Tìm x biet x*(6-x)^2016=(x-6)^2016
tim x biet |x + 3| + 2|6 + 2x| + 2016 = 4016
\(\left|x+3\right|+2\left|6+2x\right|+2016=4016\)
\(\left|x+3\right|+2\left|6+2x\right|=4016-2016\)
\(\left|x+3\right|+2\times2\left|3+x\right|=2000\)
\(1\left|x+3\right|+4\left|x+3\right|=2000\)
\(\left|x+3\right|\left(1+4\right)=2000\)
\(5\left|x+3\right|=2000\)
\(\left|x+3\right|=2000:5\)
\(\left|x+3\right|=400\)
Vậy x=-403 hoặc 397
3+6+9+.......+x
biet x la so hang thu 2016
Câu1: tìm số nguyên x mà -35/6<x>-18/5
Câu2 : so sánh A=2015/2016+2016/2017 và B= 2015+2016/2016+2017
Câu3 : tìm số nguyên x biết rằng : 1/3+1/6+1/10...+2/x(x+1) =2007/2009
câu 1. tìm x nguyên để \(\frac{-35}{6}\)<x<\(\frac{-18}{5}\)
<=> -4,375<x<-3,6
mà x\(\in\)Z nên x={-4}
câu 2. A=\(\frac{2015}{2016}\)+\(\frac{2016}{2017}\)
B=\(\frac{2015+2016}{2016+2017}\)=\(\frac{2015}{2016+2017}\)+\(\frac{2016}{2016+2017}\)
Vì \(\frac{2015}{2016+2017}\)<\(\frac{2015}{2016}\); \(\frac{2016}{2016+2017}\)<\(\frac{2016}{2017}\)
Vậy B<A
cau3:
\(\frac{1}{3}\)+\(\frac{1}{6}\)+\(\frac{1}{10}\)+.....+\(\frac{2}{x\left(x+1\right)}\)=\(\frac{2007}{2009}\)
2.(\(\frac{1}{6}\)+\(\frac{1}{12}\)+\(\frac{1}{20}\)+.....+\(\frac{1}{x\left(x+1\right)}\))=\(\frac{2007}{2009}\)
2.(\(\frac{1}{2.3}\)+\(\frac{1}{3.4}\)+\(\frac{1}{4.5}\)+.....+\(\frac{1}{x\left(x+1\right)}\))=\(\frac{2007}{2009}\)
2.(\(\frac{1}{2}\)-\(\frac{1}{3}\)+\(\frac{1}{3}\)-\(\frac{1}{4}\)+\(\frac{1}{4}\)-\(\frac{1}{5}\)+.....+\(\frac{1}{x}\)-\(\frac{1}{x+1}\))=\(\frac{2007}{2009}\)
2.(\(\frac{1}{2}\)-\(\frac{1}{x+1}\))=\(\frac{2007}{2009}\)
\(\frac{1}{2}\)-\(\frac{1}{x+1}\)=\(\frac{2007}{4018}\)
\(\frac{1}{x+1}\)=\(\frac{1}{2}\)-\(\frac{2007}{4018}\)
\(\frac{1}{x+1}\)=\(\frac{1}{2009}\)
x+1=2009
x=2009-1
x=2008
Tính 2016 * 105 - 2016 * 4 - 2016=
Tìm x biết : x * 24 + x * 6 = 240
Tìm x biết : x -167 * 15 = 167 * 185
Tính 173* 105 + 173 * 96 - 173 =
\(2016\times105-2016\times4-2016\)
\(=2016\times\left(105-4-1\right)\)
\(=2016\times100\)
\(=201600\)
\(x\times24+x\times6=240\)
\(x\times\left(24+6\right)=240\)
\(x\times30=240\)
\(x=240:30\)
\(x=8\)
\(x-167\times15=167\times185\)
\(x-2505=30895\)
\(x=30895+2505\)
\(x=33400\)
\(173\times105+173\times96-173\)
\(=173\times\left(105+96-1\right)\)
\(=173\times200\)
\(=34600\)
1. 2016 x 105 - 2016 x 4 - 2016
= 211680 - 8064 - 2016
= 203616 - 2016
= 201600
2. X x 24 + X x 6 = 240
X x (24 + 6) = 240
X x 30 = 240
X = 240 : 30
X = 8
3. X - 167 x 15 = 167 x 185
X - 2505 = 30895
X = 30895 - 2505
X = 28390
4. 173 x 105 + 173 x 96 - 173
= 18165 + 16608 - 173
= 34773 - 173
= 34600
Tìm x, biết:
(20165:20164-1/2-20178:20176)-x/2016= 2017/2016.
tìm x:
a. (x - 2015)6 = ( x - 2015)4
b. (x - 2016)2014= (x - 2016)2015
Tìm x: 2016 - 3 . ( x - 6 ) = 1446
\(2016-3.\left(x-6\right)=1446\)
\(\Rightarrow3.\left(x-6\right)=2016-1446\)
\(\Rightarrow3.\left(x-6\right)=570\)
\(\Rightarrow x-6=570:3\)
\(\Rightarrow x-6=190\)
\(\Rightarrow x=190+6\)
\(\Rightarrow x=196\)
Vậy \(x=196\)
3 . (x-6)=2016-1446
3 . (x-6)=570
x-6=570 : 3
x-6=190
x=190+6
x=196
2016-3(x-6)=1446
3(x-6)=2016-1446
3(x-6)=570
x-6=570:3
x-6=190
x=190+6
x=196
vậy x=196
2016 x 6 + 2016 x 5
Tìm x, y biết
(x-y)6^2016+|x|+|y|=2