tim a, biet: a : 4 + a : 3 =22,75
a:4+a:3=22,75
a=29
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\(a:4+a:3=22,75\)
\(a:\left(4+3\right)=22,75\)
\(a:7=22,75\)
\(a=22,75.7\)
\(a=159,25\)
Ta có ; a : 4 + a : 3 = a\(.\frac{1}{4}+a.\frac{1}{3}=a\left(\frac{1}{4}+\frac{1}{3}\right)=a.\frac{7}{12}\)= 22,75
\(\Rightarrow a=22,75:\frac{7}{12}=39\). Vậy: a=39
a: 4+a:3 = 22,75
a x 1/4 + a x 1/3=22,75
ax(1/4+1/3) =22,75
a x 7/12 =22,75
a =22,75 :7/12
a =39
Toán lớp 5 mà
a: 4+a:3 = 22,75
a: ( 4+3) = 22,75
a = 22,75: 7
a = 3,25
the value of a such that a:4+a:3=22,75
a/4+a/3=22,75
3a/12+4a/12+22,75
7a=273
a=39
The value of a such that
a:4+a:3=22,75
a:(4+3)=22,75
a:7 =22,75
a=22,75x7
a=159,25
tim a,b ,c biet a/2=2b/3=3c/4 biet a-b15
tim a;b;c >o biet ab=3/5; bc=4/5; ca=3/4. Tim a;b;c
tim a biet:(a+1)+(a+2)+(a+3)+(a+4)+(a+5)=315
(a+1)+(a+2)+(a+3)+(a+4)+(a+5)=315
<=> (a+a+a+a+a)+(1+2+3+4+5)=315
<=> 5a+15=315
<=> 5a=300
<=> a=60
(a + 1) + ( a+ 2) + (a + 3 ) + (a + 4 ) + ( a + 5 ) = 315
(a + a + a + a + a) + (1 + 2 + 3 + 4 + 5 ) = 315
a * 5 + 15 = 315
a * 5 = 315 - 15
a * 5 = 300
a = 300 : 5
a = 60
k cho mk nha
5a+15=315
5a=315-15
5a=300
=> a=60
tim a biet .a+a *2+a*3*4+....+a*49+a*50=12750
tim a biet a+a*2+a*3+a*4....+a*49+A*50=12750
a + 2a + 3a +...+ 50a = 12750
=> a(1 + 2 + 3 +...+ 50) = 12750
=> 1275a = 12750
=> a = 10
a+2a+3a+4a+..+50a=12750
<=>(1+2+3+4+..+50).a=12750
<=>\(\left[\frac{50.\left(50+1\right)}{2}\right].a=12750\Rightarrow1275.a=12750\)
<=>a=10
Vậy a=10