92*4-27=[x+350]/x+315
92 . 4 - 27 = ( x + 350): x +315
92 x 4 - 27 = ( X+ 350 ) : X + 315
368-27=(X+350):X+315
341=(X+350):X+315
X:X+350:X=341-315
1+350:X=26
350:X=26-1
350:X=25
X=350:25
X=14
Bạn Nguyễn Hữu Thế làm đúng rùi đó! Mình cũng làm như vậy!
Tìm x
92*4-27=(x+350 /x)+315
\(92.4-27=\frac{x+350}{x}+135\)
=>\(368-27=\frac{x}{x}+\frac{350}{x}+315\)
=>\(341=1+\frac{350}{x}+315\)
=>\(341=\frac{350}{x}+316\)
=>\(341-316=\frac{350}{x}\)
=>\(\frac{350}{x}=25\)
=>x=350:25
=>x=14
tìm x
92 . 4 - 27 = ( x + 350 ) : x + 315
368-27=(x+350):x+315
341=(x+350):x+315
x:x+350:x=341-315
1+350:x=26
350:x=26-1
350:x=25
x=350:25
x=14
hk tốt
92 . 4 - 27 = (x+ 350 ) : x + 315
<=> 365 - 27 = (x + 350):x +315
<=> 341 = (x+350 : x +315
<=> (x + 350 ): x = 341 - 315
<=> (x + 350 ) : x = 26
<=>(x + 350 ) . 1/x=26
<=> x . 1/x + 350 . 1/x = 26
<=> 1 + 350/x =26
<=> 350/x = 26-1
<=> 350 : x = 25
<=> x = 350 : 25
<=> x = 14
vậy x = 14
tít cho mình trước nha
Tìm x biết :
92 × 4 -27 = ( x + 350 ) : x + 315
92 × 4 -27 = ( x + 350 ) : x + 315
hay \(\left(x+350\right):x+315=92\) x \(4-27\)
\(\left(x+350\right):x=368-27-315\)
\(\left(x+350\right):x=26\)
\(\frac{x+350}{x}=26\)
\(\frac{x}{x}+\frac{350}{x}=26\)
\(1+\frac{350}{x}=26\)
\(\frac{350}{x}=25\)
\(x=350:25\)
\(x=14\)
tìm x
a, 697 : 15 . x + 364 / x =17
b, 92 . 4 - 27 = x + 350 / x + 315
1500 : [ ( 30x + 40 ) : x ] = 30
92 x 4 - 27 = x + 350 :x + 315
697 : 15x + 364 : x = 17
92 . 4 - 27 = \(\dfrac{\text{a + 350 }}{a}\)+ 315
92X4-27=\(\dfrac{a+350}{a}\)+315
=>341=1+\(\dfrac{350}{a}\)+315=316+\(\dfrac{350}{a}\)
=>\(\dfrac{350}{a}\)=341-316=25
=>a=\(\dfrac{350}{25}\)=14
Tìm x, bt:
a) 92×4-27= x+350/x +315
b) ( 3/2 - x) ×1/3 -2/3× (1/2 - x) =1/3
~♥~♥~♥~
a) \(92.4-27=\frac{x+350}{x}+315\)
\(368-27=1+\frac{350}{x}+315\)
\(341=\frac{350}{x}+316\)
\(341-316=\frac{350}{x}\)
\(25=\frac{350}{x}\)
\(25x=350\)
\(x=14\)
b) \(\left(\frac{3}{2}-x\right).\frac{1}{3}-\frac{2}{3}.\left(\frac{1}{2}-x\right)=\frac{1}{3}\)
\(\frac{\frac{3}{2}}{3}-\frac{x}{3}-\frac{2}{3}.\left(\frac{1}{2}-x\right)=\frac{1}{3}\)
\(\frac{1}{2}-\frac{x}{2}-\frac{2}{3}.\left(\frac{1}{2}-x\right)=\frac{1}{3}\)
\(\frac{3}{2}-x-2.\left(\frac{1}{2}-x\right)=1\)
\(\frac{3}{2}-x-1+2x=1\)
\(\frac{1}{2}+x=1\)
\(x=1-\frac{1}{2}\)
\(x=\frac{1}{2}\)