x>y

Mình chắc chắn đúng

K mình nha

x bé nhất = 2017

y lớn nhất = 2016

Vậy x > y

Mình cug k chắc đugs nhưng:

x > 2016 suy ra x từ 2017 trở lên

x < 2017 suy ra x từ 2017 trở xuống

Vậy x có thể bằng y hoặc lớn hơn y

\(A=2015\cdot2017=\left(2016-1\right)\left(2016+1\right)=2016^2-1< 2016\times2016.\)

ta có  2015 x 2017 >2017^2 -2 

 2016 x 2018 > 2016^2 

=> A> B

Ta có:

2016 x 2016

= (2015 + 1) x 2016

= 2015 x 2016 + 2016

2015 x 2017

= 2015 x (2016 + 1)

= 2015 x 2016 + 2015

Vì 2016 > 2015

=> 2016 x 2016 > 2015 x 2017

Thanks chị nha !!!!! <3 

Ta có:

2016 x 2016

= (2015 + 1) x 2016

= 2015 x 2016 + 2016

2015 x 2017

= 2015 x (2016 + 1)

= 2015 x 2016 + 2015

Vì 2016 > 2015

=> 2016 x 2016 > 2015 x 2017

Trả lời:

a) A = 2009 x 2011 và B = 2010²

Ta có: A = 2009 x ( 2010 + 1 )

              = 2009 x 2010 + 2009

           B = 2010² = 2010 x 2010 

              = ( 2009 + 1 ) x 2010

              =  2009 x 2010 + 2010

Ta thấy 2009 < 2010

Vậy A < B

         ~ Học tốt ~

Phần B bạn làm tương tự nha

Mk lười lắm ^^

 ~ Học tốt ~

Ta có :

\(x=\frac{2016^{2017}+1}{2016^{2016}+1}\)

\(\frac{1}{2016}x=\frac{2016^{2017}+1}{2016^{2017}+2016}=\frac{2016^{2017}+2016-2015}{2016^{2017}+2016}\)

\(\Rightarrow\frac{1}{2006}x=1-\frac{2015}{2016^{2017}+2016}\)

Ta lại có :

\(y=\frac{2016^{2016}+1}{2016^{2015}+1}\)

\(\Rightarrow\frac{1}{2016}y=\frac{2016^{2016}+1}{2016^{2016}+2016}=\frac{2016^{2016}+2016-2015}{2016^{2016}+2016}\)

\(\Rightarrow\frac{1}{2016}y=1-\frac{2015}{2016^{2016}+2016}\)

Mà \(\frac{2015}{2016^{2017}+2016}< \frac{2015}{2016^{2016}+2016}\)(so sánh mẫu)

\(\Rightarrow1-\frac{2015}{2016^{2017}+2016}>1-\frac{2015}{2016^{2016}+2016}\)

\(\Rightarrow\frac{1}{2016}x>\frac{1}{2016}y\)

\(\Rightarrow x>y\)

DÀI QUÁ KHÔNG TÍNH ĐƯỢC. CÁI NÀY CÓ MÀ ĐI HỎI THẦN ĐỒNG VỀ MÔN TOÁN ĐI

\(x< \frac{2016^{2017}+1+2015}{2016^{2016}+1+2015}\)

\(\Rightarrow x< \frac{2016^{2017}+2016}{2016^{2016}+2016}\)

\(\Rightarrow x< \frac{2016.\left(2016^{2016}+1\right)}{2016.\left(2016^{2015}+1\right)}\)

\(\Rightarrow x< y\)

. đi bạn

câu 1. tìm x nguyên để \(\frac{-35}{6}\)<x<\(\frac{-18}{5}\)

<=> -4,375<x<-3,6

mà x\(\in\)Z nên x={-4}

câu 2. A=\(\frac{2015}{2016}\)+\(\frac{2016}{2017}\)

B=\(\frac{2015+2016}{2016+2017}\)=\(\frac{2015}{2016+2017}\)+\(\frac{2016}{2016+2017}\)

Vì \(\frac{2015}{2016+2017}\)<\(\frac{2015}{2016}\); \(\frac{2016}{2016+2017}\)<\(\frac{2016}{2017}\)

Vậy B<A

cau3:

\(\frac{1}{3}\)+\(\frac{1}{6}\)+\(\frac{1}{10}\)+.....+\(\frac{2}{x\left(x+1\right)}\)=\(\frac{2007}{2009}\)

2.(\(\frac{1}{6}\)+\(\frac{1}{12}\)+\(\frac{1}{20}\)+.....+\(\frac{1}{x\left(x+1\right)}\))=\(\frac{2007}{2009}\)

2.(\(\frac{1}{2.3}\)+\(\frac{1}{3.4}\)+\(\frac{1}{4.5}\)+.....+\(\frac{1}{x\left(x+1\right)}\))=\(\frac{2007}{2009}\)

2.(\(\frac{1}{2}\)-\(\frac{1}{3}\)+\(\frac{1}{3}\)-\(\frac{1}{4}\)+\(\frac{1}{4}\)-\(\frac{1}{5}\)+.....+\(\frac{1}{x}\)-\(\frac{1}{x+1}\))=\(\frac{2007}{2009}\)

2.(\(\frac{1}{2}\)-\(\frac{1}{x+1}\))=\(\frac{2007}{2009}\)

\(\frac{1}{2}\)-\(\frac{1}{x+1}\)=\(\frac{2007}{4018}\)

\(\frac{1}{x+1}\)=\(\frac{1}{2}\)-\(\frac{2007}{4018}\)

\(\frac{1}{x+1}\)=\(\frac{1}{2009}\)

x+1=2009

x=2009-1

x=2008