\(5\frac{1}{3}+2\frac{2}{5}x1\frac{1}{9}\)
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\(5\frac{1}{3}+2\frac{2}{5}x1\frac{1}{9}\)
\(5\frac{1}{3}\)+ \(2\frac{2}{5}\)x \(1\frac{1}{9}\)
= \(\frac{16}{3}\)+ \(\frac{12}{5}\)x \(\frac{10}{9}\)
= \(\frac{16}{3}\)+ \(\frac{8}{3}\)
= \(\frac{24}{3}\)
= \(8\)
k mình nha
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\(5\frac{1}{3}+2\frac{2}{5}\times1\frac{1}{9}\)
= \(5\frac{1}{3}+\frac{8}{3}\)
= \(\frac{16}{3}+\frac{8}{3}\)
= \(\frac{24}{3}\)
= 8
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\(5\frac{1}{3}+2\frac{2}{5}\times1\frac{1}{9}\)
\(=\frac{16}{3}+\frac{12}{5}\times\frac{10}{9}\)
\(=\frac{16}{3}+\frac{8}{3}=\frac{24}{3}=8\)
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Xem thêm câu trả lời
tính giá trị biểu thức left(frac{17}{10}+7-8,7right):left(frac{23}{4}-frac{11}{2}+frac{9}{25}right)xleft(12,98x0,25right)+12,51frac{2}{24}x5frac{2}{5}x2x3frac{7}{9}x2xfrac{2}{17} 2frac{2}{17}x1frac{1}{24}x5frac{2}{5}x3frac{7}{9}x23xleft(frac{1}{7}+frac{1}{3}-frac{3}{14}right):frac{11}{14}left(1frac{3}{2}+2frac{1}{5}right)x1frac{1}{10}+left(1frac{7}{10}-frac{4}{5}right):frac{3}{7}
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tính giá trị biểu thức
\(\left(\frac{17}{10}+7-8,7\right):\left(\frac{23}{4}-\frac{11}{2}+\frac{9}{25}\right)x\left(12,98x0,25\right)+12,5\)
\(1\frac{2}{24}x5\frac{2}{5}x2x3\frac{7}{9}x2x\frac{2}{17}\)
\(2\frac{2}{17}x1\frac{1}{24}x5\frac{2}{5}x3\frac{7}{9}x2\)
\(3x\left(\frac{1}{7}+\frac{1}{3}-\frac{3}{14}\right):\frac{11}{14}\)
\(\left(1\frac{3}{2}+2\frac{1}{5}\right)x1\frac{1}{10}+\left(1\frac{7}{10}-\frac{4}{5}\right):\frac{3}{7}\)
a)\(\left(1-\frac{1}{2}\right)x\left(1-\frac{1}{3}\right)x\left(1-\frac{1}{4}\right)x\left(1-\frac{1}{5}\right)x......x\left(1-\frac{1}{18}\right)x\left(1-\frac{1}{19}\right)x\left(1-\frac{1}{20}\right)\)
b)\(1\frac{1}{2}x1\frac{1}{3}x1\frac{1}{4}x1\frac{1}{5}x......x1\frac{1}{2005}x1\frac{1}{2006}x1\frac{1}{2007}\)
\(x\)là dấu nhân hả bạn? Nếu vậy thì mk làm cho nhé
\(A=\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot....\cdot\left(1-\frac{1}{20}\right)\)
\(A=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot.......\cdot\frac{17}{18}\cdot\frac{18}{19}\cdot\frac{19}{20}=\frac{1}{20}\)
Vậy \(A=\frac{1}{20}\)
\(B=1\frac{1}{2}\cdot1\frac{1}{3}\cdot1\frac{1}{4}\cdot........\cdot1\frac{1}{2005}\cdot1\frac{1}{2006}\cdot1\frac{1}{2007}\)
\(B=\frac{3}{2}\cdot\frac{4}{3}\cdot\frac{5}{4}\cdot......\cdot\frac{2006}{2005}\cdot\frac{2007}{2006}\cdot\frac{2008}{2007}=\frac{2008}{2}=1004\)
Vậy \(B=1004\)
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DẤU CHẤM LÀ DẤU NHÂN
a,
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}....\frac{19}{20}=\frac{1}{20}\)
b, \(1\frac{1}{2}.1\frac{1}{3}....1\frac{1}{2017}=\frac{3}{2}.\frac{4}{3}....\frac{2018}{2017}=\frac{2018}{2}=1009\)
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\(3\frac{2}{3}+2\frac{1}{5}x1\frac{4}{7}=?\)
\(3\frac{2}{3}-1\frac{1}{5}:2\frac{7}{9}=?\)
Chữ \(x\)\(\)trong câu đầu là dấu "x" (nhân)
b=(6:9\(\frac{3}{5}\) -1\(\frac{1}{7}\) x\(\frac{7}{8}\) ):(4\(\frac{1}{5}\)x\(\frac{10}{11}\) +5\(\frac{2}{11}\) )x1\(\frac{2}{5}\) )x1\(\frac{2}{5}\) x2\(\frac{1}{7}\)
mk đang cần gấp ai nhanh mk tk
HELP ME! 1.frac{3}{4}xfrac{8}{5}:1frac{1}{6}2frac{1}{3}x1frac{1}{4}-frac{7}{5}4frac{2}{3}+1frac{1}{4}+2frac{1}{3}+2frac{3}{7} 2. x.frac{1}{2}frac{3}{4}+frac{1}{5}x-frac{1}{5}frac{2}{3}.frac{9}{4}x.frac{1}{5}+frac{2}{3}frac{5}{4}frac{13}{5}:x-frac{1}{2}frac{4}{5}.frac{15}{16}x:frac{4}{9}+frac{1}{3}frac{2}{5}.1frac{13}{2}Chú ý: Dấu chấm là dấu nhân giúp mị với
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\(HELP\) \(ME\)\(!\)
1.
