Bài làm

\(\frac{2^{10}.3^{10}-2^{10}.3^9}{2^9.3^{10}}\)

\(=\frac{2^{10}\left(3^{10}-3^9\right)}{2^9.3^{10}}\)

\(=\frac{2\left[3^9\left(3-1\right)\right]}{3^{10}}\)

\(=\frac{2\left[3^9.2\right]}{3^{10}}\)

\(=\frac{4.3^9}{3^{10}}\)

\(=\frac{4}{3}\)

Vậy giá tị biểu thức là \(\frac{4}{3}\)

4/3 nha bạn 

Phân số trên = 2^10.3^9.(3-1)/2^9.3^10

= 2^10.3^9.2/2^9.3^10

= 2^11.3^9/2^9.3^10

= 2^2/3 = 4/3

Tk mk nha

2¹⁰.3¹⁰-2¹⁰.3⁹ / 2⁹.3¹⁰ =2¹⁰.(3¹⁰-3⁹) / 2⁹.3¹⁰                                                                                                 

                                                  =2¹⁰.3 / 2⁹.3¹⁰

                                                   =2 / 3⁹

\(\frac{2^{10}\cdot3^{10}-2^{10}\cdot3^9}{2^9\cdot3^{10}}\)\(=\frac{2^{10}\cdot3^9\left(3-1\right)}{2^9\cdot3^{10}}\)\(=\frac{2\cdot2}{3}=\frac{4}{3}\)

Vậy \(\frac{2^{10}\cdot3^{10}-2^{10}\cdot3^9}{2^9\cdot3^{10}}=\frac{3}{4}\)

\(\frac{-11^5.13^7}{11^5.13^8}=\frac{\left(-1\right).11^5.13^7}{11^5.13^7.13}=\frac{-1}{13}\)

\(\frac{2^{10}.3^{10}-2^{10}.3^9}{2^9.3^{10}}=\frac{2^{10}.\left(3^{10}-3^9\right)}{2^9.3^{10}}=\frac{2^9.2.3^9.\left(3-1\right)}{2^9.3.3^9}=\frac{2.2}{3}=\frac{4}{3}\)

a, \(\frac{-11^5.13^7}{11^5.13^8}=\frac{-1}{13}\)

b, \(\frac{2^{10}.3^{10}-2^{10}.3^9}{2^9.3^{10}}=\frac{2^{10}.3^9.\left(1-3\right)}{2^9.3^{10}}=\frac{-4}{3}\)

thien ty tfboys ơi cách làm là gì