Cho S=1/5+2/5^2+3/5^3+4/5^4+....+2015/5^2015 . Hãy so sánh S với 1/3
Những câu hỏi liên quan
cho A= 1/2 . 3/4. 5/6 .....2015/2016. hãy so sánh A2 với B = 1/2017
Cho A=3/1*2*3+3/2*3*4+3/3*4*5+.........+3/2015*2016*2017.
So sánh A với 1.
A=\(\dfrac{3}{1\cdot2\cdot3}+\dfrac{3}{2\cdot3\cdot4}+...+\dfrac{3}{2015\cdot2016\cdot2017}\)
Nhận xét:\(\dfrac{1}{\left(n-1\right)n}-\dfrac{1}{n\left(n+1\right)}=\dfrac{n+1-n+1}{\left(n-1\right)n\left(n+1\right)}=\dfrac{2}{\left(n-1\right)n\left(n+1\right)}\)
=>A=\(3\cdot\dfrac{1}{2}\cdot\left(\dfrac{1}{1\cdot2}-\dfrac{1}{2\cdot3}+\dfrac{1}{2\cdot3}-\dfrac{1}{3\cdot4}+...+\dfrac{1}{2015\cdot2016}-\dfrac{1}{2016\cdot2017}\right)=\dfrac{3}{2}\cdot\left(\dfrac{1}{2}-\dfrac{1}{2016\cdot2017}\right)=\dfrac{3}{4}-\dfrac{3}{2.2016.2017}< \dfrac{3}{4}< 1\)
Vậy A<1
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Cho S= 1/5+2/52+3/53+.....+2015/52015. so sanh voi 1/3
\(5S=1+\frac{2}{5}+\frac{3}{5^2}+...+\frac{2015}{5^{2014}}\Rightarrow4S=1+\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{2014}}-\frac{2015}{5^{2015}}\)
Đặt B = \(1+\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{2014}}\)
=> 5B = \(5+1+\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{2013}}\)
=> 4B = \(5-\frac{1}{5^{2014}}
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cho A=1*2*3+1/2*3*4+1/3*4*5+...+1/2014*2015*2016.so sánh A với 1/4
A=\(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{2014.2015.2016}\)
A=\(\frac{1}{2}\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{2014.2015}-\frac{1}{2015.2016}\right)\)
A=\(\frac{1}{2}\left(\frac{1}{2}-\frac{1}{2015.2016}\right)\)
A=\(\frac{1}{4}-\frac{1}{2015.2016.2}\)\(\Rightarrow A<\frac{1}{4}\)
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So sánh
\(\dfrac{1}{5^1}+\dfrac{1}{5^2}+\dfrac{1}{5^3}+....+\dfrac{1}{5^{2015}}\)
Với 1/4
\(A=\dfrac{1}{5^1}+\dfrac{1}{5^2}+\dfrac{1}{5^3}+...+\dfrac{1}{5^{2014}}+\dfrac{1}{5^{2015}}\\ 5A=1+\dfrac{1}{5^1}+\dfrac{1}{5^2}+\dfrac{1}{5^3}+...+\dfrac{1}{5^{2013}}+\dfrac{1}{5^{2014}}\\ 5A-A=\left(1+\dfrac{1}{5^1}+\dfrac{1}{5^2}+\dfrac{1}{5^3}+...+\dfrac{1}{5^{2013}}+\dfrac{1}{5^{2014}}\right)-\left(\dfrac{1}{5^1}+\dfrac{1}{5^2}+\dfrac{1}{5^3}+...+\dfrac{1}{5^{2014}}+\dfrac{1}{5^{2015}}\right)\\ 4A=1-\dfrac{1}{5^{2015}}\Rightarrow A=\dfrac{1-\dfrac{1}{5^{2015}}}{4}=\dfrac{1}{4}-\dfrac{4}{5^{2015}}< \dfrac{1}{4}\)
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1) cho S = 1+2+22+23+.........+220
so sánh S với 5.219
2)có 5 số tự nhiên nào mà tích chúng = 2015 và tổng có tận cùng =4 được không
1. so sánh: A=1+3+5+...+139/70và B= 2+4+6+...+138/69
2.cho A= 201520152015.....
hỏi A có ? c/s 2015
cho A=\(\dfrac{1}{5}+\dfrac{1}{5^2}+\dfrac{1}{5^3}+...+\dfrac{1}{5^{2014}}+\dfrac{1}{5^{2015}}\)
So sánh A với\(\dfrac{1}{4}\)
\(A=\dfrac{1}{5}+\dfrac{1}{5^2}+...+\dfrac{1}{5^{2015}}\)
\(\Rightarrow5A=1+\dfrac{1}{5}+...+\dfrac{1}{5^{2014}}\)
\(\Rightarrow5A-A=\left(1+\dfrac{1}{5}+...+\dfrac{1}{5^{2014}}\right)-\left(\dfrac{1}{5}+\dfrac{1}{5^2}+...+\dfrac{1}{5^{2015}}\right)\)
\(\Rightarrow4A=1-\dfrac{1}{5^{2015}}\)
\(\Rightarrow A=\dfrac{1}{4}-\dfrac{1}{5^{2015}.4}< \dfrac{1}{4}\)
\(\Rightarrowđpcm\)
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\(A=\dfrac{1}{5}+\dfrac{1}{5^2}+\dfrac{1}{5^3}+...+\dfrac{1}{5^{2014}}+\dfrac{1}{5^{2015}}\)
\(\Rightarrow5A=5\left(\dfrac{1}{5}+\dfrac{1}{5^2}+\dfrac{1}{5^3}+...+\dfrac{1}{5^{2014}}+\dfrac{1}{5^{2015}}\right)\)
\(\Rightarrow5A=1+\dfrac{1}{5}+\dfrac{1}{5^2}+...+\dfrac{1}{5^{2013}}+\dfrac{1}{5^{2014}}\)
\(\Rightarrow5A-A=\left(1+\dfrac{1}{5}+\dfrac{1}{5^2}+...+\dfrac{1}{5^{2013}}+\dfrac{1}{5^{2014}}\right)-\left(\dfrac{1}{5}+\dfrac{1}{5^2}+\dfrac{1}{5^3}+...+\dfrac{1}{5^{2014}}+\dfrac{1}{5^{2015}}\right)\)
\(\Rightarrow4A=1-\dfrac{1}{5^{2015}}\)
\(\Rightarrow A=\dfrac{1}{4}-\dfrac{1}{5^{2015}.4}\)
\(\Rightarrow A< \dfrac{1}{4}\)
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Cho S =1/5+2/5 mu 2 +3/5mu 3 +4/5 mu 4+....+2012/5 mu 2012
So sánh S với 1/3