\(a,0,5x-\frac{2}{3}x=\frac{7}{12}\Rightarrow\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)

\(\Rightarrow x\left(\frac{1}{2}-\frac{2}{3}\right)=\frac{7}{12}\Rightarrow x\cdot\left(\frac{3}{6}-\frac{4}{6}\right)=\frac{7}{12}\)

\(\Rightarrow x\cdot\left(-1\right)=\frac{7}{12}\Rightarrow x=\frac{7}{12}:\left(-1\right)=\frac{7}{-12}\)

\(c,\frac{\left(x-5\right)}{12}\cdot\frac{9}{29}=\frac{-6}{29}\Rightarrow\frac{\left(x-5\right)}{12}=\frac{-6}{29}:\frac{9}{26}\)

\(\frac{\Rightarrow\left(x-5\right)}{12}=\frac{-6}{9}=\frac{-2}{3}\Rightarrow x-5=-\frac{2}{3}\cdot12\)

\(\Rightarrow x-5=\frac{-24}{3}=-8\Rightarrow x=-8+5=-3\)

\(a,0,5x-\frac{2}{3}x=\frac{7}{12}\)

\(\Rightarrow\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)

\(\Rightarrow-\frac{1}{6}x=\frac{7}{12}\)

\(\Rightarrow x=-\frac{7}{2}\)

\(c,\frac{x-5}{12}\cdot\frac{9}{29}=-\frac{6}{29}\)

\(\Rightarrow\frac{x-5}{12}=-\frac{2}{3}\)

\(\Rightarrow x-5=12.\left(-\frac{2}{3}\right)\)

\(\Rightarrow x-5=-8\)

\(\Rightarrow x=-3\)

b)\(\frac{-8}{17}+\frac{5}{17}< \frac{x}{17}< \frac{-6}{17}+\frac{9}{17}\)\(\left(x\in Z\right)\)

\(\Rightarrow\frac{-3}{17}< \frac{x}{17}< \frac{3}{17}\)

\(\Rightarrow-3< x< 3\)

\(\Rightarrow x\in\left\{-2;-1;0;1;2\right\}\)

Vậy \(x\in\left\{-2;-1;0;1;2\right\}\)

3x + 17 = 12

3x = 12 - 17

3x = -5

x = (-5).3

x = -15

3x + 17 = 12

3x         = 12 - 17

3x         = -5

  x         = -5 : 3

  x         = -1.66666667

3x=12-17

3x=-5

x=(-5).3

x=-15

\(\left(x-3\right)\left(x^2+3x+9\right)-\left(3x-17\right)=x^3-12\)

\(\Leftrightarrow x^3-27-3x+17=x^3-12\)

\(\Leftrightarrow-10-3x=-12\)

\(\Leftrightarrow3x=2\)

\(\Leftrightarrow x=\dfrac{2}{3}\)

Vậy...

\((x-3)(x^2+3x+9)-(3x-17)=x^3-12 \)

\(pt\Leftrightarrow x^3-27-3x+17=x^3-12\)

\(\Leftrightarrow x^3-3x-10-x^3+12=0\)

\(\Leftrightarrow2-3x=0\)\(\Leftrightarrow x=\dfrac{2}{3}\)

3x + 17 = 12

         3x = 12 - 17

          3x = -5

           x = -5/3

k cho tows nha

-1,(6) nha bạn hoặc là-5/3 nhé

3x + 17 = 12 
        3x = 12 - 17

        3x = -5

    => x = 1,6

|3x + 1| - 17 = -12

=> |3x + 1| = -12 + 17

=> |3x + 1| = 5

=> 3x + 1 = 5 hoặc 3x + 1 = -5

=> 3x = 4 hoặc 3x = -6

=> x = 3/4 hoặc x = -2

vậy___

3x+1=-12 hoac 3x+1=12

3x=-12-1           3x=12-1

3x=-13              3x=11

x=-13:3             x=11:3

x=-13/3              x=11/3

vay x=-13/3 hoac 11/3

tk cho mk nha

\(|3x+1|-17=-12\)

\(\Rightarrow|3x+1|=5\)

\(\Rightarrow\orbr{\begin{cases}3x+1=5\\3x+1=-5\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}3x=4\\3x=-6\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{4}{3}\\x=-2\end{cases}}}\)

\(\left|3x+1\right|-17=-12\)

\(\Rightarrow\left|3x+1\right|=-12+17=5\)

\(\Rightarrow\orbr{\begin{cases}3x+1=5\\3x+1=-5\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}3x=4\\3x=-6\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{4}{3}\\x=-2\end{cases}}\)

Ta có :

\(|3x+1|-17=-12\)

\(\Rightarrow|3x+1|=\left(-12\right)+17\)

\(\Rightarrow|3x+1|=5\)

\(\Rightarrow\orbr{\begin{cases}3x+1=5\\3x+1=-5\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}3x=4\\3x=-6\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=4:3\\x=\left(-6\right):3\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=\frac{4}{3}\\x=-2\end{cases}}\)

Vậy x có 2  giá trị là \(\frac{4}{3};-2\)

Chúc bạn học tốt !

Tìm số nguyên x, biết:
1) -16 + 23 + x = - 16

7+x=-16

    x=-16-7

    x=-23
2) 2x – 35 = 15

2x=15+35

2x=50

  x=50:2

  x=25
3) 3x + 17 = 12

3x=12-17

3x=-5

  x=-5/3
4) (2x – 5) + 17 = 6

2x-5=6-17

2x-5=-11

2x=-11+5

2x=-6

  x=-6:2

  x=-3
5) 10 – 2(4 – 3x) = -4

2(4-3x)=10-(-4)

2(4-3x)=14

4-3x=14:2

4-3x=7

3x=4-7

3x=-3

  x=-3:3

  x=-1
6) - 12 + 3(-x + 7) = -18

3(-x+7)=-18-(-12)

3(x+7)=-6

x+7=-6:3

x+7=-2

    x=-2-7

    x=-9

tự đi mà làm

\(\left(x-3\right)\left(x^2+3x+9\right)-\left(3x-17\right)=x^3-12\)

\(\Rightarrow x\left(x^2+3x+9\right)-3\left(x^2+3x+9\right)-3x+17=x^3-12\)

\(\Rightarrow x^3+3x^2+9x-3x^2-9x-27-3x+17=x^3-12\)

\(\Rightarrow x^3+\left(3x^2-3x^2\right)+\left(9x-9x\right)-3x-10=x^3+12\)

\(\Rightarrow x^3-3x-10=x^3+12\)

\(\Rightarrow x^3-3x-10-12=x^3\)

\(\Rightarrow x^3-3x-22=x^3\)

\(\Rightarrow3x-22=0\)

\(\Rightarrow3x=22\Rightarrow x=\dfrac{22}{3}\)