\(\left(x-\frac{1}{2}\right)^2=0\)

\(\Leftrightarrow\left(x-\frac{1}{2}\right)^2=0^2\)

\(\Leftrightarrow x-\frac{1}{2}=0\)

\(\Leftrightarrow x=\frac{1}{2}\)

Vậy x = 1/2

\(\left(x-2\right)^2=1\)

\(\Leftrightarrow\left(x-2\right)^2=1^2\)

\(\Leftrightarrow x-2=1\)

\(\Leftrightarrow\orbr{\begin{cases}x-2=1\\x-2=-1\end{cases}\Leftrightarrow\orbr{\begin{cases}x=3\\x=1\end{cases}}}\)

Vậy x = 3 hoặc x = 1

\(\left(2x-1\right)^3=-8\)

\(\Leftrightarrow\left(2x-1\right)^3=\left(-2\right)^3\)

\(\Leftrightarrow2x-1=-2\)

<=> 2x = -1

<=> x = -0,5

Vậy x = -0,5

\(\left(x-\frac{1}{2}\right)^2=0\)

\(x-\frac{1}{2}=0\)

\(x=\frac{1}{2}\)

\(\left(x-2\right)^2=1\)

\(\Leftrightarrow\orbr{\begin{cases}x-2=1\\x-2=-1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=1+2\\x=-1+2\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=3\\x=1\end{cases}}\)

Vậy\(x\in\left\{3;1\right\}\)
\(\left(2x-1\right)^3=-8\)

\(\left(2x-1\right)^3=\left(-2\right)^3\)

\(2x-1=-2\)

\(2x=\left(-2\right)+1\)

\(2x=-1\)

\(x=-1\times2\)

\(x=-2\)

\(x\left(\frac{1}{2}\right)^2=\frac{1}{16}\)

\(x\left(\frac{1}{2}\right)^2=\left(\frac{1}{4}\right)^2\)

\(\Leftrightarrow\orbr{\begin{cases}x\frac{1}{2}=\frac{1}{4}\\x\frac{1}{2}=-\frac{1}{4}\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{4}:\frac{1}{2}\\x=-\frac{1}{4}:\frac{1}{2}\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{1}{2}\\x=-\frac{1}{2}\end{cases}}}\)

\(49\times7^x=2401\)

   \(7^x=2401:49\)

\(7^x=49\)

\(7^x=7^2\)

\(\Rightarrow x=2\)

\(2x^x-15=17\)

\(2x^x=17+15\)

\(2x^x=32\)

\(2x^x=2^5\)

\(\Rightarrow x\times x=5\)

\(\Rightarrow x^2=5\)

\(2^x+3\times2^x=32\)

\(2^x\times\left(3+1\right)=32\)

\(2^x\times4=32\)

\(2^x=32:4\)

\(2^x=8\)

\(2^x=2^3\)

\(\Rightarrow x=3\)

\(2x\left(x-\frac{1}{7}\right)=0\)

\(x\left(x-\frac{1}{7}\right)=0:2\)

\(x\left(x-\frac{1}{7}\right)=0\)

\(x\times x-x\times\frac{1}{7}=0\)

\(x^2-x\frac{1}{7}=0\)

\(x-x=0:\frac{1}{7}\)

\(x-x=0\)

\(\Rightarrow x=0\)

a, 6

b,1

c,1

a;2 mu x =2 mu 6 .Vậy x=6

7A=7^2+7^3+7^4+....+7^100

A=7+7^2+7^3+....+7^99

6A=7^100-7

khi đó ta có

tiếp 

7^100-7+7=7^2x

7^100=7^2x

100=2x

x=50

cảm ơn nha

a) (49⁵ . 7¹⁶) : (7¹⁸.7⁶)

=((7²)⁵.7¹⁶) :7²⁴

=(7¹⁰.7¹⁶) :7²⁴

=7²⁶ : 7²⁴=7²=49

b) (4¹⁶.8²⁰ ) : (2¹⁴.32¹⁵)

=((2²)¹⁶.(2³)²⁰) : (2¹⁴.(2⁵)¹⁵

=(2³².2⁶⁰) : (2¹⁴.2⁷⁵)

=2⁹² : 2⁸⁹=2³=8

tích mình đi

ai tích mình 

mình tích lại 

thanks

\(\frac{14^{16}\times21^{32}\times35^{48}}{10^{16}\times35^{32}\times7^{96}}\)

\(=\frac{\left(2\times7\right)^{16}\times\left(3\times7\right)^{32}\times\left(5\times7\right)^{48}}{\left(2\times5\right)^{16}\times\left(5\times7\right)^{32}\times7^{96}}\)

\(=\frac{2^{16}\times7^{16}\times3^{32}\times7^{32}\times5^{48}\times7^{48}}{2^{16}\times5^{16}\times5^{32}\times7^{32}\times7^{96}}=\frac{2^{16}+7^{96}+3^{32}+5^{48}}{2^{16}\times5^{48}\times7^{32}\times7^{96}}\)

\(=\frac{3^{32}}{7^{32}}=\left(\frac{3}{7}\right)^{32}\)

1. 2^x=16\(\Rightarrow\)X=4

2. 2^2x-1=2⁷

\(\Rightarrow\)2⁷=2^2.4-1

Vậy x =4

x=4 nha chị

\(\left(x-4\right)^9=49.\left(x-4\right)^7\\ =>\left(x-4\right)^9:\left(x-4\right)^7=49\\ =>\left(x-4\right)^2=49\\ =>\left[{}\begin{matrix}x-4=7\\x-4=-7\end{matrix}\right.\\ =>\left[{}\begin{matrix}x=11\\x=-3\end{matrix}\right.\)

              (x - 4)⁹ = 49 . (x - 4)⁷

(x - 4)⁹ : (x - 4)⁷ = 49

              (x - 4)² = 7² = (-7)²

TH1 :                                                    TH2 :

(x - 4)² = 7²                                          (x - 4)² = (-7)²

    x - 4 = 7                                                x - 4 = -7

         x = 7 + 4                                               x = -7 + 4

         x = 11                                                   x = -3

    Vậy x = 11                                          Vậy x = -3

B

B

B