\(A=\frac{7a-2}{a-3}=\frac{7\left(a-3\right)+19}{a-3}=7+\frac{19}{a-3}\)

Để A nguyên thì \(\frac{19}{a-3}\) nguyên

Khi \(a-3\in\left\{1;19;-1;-19\right\}\)

\(\Leftrightarrow a\in\left\{4;22;2;-16\right\}\)

Vậy

{9;7;10;6;12;4;16;0}

\(\text{Ta có:}\)

\(\text{Để}\)\(\frac{4b+42}{b+7}\)\(\text{nguyên thì}\)\(4b+42⋮b+7\)

\(\text{Lại có:}\)

\(\text{4b + 42 = 4b + 28 + 14 = 4( b+7 ) + 14}\)

\(\text{Vì}\)\(b+7⋮b+7\)\(\Rightarrow4\left(b+7\right)⋮b+7\)

\(\text{Do đó:}\)\(14⋮b+7\)

\(\Rightarrow b+7\inƯ\left(14\right)=\left\{1;2;7;14\right\}\)

\(\Rightarrow b\in\left\{-6;-5;0;7\right\}\)

 \(\frac{3a+45}{a+9}\)là số nguyên

\(\Rightarrow3a+45⋮a+9\)

Ta có : \(3a+45⋮a+9\)

\(\Rightarrow3a+27+18⋮a+9\)

\(\Rightarrow3\left(a+9\right)+18⋮a+9\)

\(\Rightarrow18⋮a+9\)

\(\Rightarrow a+9\inƯ\left(18\right)=\left\{-18;-9;-6;-3;-2;-1;1;2;3;6;9;18\right\}\)

\(\Rightarrow a\in\left\{-27;-18;-15;-12;-11;-10;-8;-7;-6;-3;0;9\right\}\)

Học tốt!

4x-37 chia hết cho x-6

4x-24-13

=>13 chia hết cho x-6

x=7,19,5,-7

Ta đặt A\(=\dfrac{4c-4+8}{c-1}\) \(\Rightarrow A=\dfrac{4c-4+8}{c-1}=\dfrac{4\left(c-1\right)+8}{c-1}=4+\dfrac{8}{c-1}\)

Để A∈Z \(\Leftrightarrow\) \(4+\dfrac{8}{c-1}\in Z\) \(\Rightarrow\dfrac{8}{c-1}\in Z\) \(\Rightarrow8⋮\left(c-1\right)\) \(\Rightarrow c-1\in\left\{-8;-4;-2;-1;1;2;4;8\right\}\) \(\Rightarrow c\in\left\{-7;-3;-1;0;2;3;5;9\right\}\)

Ta đặt A=\(\dfrac{4n-2}{n-4}\)\(\Rightarrow A=\dfrac{4n-16+14}{n-4}=\dfrac{4\left(n-4\right)+14}{n-4}=4+\dfrac{14}{n-4}\)

Để A\(\in Z\) \(\Leftrightarrow4+\dfrac{14}{n-4}\in Z\) \(\Rightarrow\dfrac{14}{n-4}\in Z\) \(\Rightarrow14⋮\left(n-4\right)\Rightarrow n-4\in\left\{-14;-7;-2;-1;1;2;7;14\right\}\) 

\(\Rightarrow n\in\left\{-10;-3;2;3;5;6;11;18\right\}\)