a)

\(\frac{864\cdot48-432\cdot96}{864\cdot48\cdot432}=\frac{432\cdot2\cdot48-432\cdot96}{864\cdot48\cdot432}=\frac{432\cdot96-432\cdot96}{864\cdot48\cdot432}=\frac{0}{864\cdot48\cdot432}=0\)

Làm từng phần một nha =))

b)

\(\frac{16\cdot17-5}{16\cdot16+11}=\frac{16\cdot\left(16+1\right)-5}{16\cdot16+11}=\frac{16^2+16-5}{16^2+11}=\frac{16^2+11}{16^2+11}=1\)

@_@

câu khó quá mmk ko làm đc

ban vt sai dau bai roi phai la 

1/2+1/6+1/12+....+1/(x+1).x=2016/2017

1/1.2+1/2.3+1/3.4+.....+1/x.(x+1)=2016/2017

1-1/2+1/2-1/3+......+1/x-1/x+1=2016/2017

1-1/x+1=2016/2017

1/x+1=1-2016/2017

1/x+1=1/2017

=>x+1=2017

=>x=2016

b)

85/8:x+(-4)/17:x+15:51=4/11

85/8:x+(-4)/17:x=13/187

1413/136:x=13/187

x=15543/104

\(\frac{1}{3}\left(x-1\right)+\frac{2}{5}\left(x+1\right)=0\)

\(\frac{1}{3}x-\frac{1}{3}+\frac{2}{5}x+\frac{2}{5}=0\)

\(\frac{11}{15}x+\left(\frac{2}{5}-\frac{1}{3}\right)=0\)

\(\frac{11}{15}x+\frac{1}{15}=0\)

\(\frac{1}{15}\left(11x+1\right)=0\)

\(11x+1=0\)

\(\Rightarrow x=-\frac{1}{11}\)

Ta có \(\left(x+2\right)^{n+1}=\left(x+2\right)^{n+11}\)

\(\Rightarrow\left(x+2\right)^{n+1}-\left(x+2\right)^{n+11}=0\)

\(\Rightarrow\left(x+2\right)^{n+1}.\left[1-\left(x+2\right)^{10}\right]=0\)

\(\Rightarrow\left(x+2\right)^{n+1}=0\)hoặc \(1-\left(x+2\right)^{10}=0\)

Với \(\left(x+2\right)^{n+1}=0\Rightarrow x+2=0\Rightarrow x=-2\)

Với \(1-\left(x+2\right)^{10}=0\Rightarrow\left(x+2\right)^{10}=1\Rightarrow\orbr{\begin{cases}x+2=1\\x+2=-1\end{cases}\Rightarrow\orbr{\begin{cases}x=-1\\x=-3\end{cases}}}\)