105 : [3+7-5] =105:5 =21 

100¹¹:105⁸-105³+105⁷=105³-105³+105⁷=105⁷

\(105^5.105^6\div105^8-105^3+105^7\)

\(=105^{11}\div105^8-105^3+105^7\)

\(=105^3-105^3+105^7\)

\(=0+105^7\)

\(=105^7\)

458 x 105 + 324 x 105 + 217 x 105 +105

= 105 x ( 458 + 324 + 217 + 1 )

= 105 x 1000

= 105000

Đây bạn nhé. Nhớ k cho mk nha

\(\dfrac{3}{7}:\dfrac{7}{x}:\dfrac{3}{4}=\dfrac{12}{105}\)

\(\dfrac{3}{7}.\dfrac{x}{7}=\dfrac{3}{35}\)

\(\dfrac{x}{7}=\dfrac{1}{5}\)

\(x=\dfrac{1}{5}.7=\dfrac{7}{5}\)

tìm x biết  :

\(\dfrac{3}{7}\) :  \(\dfrac{7}{x}\) : \(\dfrac{3}{4}\) = \(\dfrac{12}{105}\)

\(\dfrac{3}{7}\) : \(\dfrac{7}{x}\) = \(\dfrac{12}{105}\)\(\times\) \(\dfrac{3}{4}\)

\(\dfrac{3}{7}\) \(\times\) \(\dfrac{x}{7}\) = \(\dfrac{3}{35}\)

        \(\dfrac{x}{7}\) = \(\dfrac{3}{35}\) : \(\dfrac{3}{7}\)

        \(\dfrac{x}{7}\) = \(\dfrac{1}{5}\)

         \(x\) =  \(\dfrac{1}{5}\) \(\times\) 7

         \(x\) = \(\dfrac{7}{5}\)

kết quả là -38

Liệt kê ra bn ơi

bằng 38

\(a,12-\left(4+105-13\right)+\left(4+105-3\right)\)

\(=12-4-105+13+4+105-3\)

\(=12+\left(-4+4\right)+\left(-105+105\right)+\left(13-3\right)\)

\(=12+0+0+10\)

\(=22\)

\(b,-15+\left(-17+21-35\right)+\left(4+105-13\right)\)

\(=-15-17+21-35+4+105-13\)

\(=\left(-15-35\right)+\left(-17-13\right)+\left(21+4+105\right)\)

\(=-50-30+130\)

\(=-50+100\)

\(=50\)

\(c,\left(\left|-5\right|+\left|+7\right|+\left|-9\right|\right)-\left(\left|+5\right|+\left|-7\right|+9\right)\)

\(=\left(5+7+9\right)-\left(5+7+9\right)\)

\(=0\)

Bài 7:

a)(x-15)-75=0

⇔x-15=75

⇔x=90

b)575-(6x+70)=445

⇔6x+70=130

⇔6x=60

⇔x=10

c)x-105:21=15

⇔x-5=15

⇔x=20

d)(x-105):21=15

⇔x-105=315

⇔x=420