So sánh:
\(\frac{3}{124},\frac{1}{41},\frac{2}{83},\frac{5}{207}\)
\(\frac{-2525}{2929}v\text{à}\frac{-217}{245}\)
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So sánh :
a)\(\frac{3}{124},\frac{1}{41},\frac{5}{207},\frac{2}{83}\)
b)\(\frac{-2525}{2929}và\frac{-217}{245}\)
c)\(A=\frac{3^{10}+1}{3^9+1}vàB=\frac{3^9+1}{3^8+1}\)
d)\(\frac{27}{82}và\frac{26}{75}\)
so sánhfrac{3}{124};frac{1}{41};frac{5}{207};frac{2}{83}frac{16}{9};frac{24}{13}frac{27}{82};frac{26}{75}frac{134}{43};frac{55}{21};frac{74}{19};frac{116}{37}-frac{2525}{2929};-frac{217}{245}-frac{4}{78};frac{64}{-95}-frac{49}{78};frac{64}{-95}
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so sánh
\(\frac{3}{124};\frac{1}{41};\frac{5}{207};\frac{2}{83}\)
\(\frac{16}{9};\frac{24}{13}\)
\(\frac{27}{82};\frac{26}{75}\)
\(\frac{134}{43};\frac{55}{21};\frac{74}{19};\frac{116}{37}\)
\(-\frac{2525}{2929};-\frac{217}{245}\)
\(-\frac{4}{78};\frac{64}{-95}\)
\(-\frac{49}{78};\frac{64}{-95}\)
a/ Ta có:
\(\frac{3}{124}=\frac{30}{1240}\) ; \(\frac{1}{41}=\frac{30}{1230}\) ; \(\frac{5}{207}=\frac{30}{1242}\) ; \(\frac{2}{83}=\frac{30}{1245}\)
Vì các phân số trên đều cùng tử nên ta so sánh mẫu : 1230<1240<1242<1242
=> \(\frac{30}{1230}>\frac{30}{1240}>\frac{30}{1242}>\frac{30}{1245}\)
Hay : \(\frac{1}{41}>\frac{3}{124}>\frac{5}{207}>\frac{2}{83}\)
b/ Ta có:
\(\frac{16}{9}=\frac{48}{27};\frac{24}{13}=\frac{48}{26}\)
Vì 27>26
=> \(\frac{16}{9}< \frac{24}{13}\)
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3124=3012403124=301240 ; 141=301230141=301230 ; 5207=3012425207=301242 ; 283=301245283=301245
Vì các phân số trên đều cùng tử nên ta so sánh mẫu : 1230<1240<1242<1242
=> 301230>301240>301242>301245301230>301240>301242>301245
Hay : 141>3124>5207>283141>3124>5207>283
b/ Ta có:
169=4827;2413=4826169=4827;2413=4826
Vì 27>26
=> 169<2413169<2413
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So sánh các phân số:
a)\(\frac{3}{124},\frac{1}{41},\frac{5}{207},\frac{2}{83}\)
b)\(\frac{134}{43},\frac{55}{21},\frac{74}{19},\frac{116}{37}\)
c)\(\frac{-2525}{2929},,\frac{-217}{245}\)
d)\(\frac{27}{28},\frac{26}{75}\)
e)\(\frac{-49}{78}.\frac{64}{-95}\)
Bài 1: So sánh các ps sau: a)frac{1}{2};frac{1}{3};frac{2}{3}b)frac{4}{9};-frac{1}{2};frac{3}{7}c)frac{3}{124};frac{1}{41};frac{5}{207};frac{2}{83}d)frac{134}{43};frac{55}{21};frac{74}{19};frac{116}{37}e)frac{16}{9};frac{24}{13}g)frac{-2525}{2929};frac{-217}{245}h)frac{27}{82};frac{26}{75}i)frac{-49}{75};frac{64}{-95}
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Bài 1: So sánh các ps sau:
a)\(\frac{1}{2};\frac{1}{3};\frac{2}{3}\)
b)\(\frac{4}{9};-\frac{1}{2};\frac{3}{7}\)
c)\(\frac{3}{124};\frac{1}{41};\frac{5}{207};\frac{2}{83}\)
d)\(\frac{134}{43};\frac{55}{21};\frac{74}{19};\frac{116}{37}\)
e)\(\frac{16}{9};\frac{24}{13}\)
g)\(\frac{-2525}{2929};\frac{-217}{245}\)
h)\(\frac{27}{82};\frac{26}{75}\)
i)\(\frac{-49}{75};\frac{64}{-95}\)
Xem thêm câu trả lời
So sánh: \(\frac{3}{124},\frac{1}{41},\frac{2}{83},\frac{5}{207}\)
1/41>3/124>5/207>2/83
Ta co
3/124=30/1240
1/41=30/1230
5/207=30/1242
2/83=30/1245
k cho mik nha!
