-64.(-0,5)^7
64 : 0,5 + 64 : 0,25 + 64 x 4
64:0,5 + 64:0,25 + 64\(\times4\)
= 64 \(\times\) 2 + 64 \(\times\) 4 + 64 \(\times\) 4
= 64 \(\times\) ( 2 + 4 + 4)
= 64 \(\times\) 10
= 640
tính nhanh
8,64 x 93 + 8,64 : 0,5 + 8, 64 : 0,25 + 8, 64
\(8,64\times93+8,64:0,5+8,64:0,25+8,64\)
\(=8,64\times93+8,64\times2+8,64\times4+8,64\times1\)
\(=8,64\times\left(92+4+2+1\right)\)
\(=8,64\times100\)
\(=864\)
8,64×93+8,64:0,5+8,64:0,25+8,648
=8,64×93+8,64×2+8,64×4+8,64×1
=8,64×(92+4+2+1)
=8,64×100
=864
giúp mh với mh đang cần gấp
hứa mh sẽ tích
[(0,5)^3]^x=1/64
\(\left[\left(0,5\right)^3\right]^x=\dfrac{1}{64}\\ \Leftrightarrow\left[\left(\dfrac{1}{2}\right)^3\right]^x=\dfrac{1}{64}\\ \Leftrightarrow\left(\dfrac{1}{8}\right)^x=\dfrac{1}{64}=\left(\dfrac{1}{8}\right)^2\\ Vậy:x=2\\ \rightarrow S=\left\{2\right\}\)
Ta có: \(\left[\left(-0.5\right)^3\right]^x=\dfrac{1}{64}\)
\(\Leftrightarrow\left(-\dfrac{1}{2}\right)^{3x}=\dfrac{1}{64}\)
\(\Leftrightarrow3x=6\)
hay x=2
[(-0,5)^3]^8=1/64
Ta có: \(\left[\left(-0.5\right)^3\right]^x=\dfrac{1}{64}\)
\(\Leftrightarrow\left(-\dfrac{1}{2}\right)^{3x}=\dfrac{1}{64}\)
\(\Leftrightarrow3x=6\)
hay x=2
[(-0,5)^3]^x=1/64
\(\left[\left(-0,5\right)^3\right]^x=\dfrac{1}{64}\)
\(\Rightarrow\left(-\dfrac{1}{8}\right)^x=\left(-\dfrac{1}{8}\right)^2\)
\(\Rightarrow x=2\)
Ta có: \(\left[\left(-0.5\right)^3\right]^x=\dfrac{1}{64}\)
\(\Leftrightarrow\left(\dfrac{1}{2}\right)^{3x}=\dfrac{1}{64}\)
\(\Leftrightarrow3x=6\)
hay x=2
9:0,5 - 64 : 0,4 + 80
a) 92 : 0,01 = …………. 92 x 100 = ……… 64 : 0,01=………..
b) 25 : 0,5 =………….. 25 x 2 =…………. 39 : 0,5 = ………..
c) 32 : 0,25 =……..….. 32 x 4 =…………. 15 : 0,25 = ………
a) 92 : 0,01 = 9200 92 x 100 = 9200 64 : 0,01= 6400
b) 25 : 0,5 = 50 25 x 2 = 50 39 : 0,5 = 78
c) 32 : 0,25 = 128 32 x 4 = 128 15 : 0,25 = 60
a)92 : 0,01 = 9200 92 x 100 = 9200 64 : 0,01 = 6400
b)25 : 0,5 = 50 25 x 2 = 50 39 : 0,5 = 78
c)32 : 0,25 = 128 32 x 4 = 128 15 x 0,25 = 60
điền dấu > , < , =
6m 4dm ........ 64 dm
512 m .......... 0,5 km
2 tạ 51 kg ........ 25 ,1 yến
7 km2 51 m2 ............. 751 m2
giúp nha ! mình đang cần gấp
6m 4dm = 64dm
512m > 0,5 km
2 tạ 51kg = 25,1 yến
7km2 51m2 > 751m2
[(-0,5)^3]^x = 1 phần 64
Các bạn làm giúp mình đi, ngày mai phải nộp r :(((
[(-0.5)3]x = \(\frac{1}{64}\)
<=> \(\left(-\frac{1}{8}\right)^x\)= \(\left(-\frac{1}{8}\right)^2\)
<=> x = 2
\(\left[-\frac{1}{8}\right]^x=\frac{1}{64}\)
\(\frac{-1^x}{8^x}=\frac{1}{8^2}\)
\(\Rightarrow x=2\)
Vậy,........
Ta có \(\left[\left(-0,5\right)^3\right]^x=\frac{1}{64}\)
\(\Rightarrow\left(\left(\frac{-1}{2}\right)^3\right)^x=\frac{1}{64}\)
\(\Rightarrow\left(-\frac{1}{8}\right)^x=\left(-\frac{1}{8}\right)^{-2}\)
\(\Rightarrow x=-2\)
\(\cdot a^2+b^2=2\left(8+ab\right)\)
⇔\(a^2+b^2=16+2ab\)
⇔\(\left(a-b\right)^2=16\)
mà a < b
⇒\(a-b=-4\)
\(\cdot P=a^2\left(a+1\right)-b^2\left(b-1\right)+ab-3ab\left(a-b+1\right)+64\)
\(=\left(a^3-b^3\right)+a^2+b^2+ab-3ab\left(-3\right)+64\)
\(=\left(a-b\right)\left(a^2+ab+b^2\right)+a^2+b^2+10ab+64\)
\(=-4a^2-4ab-4b^2+a^2+b^2+10ab+64\)
\(=-3a^2-3b^2+6ab+64\)
\(=-3\left(a^2-ab+b^2\right)+64\)
\(=-3\left(a-b\right)^2+64\)
\(=-48+64=16\)