ta co (x-2163)(1/2011+1/28+1/124)=0

vi 1/2011+1/28+1/124khac0

x-2163=0

x=2163

Đặt \(A=\dfrac{x-28-124}{2011}+\dfrac{x-124-2011}{28}+\dfrac{x-2011-28}{124}=3\)

\(\Rightarrow\dfrac{x-28-124}{2011}-1+\dfrac{x-124-2011}{28}-1+\dfrac{x-2011-28}{124}-1=3-1-1-1\)

\(\Rightarrow\dfrac{x-28-124}{2011}-\dfrac{2011}{2011}+\dfrac{x-124-2011}{28}-\dfrac{28}{28}+\dfrac{x-2011-28}{124}=0\)

\(\Rightarrow\dfrac{x-28-124-2011}{2011}+\dfrac{x-124-2011-28}{28}+\dfrac{x-2011-29-124}{124}=0\)

\(\Rightarrow x-28-124-2011\left(\dfrac{1}{2011}+\dfrac{1}{28}+\dfrac{1}{124}\right)=0\)

\(\Rightarrow x-28-124-2011=0\Rightarrow x=2163\)

Vậy x = 2163

Áp dụng tính chất của dãy tỉ số bằng nhau

Áp dụng tính chất của dãy tỉ số bằng nhau nha ^^^

\(\frac{x-28-124}{2011}+\frac{x-124-2011}{28}+\frac{x-2011-28}{124}\)\(=3\)

\(\Leftrightarrow\frac{x-152}{2011}+\frac{x-2135}{28}+\frac{x-2039}{124}=3\)\(\Leftrightarrow\left(\frac{x-152}{2011}-1\right)+\left(\frac{x-2135}{28}-1\right)+\left(\frac{x-2039}{124}-1\right)=3-1-1-1\)

\(\Leftrightarrow\frac{x-2163}{2011}+\frac{x-2163}{28}+\frac{x-2163}{124}=0\)

\(\Leftrightarrow\left(x-2163\right)\left(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\right)=0\)

        Vì \(\left(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\right)>0\)

  \(\Rightarrow x-2163=0\)

\(\Leftrightarrow x=2163\)

          Vậy \(x=2163\)

\(\frac{x-28-124}{2011}+\frac{x-124-2011}{28}+\frac{x-2011-28}{124}=3\)

<=> \(\left(\frac{x-152}{2011}-1\right)+\left(\frac{x-2135}{28}-1\right)+\left(\frac{x-2039}{124}-1\right)=0\)

<=> \(\frac{x-2163}{2011}+\frac{x-2163}{28}+\frac{x-2163}{124}=0\)

<=> \(\left(x-2163\right)\left(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\right)=0\)

<=> \(x-2163=0\)(vì \(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\ne0\)

<=> \(x=2163\)

\(\frac{x-28-124}{2011}+\frac{x-124-2011}{28}+\frac{x-2011-28}{124}=3\)

<=> \(\frac{x-28-124}{2011}+\frac{x-124-2011}{28}+\frac{x-2011-28}{124}-3=0\)

<=> \(\left(\frac{x-28-124}{2011}-1\right)+\left(\frac{x-124-2011}{28}-1\right)+\left(\frac{x-2011-28}{124}-1\right)=0\)

<=> \(\frac{x-28-124-2011}{2011}+\frac{x-124-2011-28}{28}+\frac{x-2011-28-124}{124}=0\)

<=> \(\frac{x-2163}{2011}+\frac{x-2163}{28}+\frac{x-2163}{124}=0\)

<=> \(\left(x-2163\right)\left(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\right)=0\)

Vì \(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\ne0\)

=> \(x-2163=0\)

=> \(x=2163\)

thanks!

Cảm ơn mọi người nhiều nhé!

a )

\(\Rightarrow\frac{x-100}{24}-1+\frac{x-98}{26}-1+\frac{x-96}{26}-1=0\)

\(\frac{x-124}{24}+\frac{x-124}{26}+\frac{x-124}{28}=0\)

\(\left(x-124\right)\left(\frac{1}{26}+\frac{1}{24}+\frac{1}{28}\right)=0\)

\(\Rightarrow x-124=0\Rightarrow x=124\)

b) 

\(\frac{x-28-124}{2011}-1+\frac{x-124-2011}{28}-1+\frac{x-2011-28}{124}-1=0\)

\(\Rightarrow\frac{x-2163}{2011}+\frac{x-2163}{28}+\frac{x-2163}{124}=0\)

\(\left(x-2163\right)\left(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\right)=0\)

=) x - 2163 =0

x= 2163