42 -(2x + 32) + 12 :2 =6

42 - 2x - 32 + 6 = 6

42 - 2x - 32 = 0

42 - 2x = 32

2x = 42 - 32 = 10

x = 5

134 - 2 . {156 - 6.[54 -2.(9+6) ] } x = 86

134 - 2.{ 156 - 6.[54 - 2 . 15 ]} x = 86

134 - 2.{ 156 - 6 . 24} x = 86

134 - 2. 12 .x = 86

134 - 24x = 86

24x = 48

x = 2 

\(42-\left(2x+32\right)+12:2=6\)

\(\Rightarrow42-2x-32=0\)

\(\Rightarrow2x=10\)

\(\Rightarrow x=5\)

\(5.\left[225-\left(x-10\right)-125\right]=0\)

\(225-\left(x-10\right)-125=0:5\)

\(225-\left(x-10\right)-125=0\)

\(\left(x-10\right)-125=225-0\)

\(\left(x-10\right)-125=225\)

\(x-10=225+125\)

\(x-10=350\)

Mấy bài này làm theo thứ tứ trái sang phải, nhân chia trc cộng trừ sau thoi mà :>>>?

Quên, thứ tự ngoặc là { [ ( ) ] } nha :))))))))))))))))

a/ 720 : (x - 7) = 12

=> x - 7 = 720 : 12

=> x - 7 = 60

=> x = 60 + 7

=> x = 67

b/ 26 + 8x = 6x + 46

=> 26 + 6x + 2x = 6x + 46

=> 26 + 2x = 46

=> 2x = 46 - 26

=> 2x = 20

=> x = 20 : 2

=> x = 2

c/ 42 - (2x + 32) + 12 : 2 = 6

=> 42 - (2x + 32) + 6 = 6

=> 42 - (2x + 32) = 6 - 6

=> 42 - (2x + 32) = 0

=> 2x + 32 = 0 + 42

=> 2x + 32 = 42

=> 2x = 42 - 32

=> 2x = 10

=> x = 10 : 2

=> x = 5

1 + 2 + 3 + .... + x = 378

=> (1 + x) . x : 2 = 378

=> (1 + x) . x = 378 . 2

=> (1 + x) . x = 756

Ta thấy x và x + 1 là 2 số tự nhiên liên tiếp mà 756 = 27 . 28

=> x = 27

câu b là 10 mà

a)(x-5):5+22=24

    (x-5):5=2

    (x-5)=10

    x=15

b)42-(2x+32)+12:2=6

   42-(2x+32)+6=6

   42-(2x+32)=0

         (2x+32)=42

          2x=10

         x=5

a, (x-5):5+22=24                                    b, 42-(2x+32)+12:2=6

(x-5):5=2                                                42-(2x+32)=0

x-5=10                                                   2x+32=42

x=15                                                      x=5

d, (2x+35)-60=121                   câu c không có vế để tính

  2x+35=181

  2x=146

  x=73

5+2.x=1055

a,\(\left(x-15\right):50+22=24\)

\(< =>\frac{\left(x-15\right)}{50}=2< =>x-15=100\)

\(< =>x=100+15=115\)

b,\(42-\left(2x+32\right)+12:2=6\)

\(< =>42-2x-32=0\)

\(< =>10-2x=0< =>x=\frac{10}{2}=5\)

Làm nốt :

c) \(134-2\left\{156-6\cdot\left[54-2\cdot\left(9+6\right)\right]\right\}\cdot x=86\)

=> 134 - 2{156 - 6 . [54 - 2 . 15]} . x = 86

=> 134 - 2{156 - 6 . [54 - 30]} . x = 86

=> 134 - 2{156 - 6. 24} . x = 86

=> 134 - 2{156 - 144} . x = 86

=> 134 - 2.12 . x = 86

=> 134 - 24 . x = 86

=> 24.x = 48

=> x = 2

Bài 2 : a) 120 : [21 - (4x - 4)] = 2³.3

=> 120 : [21 - (4x - 4)] = 8.3

=> 120 : [21 - (4x - 4)] = 24

=> 21 - (4x - 4) = 5

=> 4x - 4 = 16

=> 4x = 20

=> x = 5

b) 3.[205 - (x - 9)] - 486 = 0

=> 3.[205 - (x - 9)] = 486

=> 205 - (x - 9) = 162

=> x - 9 = 205 - 162 = 43

=> x = 43 + 9 = 52

c) 204 - 2{200 - 5.[64 - 2.(11 + 6)]} . x = 4

=> 204 - 2{200 - 5.[64 - 2.17]} . x = 4

=> 204 - 2{200 - 5 .[64 - 34]}.x = 4

=> 204 - 2{200 - 5.30} . x = 4

=> 204 - 2{200 - 150}.x = 4

=> 204 - 2.50 . x = 4

=> 2.50.x = 200

=> 100.x = 200

=> x = 2

C1: \(\left(x-1\right)^2=5^4=625\)

\(\Rightarrow\left[{}\begin{matrix}x-1=25\\x-1=-25\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=26\\x=-24\end{matrix}\right.\) => Chọn C

C2: \(\left(4x^2-9\right)\left(2^{x-1}-1\right)=0\)

\(\Rightarrow\left(2x-3\right)\left(2x+3\right)\left(2^{x-1}-1\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{3}{2}\\x-1=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{3}{2}\\x=1\end{matrix}\right.\) => Chọn A

C3: \(3^x=9^3.27^5\)

\(\Rightarrow3^x=3^6.3^{15}=3^{21}\Rightarrow x=21\) => Chọn B

\(7\left(x-9\right)=35\Leftrightarrow x-9=5\Leftrightarrow x=14\)

Câu 2:  \(2^x=2^2\cdot2\Leftrightarrow2^x=2^3\Leftrightarrow x=3\)

Câu 3: \(2\cdot3^{x-1}=54\Leftrightarrow3^{x-1}=27\Leftrightarrow3^{x-1}=3^3\Leftrightarrow x-1=3\Leftrightarrow x=4\)

Câu 4: \(42-\left(2x+32\right)+12:2=6\)

      \(\Leftrightarrow42-2x-32+6=6\)

      \(\Leftrightarrow-2x=6-6+32-42=-10\)

      \(\Leftrightarrow x=5\)

Cau 1: 7.(x-9)=35

x-9=35:7

x-9=5

x=5+9

x=14

Cau2: 2:2^x=2^2.2

2:2^x=8

2^x=8.2

2^x=16

=> x=4

Cau 3: 2.3^x-1=54

3^x-1=54:2

3^x-1=27

3^x-1=3^3

=> x-1=3

x=3+1

x=4

Cau4: 42-(2x+32)+12:2=6

(2x+32)+6=42-6

(2x+32)+6=36

2x+32=36-6

2x+32=30

2x=30-32

2x=-2

x=-2:2

x=-1