\(\left[0,\left(37\right)+0,\left(7\right)\right]x=0,1\left(6\right)\)

\(\Rightarrow\left[\frac{37}{99}+\frac{7}{9}\right]x=0,1+0,0\left(6\right)\)

\(\Rightarrow\frac{38}{33}.x=\frac{1}{10}+\frac{6}{90}\)

\(\Rightarrow\frac{38}{33}.x=\frac{1}{6}\)

\(\Rightarrow x=\frac{1}{6}:\frac{38}{33}=\frac{1}{6}.\frac{33}{38}\)

\(\Rightarrow x=\frac{11}{76}\)

Vậy \(x=\frac{11}{76}\)

Ta có:[\(\frac{37}{99}\)+\(\frac{7}{9}\)]x=\(\frac{1}{6}\)

x=\(\frac{38}{33}\).x=\(\frac{1}{6}\)

x=\(\frac{1}{6}\):\(\frac{38}{33}\)

=>    x=\(\frac{11}{76}\)

0,(37)=37/99

0,(62)=62/99

=>0,(37)+0,(62)=37/99+62/99=99/99=1

=>1.x=10

=>x=10

\(\left(\frac{37}{99}+\frac{62}{99}\right).x=10\)

\(\frac{99}{99}.x=10\Rightarrow x=10\)

Đáp án cần chọn là: B