\(\frac{3}{4}x\frac{8}{5}:1\frac{1}{6}=\)\(2\frac{1}{3}x1\frac{1}{4}-\frac{7}{5}=\)\(4\frac{2}{3}+1\frac{1}{4}+2\frac{1}{3}+2\frac{3}{7}=\)2.
\(x.\frac{1}{2}=\frac{3}{4}+\frac{1}{5}\)\(x-\frac{1}{5}=\frac{2}{3}.\frac{9}{4}\)\(x.\frac{1}{5}+\frac{2}{3}=\frac{5}{4}\)\(\frac{13}{5}:x-\frac{1}{2}=\frac{4}{5}.\frac{15}{16}\)\(x:\frac{4}{9}+\frac{1}{3}=\frac{2}{5}.1\frac{13}{2}\)Chú ý: Dấu chấm là dấu nhângiúp mị với
\(\dfrac{3}{4}\times\dfrac{8}{5}:1\dfrac{1}{6}\)
=\(\dfrac{6}{5}:\) \(\dfrac{7}{6}\)
=\(\dfrac{6}{5}\times\dfrac{6}{7}=\dfrac{36}{35}\)
2\(\dfrac{1}{3}\) x 1\(\dfrac{1}{4}\) -\(\dfrac{7}{5}\)
\(\dfrac{7}{3}\times\dfrac{5}{4}-\) \(\dfrac{7}{5}\)
\(\dfrac{35}{12}-\dfrac{7}{5}\)
\(\dfrac{175}{60}-\dfrac{84}{60}=\dfrac{91}{60}\)
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4\(\dfrac{2}{3}+1\dfrac{1}{4} +2\dfrac{1}{3}+2\dfrac{3}{7}\)
(4 +2) + \(\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\) +1\(\dfrac{1}{4}\) + \(2\dfrac{3}{7}\)
6 + 1 + \(\dfrac{5}{4}\) + \(\dfrac{17}{7}\)
7 + \(\dfrac{103}{28}\)
\(\dfrac{299}{28}\)
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x. \(\dfrac{1}{2}\) =\(\dfrac{3}{4}+\dfrac{1}{5}\)
x . \(\dfrac{1}{2}=\dfrac{15}{20}+\dfrac{4}{20}\)
x.\(\dfrac{1}{2}=\dfrac{19}{20}\)
x = \(\dfrac{19}{20}:\dfrac{1}{2}\)
x = 19/10
\(x-\dfrac{1}{5}=\dfrac{2}{3}\) . \(\dfrac{9}{4}\)
\(x-\dfrac{1}{5}=\) \(\dfrac{3}{2}\)
x = \(\dfrac{3}{2}+\dfrac{1}{5}\)
x =\(\dfrac{15}{10}\) + \(\dfrac{3}{10}\)
x=\(\dfrac{18}{10}\) =\(\dfrac{9}{5}\)
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Xem thêm câu trả lời
1\(\frac{1}{2}\)x1\(\frac{1}{3}\)x1\(\frac{1}{4}\)x1\(\frac{1}{5}\)x1\(\frac{1}{6}\)x1\(\frac{1}{7}\)x1\(\frac{1}{7}\)x1\(\frac{1}{8}\)x 1\(\frac{1}{9}\)x 1\(\frac{1}{10}\)tính bằng cách thuận tiện nhất
Chuyển các hỗn số thành phân số rồi thực hiện phép tính:
a)\(6\frac{1}{7}x1\frac{6}{43}\)
b)\(9\frac{1}{5}:4\frac{3}{5}\)
c)\(2\frac{1}{5}x3\frac{4}{9}\)
d)\(7\frac{2}{3}:2\frac{1}{4}\)
đ)\(4\frac{2}{3}+2\frac{3}{4}x7\frac{3}{11}\)
Tìm X1 ,x2 ,x3,x4,x5
\(\frac{x1-1}{5}=\frac{x2-2}{4}=\frac{x3-3}{3}=\frac{x4-4}{2}=\frac{x5-5}{1}\)\(v\text{à}\)X1 +x2+x3+x4+x5 =30
Đặt \(\frac{x_1-1}{5}=\frac{x_2-2}{4}=\frac{x_3-3}{3}=\frac{x_4-4}{2}=\frac{x_5-5}{1}=k\)
Áp dụng TC DTSBN ta có :
\(k=\frac{\left(x_1-1\right)+\left(x_2-2\right)+\left(x_3-3\right)+\left(x_4-4\right)+\left(x_5-5\right)}{5+4+3+2+1}\)
\(=\frac{x_1+x_2+x_3+x_4+x_5-15}{15}=\frac{30-15}{15}=1\)
\(\frac{x_1-1}{5}=1\Rightarrow x_1=6;\frac{x_2-2}{4}=1\Rightarrow x_2=6;\frac{x_3-3}{3}=1\Rightarrow x_3=6;\frac{x_4-4}{2}=1\Rightarrow x_4=6;\frac{x^5-5}{2}=1\Rightarrow x_5=6\)
Vậy \(x_1=x_2=x_3=x_4=x_5=6\)
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