given the quadrilateral ABCD with two diagonals perpendicular and AB=8cm, BC=7cm, AD=4cm. Evaluate CD
Given the quadrilateral ABCD with two diagonals perpendicular and AB = 8cm, BC = 7cm, AD = 4cm. Evaluate CD.
Answer: CD = cm.
1.Given the quadrilateral ABCD with two diagonals perpendicular and AB = 8cm, BC = 7cm, AD = 4cm. Evaluate CD.
2.Given three consecutive even natural numbers, which have the product of last two numbers is 80 greater than the product of first two numbers.
Find the largest number.
Answer: The largest number is
2) đặt 3 số có dạng a; a+2, a+4 rồi khai triển ra
số lớn nhất là 22
The quadrilateral ABCD has 2 diagonals that are perpendicular lines. AB=8cm, BC=7cm, AD=4cm.
CD=... cm
the right-angled triangle AOD has OD^2+OA^2=AD^2=4^2 cm=16cm(1)
demonstrate **** that we haveOA^2+OB^2=AB^2=8^2cm=64cm(2)
OB^2+OC^2=BC^2=7^2cm=49cm(3)
plus (1) with (2) and (3) (OD^2+OA^2)+(OA^2+OB^2)+(OB^2+OC^2)=16+64+49
2(OA^2+OB^2)+(OC^2+OD^2)=129cm
OC^2+OD^2=129 - 2(OA^2+OB^2)
CD^2=129 - 2.64=1cm
deduce CD=1cm
DC2= 1 cm
thì DC = \(\sqrt{1}\) cm mới đúng chứ nhỉ?!
give isosceles trapezoid abcd ( ab // cd,ab<cd) from a draw ah perpendicular ab , ah intersects bd at h . from b draw bk perpendicular ab , bk intersects ac at k a) what figure is quadrilateral ahkb?why? b) Given that E,F are the midpoints of AB, DC; I and G are respectively the intersection points of AC with BD , CH with DK . Prove that four points E,I,G,F are collincar
Given a trapezoid ABCD with base AB=4cm , CD=6cm , and góc C + góc D = 90 độ . Let M, N be respectively the midpoints of the segments AB and CD . Evaluate MN.
Answer: MN= ? cm
chỗ tiếng việt chỗ tiếng anh là sao
Given a isoseles trapizoid ABCD ( AB paralle CD) AC is perpendicular to BD and the length of the height of the ABCD is 7cm . What is the area of the isoseles trapizoid ABCD ?
I hope to everyone help me to solution this math ! thanks
Cho tứ giác ABCD có AC Vuong goc voi BD. AB=8cm. BC=7cm, AD=4cm. Tinh CD
tứ giác ABCD có hai đường chéo vuông góc và AB=8cm, BC=7cm, AD=4cm. tính độ dài CD=?
Xet tam giac AOB OA^2+OB^2=AB^2
CM Tuong Tu: OD^2=AD^2-OA^2 :OC^2=BC^2-OB^2 (1)
Co DC^2=OD^2+OC^2 (2)
Thay (1) vao (2)Ta duoc
AD^2+BC^2-(OA^2+OB^2)=DC^2 =>4^2+7^2-8^2=DC^2=>DC=1cm
Tứ giác ABCD có hai đường chéo vuông góc và AB = 8cm, BC = 7cm, AD = 4cm. Tính độ dài CD.
Kí hiệu: OA=a, OB=b, OC=c, OD=d
Áp dụng định lí Py-ta-go cho các tam giác vuông tại O ta có:
a^2+b^2=8^2=64
b^2+c^2=7^2=49 (1)
a^2+d^2=4^2=16 (2)
Từ (1) và (2): a^2+b^2+c^2+d^2=65
=> c^2+d^2=65-64=1
Mà CD^2=c^2+d^2=1
=> CD=1cm