Tìm x :

x + 100 = 60 x 2

x + 100 = 120

x          = 120 - 100

x          = 20

Vậy x = 20

x+100=60x2

x+100=120

x=120-100

x=100

tk mk nha

 x + 100 = 60 x 2

x + 100 = 120

x           = 120 - 100

x           = 20

Vậy x = 20

k mình nhé Yến Nhi Libra Virgo HotGirl Sakura

a) x +60+40 =400

   x             = 400-40-60

   x             =300

b) (x+25) + 50 = 100:2 +30

(x+25) +50     = 50+30=80

x+25             = 80-50=30

x                   =30-25

x                  = 5

a.x+60+40=200

x+100=200

x=200-100

x=100

b.x+25+50=100:2+30

x+75=50+30

x+75=80

x=80-75

x=5

mk nhanh nhất

a) x + 100 = 200

    x           = 200 - 100

    x           = 100

b) x + 25 + 50 = 50 + 30

    x + 75          = 80

    x                  = 80 - 75

    x                  = 5

a) x + 100 = 50 + 60

x + 100 = 110

x = 110 - 100

x = 10

b) x + 50 = 30 + 60

x + 50 = 90

x = 90 - 50

x = 40

_______________________________________________THE END_____________________________________________________

a)=10

b)40 

tk m nhé

A)

x+100=50+60

x+100=110

x=110-100

x=10

B)

x+50=30+60

x+50=90

x=90-50

x=40

x+60=100

x=100-60

x=40

x + 60 = 100

x = 100 - 60

x = 40

=100-60

=40

TL :

5 + ( 75-x ) + ( 60 - x ) + x = 100

5 + 75 - x + 60 - x + x = 100

( 5 + 75 + 60 ) + ( x - x - x) = 100

140 - x = 100

x = 140 - 100

x = 40

Hok tốt ạ :33

a, Thay \(x=\frac{7}{13}\)vào \(x+y=40\)=> \(\frac{7}{13}+y=40\Rightarrow y=40-\frac{7}{13}\Rightarrow y=\frac{513}{13}\)

b, Ta có: \(13x=7y\Rightarrow\frac{x}{7}=\frac{y}{13}\)và x+y=-60. Áp dụng tính chất dãy tỉ số bằng nhau ta có:

\(\frac{x}{7}=\frac{y}{13}=\frac{x+y}{7+13}=\frac{-60}{20}=-3\) \(\Rightarrow\hept{\begin{cases}\frac{x}{7}=-3\Rightarrow x=-3\cdot7=-21\\\frac{y}{13}=-3\Rightarrow y=-3\cdot13=-39\end{cases}}\)

a.  -12 (x-5) +7(3-x) = -12x+60+21-7x=-19x+81=15

=> -19x=15-81=-66

=> x=66/19

b. 30(x+2) - 5 (x-5) - 24x = 30x+60-5x+25-24x =(30x-5x-24x)+(60+25)=x+85=100

=> x=100-85=15

c. ( 30x + 60 ) - ( 6x - 30 ) - 24x = 100

=30x+60-6x+30-24x

=90=100 (cô lý)

Vậy không có x thỏa mãn