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so sánh \(\frac{-2525}{2929}\)và \(\frac{-217}{245}\)
Ta có : \(\frac{-2525}{2929}=\left(-1\right)\frac{25}{29}\)
\(\frac{-217}{245}=\left(-1\right)\frac{217}{245}\)
Xét \(\frac{25}{29}\)và \(\frac{217}{245}\)
Có 25 . 245 = 6125
217 . 29 = 6293
Có 6293>6125
=> 25/29<217/245
=>-25/29>-217/245
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so sánhfrac{1}{2},frac{1}{3},frac{2}{3} frac{4}{9},-frac{1}{2},frac{3}{7}frac{3}{124},frac{1}{41},frac{5}{207},frac{2}{83} frac{134}{43},frac{55}{21},frac{74}{19},frac{116}{37} frac{16}{9},frac{24}{13} frac{-2525}{2929},frac{-217}{245}frac{27}{82},frac{26}{75} fr...
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so sánh
\(\frac{1}{2},\frac{1}{3},\frac{2}{3}\) \(\frac{4}{9},-\frac{1}{2},\frac{3}{7}\)
\(\frac{3}{124},\frac{1}{41},\frac{5}{207},\frac{2}{83}\) \(\frac{134}{43},\frac{55}{21},\frac{74}{19},\frac{116}{37}\)
\(\frac{16}{9},\frac{24}{13}\) \(\frac{-2525}{2929},\frac{-217}{245}\)
\(\frac{27}{82},\frac{26}{75}\) \(\frac{-49}{78},\frac{64}{-95}\)
So sánh:
a) \(\frac{-2525}{2929}\) và \(\frac{-217}{245}\)
b) \(\frac{27}{82}\) và \(\frac{26}{75}\)
c) A= \(\frac{3^{10}+1}{3^9+1}\) và B= \(\frac{3^9+1}{3^8+1}\)
A=\(\frac{3^{10}+1}{3^9+1}\)>1
=> A=\(\frac{3^{10}+1}{3^9+1}\)> \(\frac{3^{10}+1+2}{3^9+1+2}\)
=>A=\(\frac{3^{10}+1}{3^9+1}\)>\(\frac{3^{10}+3}{3^9+3}\)
=>A=\(\frac{3^{10}+1}{3^9+1}\)>\(\frac{3\left(3^9+1\right)}{3.\left(3^8+1\right)}\)
=>A=\(\frac{3^{10}+1}{3^9+1}\)>\(\frac{3^9+1}{3^8+1}\)=B
vậy A>B
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vì 1 là bạn quy đồng lên
hai là giải thich như sau
\(\frac{25}{29}\)= 1- \(\frac{4}{29}\)
\(\frac{31}{35}\)= 1- \(\frac{4}{35}\) mà \(\frac{4}{29}\)> \(\frac{4}{35}\)
nên 1-\(\frac{4}{29}\)<1-\(\frac{4}{35}\)
vậy \(\frac{25}{29}\)<\(\frac{31}{35}\)
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a. \(\frac{-2525}{2929}\)= -\(\frac{25.101}{29.101}\)=\(\frac{-25}{29}\)
\(\frac{-217}{245}\)=\(\frac{-7.31}{7.35}\)=\(\frac{-31}{35}\)
vì \(\frac{25}{29}\)>\(\frac{31}{35}\) => \(\frac{-25}{29}\)<\(\frac{-31}{35}\)
b.ta có 27.75=2025
26.82=2132
=> 26.82> 27.75
vậy \(\frac{27}{82}\)<\(\frac{26}{75}\)
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Xem thêm câu trả lời
so sánh :
a) \(\frac{3}{124};\frac{1}{41};\frac{5}{207}và\frac{2}{83}\)
b)\(\frac{16}{9}và\frac{24}{13}\)
c)\(\frac{27}{82}và\frac{26}{72}\)