Tim x,y biet: |x+1| - 2|2x-3|
a,tim x biet |x-2|+|3-2x|=2x+1
b,tim x,y thuoc Z biet xy+2x-y=5
c, tinh A=(1-1/15)(1-1/21)(1-1/28).....(1-1/210)
a, Tim x biet:/x-2/+/3-2x/=2x+1
b, Tim x,y thuoc Z biet:xy+2x-y=5
c, tim x,y,z, biet :2x=3y;4y=5zva 4x-3y+5z=7
Tim x,y,z biet:2(x-1)-3(2x+2)-4(2x+3)=16
2(x-1)-3(2x+2)-4(2x+3)=16
2x-2-6x+6-8x+12=16
(2x-6x-8x)-(2+6+12)=16
(-12).x-20=16
(-12).x=16+20=36
x=36:(-12)=-3
2(x-1)-3(2x+2)-4(2x+3)=16
2x-2-6x-6-8x-12=16
2x-6x-8x=16+2+6+12
-12x=36
x=-3
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Tim x,y,z biet:2(x-1)-3(2x+2)-4(2x+3)=16
giai day du
2(x-1)-3(2x+2)-4(2x+3)=16
\(\Rightarrow\)2x-2-6x-6-8x-12=16
\(\Rightarrow\)(2x-6x-8x)-(2+6+12)=16
\(\Rightarrow\)-12x-20=16
\(\Rightarrow\)-12x=16+20
\(\Rightarrow\)-12x=36
\(\Rightarrow\)x = 36 :(-12)
\(\Rightarrow\)x= -3 . tick nha
tim 2 so tu nhien x va y biet (2x+1)x(y-3)=10
tim x biet x-y=xy-1
cm x^3 -x^2 -2x^2 +2x chia het cho 6
Tim so nguyen x,y biet
(x+1)^2+(y-1)^2=0
(x+3)×(y+1)=3
xy-2x=5
(x+3).(y+1)=3
--->x+3,y+1 thuộc Ư(3)={1,3,-1,-3}
Ta có bảng sau
x+3 1 -1
y+1 3 -3
y 2 -4
x -2 -4
--->(x,y) thuộc(-2,2),(-4,-4)
Tim x+y+z = ? biet (x-1) /2= (y-2) /3 = (z-3) /4 va 2x+3y-z=95
Áp dụng tính chất dãy tỉ số bằng nhau , ta có:
x-1/2 = y-2/3 = z-3/4 = 2x-2+3y-6-z+3/4+9-4 = 2x+3y-z + (-5)/9 = 90/9 = 10
x-1/2 = 10 => x= 21
y-2/3 = 10 => y = 32
z-3/4 = 10 => x = 43
Vậy x + y + z= 21 + 32 + 43 = 96
tim x;y biet
x-y=xy-1
cho x thuoc tap so nguyen biet
x^3 -x^2 -2x^2 +2x chia het cho 6