Tính A
A = (-3)+(-3)2+(-3)3+(-3)4+...+(-3)200
Tính thuận tiện Q=1/2*2+1/3*3+1/4*4+....+1/200*200 so sánh Q với 3/4 giúp mk vớiiiiiiiiiiiiiiiiiiiiiii
Ta đã biết \(\dfrac{1}{a\cdot a}< \dfrac{1}{\left(a+1\right)\left(a-1\right)}\) ( a ϵ Z )
⇒ \(Q=\dfrac{1}{2\cdot2}+\dfrac{1}{3\cdot3}+\dfrac{1}{4\cdot4}+...+\dfrac{1}{200\cdot200}\) < \(\dfrac{1}{1\cdot3}+\dfrac{1}{2\cdot4}+\dfrac{1}{3\cdot5}+...+\dfrac{1}{199\cdot201}\)
Ta có \(\dfrac{1}{1\cdot3}+\dfrac{1}{2\cdot4}+\dfrac{1}{3\cdot5}+...+\dfrac{1}{199\cdot201}\)
= \(\dfrac{1}{2}\left(\dfrac{2}{1\cdot3}+\dfrac{2}{2\cdot4}+\dfrac{2}{3\cdot5}+...+\dfrac{2}{199\cdot201}\right)\)
= \(\dfrac{1}{2}\left(1-\dfrac{1}{3}+\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{3}-\dfrac{1}{5}+...+\dfrac{1}{199}-\dfrac{1}{201}\right)\)
= \(\dfrac{1}{2}\left(1-\dfrac{1}{201}\right)=\dfrac{1}{2}\cdot\dfrac{200}{201}=\dfrac{100}{201}< \dfrac{100}{200}=\dfrac{1}{2}< \dfrac{3}{4}\)
Vậy Q < \(\dfrac{3}{4}\)
a)Tính tổng :E=1+1/2(1+2)+1/3(1+2+3)+1/4(1+2+3+4)+...+1/200(1+2+3+4+...+200)
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Áp dụng công thức \(1+2+...+n=\frac{n\left(n+1\right)}{2}\)ta có:
\(E=1+\frac{1}{2}\left(1+2\right)+\frac{1}{3}\left(1+2+3\right)+...+\frac{1}{200}\left(1+2+...+200\right)\)
\(=1+\frac{1}{2}.\frac{2.3}{2}+\frac{1}{3}.\frac{3.4}{2}+....+\frac{1}{200}.\frac{200.201}{2}\)
\(=1+\frac{3}{2}+\frac{4}{2}+....+\frac{201}{2}\)
\(=\frac{2+3+4+...+201}{2}=\frac{\frac{201.202}{2}-1}{2}=10150\)
Thực hiện tính:
E=1+1/2.(1+2)+1/3.(1+2+3)+1/4.(1+2+3+4)+.....+1/200(1+2+...+200)
a/ Tính tổng: S = (-1/3)^0 + (-1/3)^1 + (-1/3)^2 + ... +(-1/3)^200
b/ CMR: S = 1/2! + 2/3! + 3/4! +...+ 199/200! < 1
TÍNH TỔNG:
a)A=3-3^2+3^3-3^4+...+3^99-3^100
b)B=-(4/5)+4/5^2-4/5^3+...-4/5^199+4/5^200
Tính nhẩm:
Cách làm: 200 x 3 = ?
Nhẩm: 2 trăm x 3 = 6 trăm
Vậy: 200 x 3 = 600
200 x 2 = 300 x 2 =
200 x 4 = 400 x 2 =
100 x 5 = 500 x 1 =
Học sinh nhẩm và ghi kết quả như sau:
200 x 2 = 400
200 x 4 = 800
100 x 5 = 500
300 x 2 =600
400 x 2 =800
500 x 1 =500
200 x 2 = 400 300 x 2 =600
200 x 4 = 800 400 x 2 =800
100 x 5 = 500 500 x 1 =500
thực hiện phép tính
E=1+1/2(1+2)+1/2(1+2+3)+1/4(1+2+3+4)+.....+1/200(1+2+3+....+200)
Xét thừa số tổng quát:
\(\frac{1+2+...+n}{n}=\frac{n\left(n+1\right):2}{n}=\frac{n+1}{2}\)
Thay vào bài toán:
\(E=1+\frac{1}{2}\left(1+2\right)+\frac{1}{3}\left(1+2+3\right)+...+\frac{1}{200}\left(1+2+3+...+200\right)\)
\(E=1+\frac{1+2}{2}+\frac{1+2+3}{3}+...+\frac{1+2+3+...+200}{200}\)
\(E=1+\frac{2+1}{2}+\frac{3+1}{2}+...+\frac{200+1}{2}\)
\(E=\frac{2}{2}+\frac{3}{2}+\frac{4}{2}+...+\frac{201}{2}\)
\(E=\frac{2+3+4+...+201}{2}=\frac{20300}{2}=10150\)
Tính nhẩm:
a) 2 x 2 = ...... 3 x 3 = ......
2 x 4 = ...... 3 x 5 = ......
2 x 6 = ...... 3 x 7 = ......
2 x 8 = ...... 3 x 9 = ......
4 x 4 = ...... 5 x 5 = ......
4 x 2 = ...... 5 x 7 = ......
4 x 6 = ...... 5 x 9 = ......
4 x 8 = ...... 5 x 3 = ......
b) 200 x 4 = ...... 300 x 2 = ......
200 x 2 = ...... 300 x 3 = ......
400 x 2 = ...... 500 x 1 = ......
100 x 4 = ...... 100 x 3 = ......
a) 2 x 2 = 4 3 x 3 = 9
2 x 4 = 8 3 x 5 = 15
2 x 6 = 12 3 x 7 = 21
2 x 8 = 16 3 x 9 = 27
4 x 4 = 16 5 x 5 = 25
4 x 2 = 8 5 x 7 = 35
4 x 6 = 24 5 x 9 = 45
4 x 8 = 32 5 x 3 = 15
b) 200 x 4 = 800 300 x 2 = 600
200 x 2 = 400 300 x 3 = 900
400 x 2 = 800 500 x 1 = 500
100 x 4 = 400 100 x 3 = 300
Trả lời 1 câu thôi nhé em 100 nhân 4 bằng 400 nhá em
a) 2 x 2 =4 ...... 3 x 3 = ..9....
2 x 4 = ....8.. 3 x 5 = ...15...
2 x 6 = ....12.. 3 x 7 = .21.....
2 x 8 = ..16.... 3 x 9 = ..27....
4 x 4 = ...16... 5 x 5 = ...25...
4 x 2 = ...8... 5 x 7 = ..35....
4 x 6 = .....24. 5 x 9 = .45.....
4 x 8 = ..32.... 5 x 3 = .15.....
b) 200 x 4 = 800...... 300 x 2 =600 ......
200 x 2 = ..400.... 300 x 3 = 900......
400 x 2 = .....800. 500 x 1 = ..500....
100 x 4 = ....400.. 100 x 3 = .300.....
Tính: \(E=1+\frac{1}{2}\left(1+2\right)+\frac{1}{3}\left(1+2+3\right)+\frac{1}{4}\left(1+2+3+4\right)+...+\frac{1}{200}\left(1+2+3+...+200\right)\)
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Tính:
\(E=1+\frac{1}{2}\left(1+2\right)+\frac{1}{3}\left(1+2+3\right)+\frac{1}{4}\left(1+2+3+4\right)+...+\frac{1}{200}\left(1+2+3+...+200\right)\)