tim x biet /3x+1/+/4-x/=3
Tim x biet: (3/4x+5)-(2/3x-4)-(1/6x+1)=(1/3+4)-(1/3x-3)
\(\left(\dfrac{3x}{4}+5\right)-\left(\dfrac{2x}{3}-4\right)-\left(\dfrac{x}{6}+1\right)=\left(\dfrac{1}{3}+4\right)-\left(\dfrac{1}{3}x-3\right)\)
\(\Leftrightarrow\dfrac{3x}{4}-\dfrac{2x}{3}-\dfrac{x}{6}+5+4-1=\dfrac{13}{3}-\dfrac{1}{3}x+9\)
\(\Leftrightarrow\dfrac{9x-8x-2x}{12}+8=\dfrac{13-x}{3}+\dfrac{27}{3}\)
\(\Leftrightarrow\dfrac{-x}{12}+\dfrac{96}{12}=\dfrac{40-x}{3}\Leftrightarrow\dfrac{96-x}{12}=\dfrac{160-4x}{12}\)
\(\Rightarrow96-160=-4x+x\Leftrightarrow-64=-3x\Leftrightarrow x=\dfrac{64}{3}\)
tim x biet
|x+1|+|3x+2|=3x
|x-2|+4|x+1|=x-3
Tim x biet:
(3/4x + 5) - (2/3x - 4) - (1/6x + 1) = (1/3x + 4) - (1/3x - 3)
3/4x + 5-(2/3x-4)-(1/6+1)=(1/3x+4)-(1/3x-3)
=3/4x+5-2/3x-4-1/6x+1=1/3x+4-1/3x-3
=-1/12=7
x=84
Đ/S...
tim x biet;(2x-1)(3x+1)+(3x-4)(3-2x)=5
ta co (2x-1)(3x+1)+(3x+4)(3-2x)=5
(=)6x2-3x+2x-1+6x-6x2+12-8x=5
(=)-4x+11=5
(=)-4x=-6
(=)x=3/2
(2x-1)(3x+1)+(3x-4)(3-2x)=5
<=> 6x2+2x-3x-1+9x-6x2-12+8x=5
<=> 16x-13=5
<=> 16x = 18
<=> x=9/8
tim a b biet x ^4-3x +2=(x-1)(x^3+ax^2+bx-2)
tim x biet
1/4+1/3:3x=-5
\(\frac{1}{4}+\frac{1}{3}:3x=-5\)
\(\Rightarrow\frac{1}{9x}=\frac{-21}{4}\)
\(\Rightarrow-189x=4\)
\(\Rightarrow x=-\frac{4}{189}\)
1/4 + 1/3 :3x= -5
=> 1/3 : 3x= (-5) - 1/4 = -21/4
=> 3x = -4/63
=> x = -4/189
nhớ cho mk nha
\(\frac{1}{4}+\frac{1}{3}:3x=-5\)
\(=\frac{1}{4}+\frac{1}{\frac{3}{3}}x=-5\)
\(=\frac{1}{4}+\frac{1}{9}x=-5\)
\(=\frac{1}{9}x=\left(-5\right)-\frac{1}{4}\)
\(=\frac{1}{9}x=-\frac{21}{4}\)
\(=x=9.\left(-\frac{21}{4}\right)\)
\(=x=-\frac{189}{4}\)
\(\Rightarrow x=-\frac{189}{4}\)
tim x , biet :
1 ) 2017 - \ x - 2017 \ = x
2) -1/2 . ( 3x - 1 ) + 3/4 . ( 3-2x) = -3 . ( x/2 - 1 ) - ( 4/5) mu -1
Tim x , biet : \(A,[3x - 4] = x ; B, [5x -3] = 2x + 1\)
bai1.tim x biet:
a,(x+2).(x+3)-(x-2).(x+5)=0
b,(2x+3).(x-4)+(x-5).(x-2)=(3x-5).(x-4)
c,(8x-3).(3x+2)-(4x+7).(x+4)=(2x+1).(5x-1)=33
,(8x-3).(3x+2)-(4x+7).(x+4)=(2x+1).(5x-1)-33 đúng không bạn