}{50}\)
c ) \(\frac{100}{50}=\frac{1}{2}x\)
a)\(\frac{1}{2}x+\frac{9}{4}-\frac{8}{20}=\frac{77}{20}\)
<=>\(\frac{1}{2}x=\frac{77}{20}-\frac{9}{4}+\frac{8}{20}=\frac{77-45+8}{20}\)
<=>\(\frac{1}{2}x=\frac{40}{20}=2\)
<=>\(x=2:\frac{1}{2}=2.2\)
<=>x=4
Vậy x=4
giải phương trình \(\frac{100}{x}-\frac{100}{x+20}=\frac{1}{3}\)
\(\frac{100\left(x+20\right)}{x\left(x+20\right)}-\frac{100x}{x\left(x+20\right)}=\frac{1}{3}\)
\(\frac{100x+2000-100x}{x\left(x+20\right)}=\frac{1}{3}\)
\(\frac{2000}{x\left(x+20\right)}=\frac{1}{3}\)
\(\Rightarrow x^2+20x=3.2000\)
\(\Rightarrow x^2+20x-6000=0\)
ĐKXĐ: \(x\ne0;x\ne-2\)
Ta có: \(\frac{100x+2000-100x}{x\left(x+20\right)}=\frac{1}{3}\)
\(\Leftrightarrow\frac{2000}{x^2+20x}=\frac{1}{3}\)
\(\Leftrightarrow x^2+20x=6000\)
\(\Leftrightarrow x^2+2.10x+100=6100\)
\(\Leftrightarrow\left(x+10\right)^2=6100\)
\(\Leftrightarrow\orbr{\begin{cases}x=10\sqrt{61}-10\left(TM\right)\\x=-10\sqrt{61}-10\left(TM\right)\end{cases}}\)
Vậy...
Tìm x :
a ) \(\frac{1}{2}x+\frac{9}{4}-\frac{8}{20}=\frac{77}{20}\)
b ) \(\frac{28}{100}x+\frac{4}{25}+\frac{10}{4}=\frac{203}{50}\)
c ) \(\frac{100}{58}=\frac{1}{2}x\)
AI NHANH NHẤT + RÕ RÀNG NHẤT + ĐÚNG NHẤT = 2 LIKE
b)\(\frac{28}{100}x+\frac{4}{25}+\frac{10}{4}=\frac{203}{50}\)
<=>\(\frac{28}{100}x=\frac{203}{50}-\frac{10}{4}-\frac{4}{25}=\frac{406-250-16}{100}\)
<=>\(\frac{28}{100}x=\frac{140}{100}\)
<=>\(x=\frac{140}{100}:\frac{28}{100}=\frac{140}{100}.\frac{100}{28}\)
<=>x=5
a) \(\frac{1}{2}x+\frac{9}{4}-\frac{8}{20}=\frac{77}{20}\)
=> \(\frac{1}{2}x=\frac{77}{20}+\frac{8}{20}-\frac{9}{4}=2\)
=> \(\frac{x}{2}=2\Rightarrow x=2\cdot2=4\)
vậy x = 4
b) \(\frac{28}{100}x+\frac{4}{25}+\frac{10}{4}=\frac{203}{50}\)
=> \(\frac{28}{100}x=\frac{203}{50}-\frac{10}{4}-\frac{4}{25}=1\frac{2}{5}=\frac{7}{5}\)
=> \(\frac{28x}{100}=\frac{7}{5}\Rightarrow28x=\frac{100\cdot7}{5}=140\Rightarrow x=140:28=5\)
vậy x = 5
c) \(\frac{100}{58}=\frac{1}{2}x\)
=> \(\frac{100}{58}=\frac{x}{2}\Rightarrow x=\frac{100\cdot2}{58}=3\frac{13}{29}=\frac{100}{29}\)
vậy x = 100/29
100 - 10 x ( X + 1 ) = 20
\(\frac{x}{2}=\frac{5}{y}=\frac{20}{60}\)
Ai giải được mik tick nha !
(4,53 x 02+6,165 x 3):2,5
=(0,906 + 18,495); 2,5
=19,401: 2,5
=7,7604
100:4+5-10-5+50+46+4-120+240+295-150-55+20-150+100=
trả lời
=259
chúc bn
hc tốt
100:4+5-10-5+50+46+4-120+240+295-150-55+20-150+100=259
Chúc học tốt!!!!!!!!
trả lời
=295
chúc bn
hc tốt
Tìm x, y biết :
\(\left(x+20\right)^{100}+\left|y+4\right|=0\)
Ta có: \(\left(x+20\right)^{100}\ge0;\left|y+4\right|\ge0\)
Mà \(\left(x+20\right)^{100}+\left|y+4\right|=0\)
\(\Rightarrow x+20=0\text{ và }y+4=0\)
\(\Rightarrow x=-20\text{ và }y=-4\)
Vậy...
150 - 40 x 20 x 5 x 0,5 x 0,25 x 0,2 - 50
1 + 2 + 3 +......+ 98 + 99 + 100