tim X
a) X-1/8= 2va1/3 nhan 5 va 1/4
b) X:3/2 =1/4
c) 10 va 3/10- x= 4/5
d)x:4/17 = 51
lam nhanh nhanh giup minh
Tim x, biet:
1) -5.(2-x)+4.(x-3)=10.x-15
2) 2.(7x-14)-7.(3x-5)=28
3) 17+x=7+6.x
4) 4.!x-2!=8
5) 4.x-5.(-3+x)=7
mik dag gap lam tra loi nhanh va chi tiet giup mik
1 tim x , biet
a) x - 7va 5/8 = 1 va 1/4
b) x + 7 va 5/8 = 9 va 1/4
c) ( x - 7 va 5/8 ) : 1/2 = 3
d) x / 1x3 + x/3x5+.....+x/97x99=99
giup mik nhanh nha . mik can gap lam
\(a,x-7\frac{5}{8}=1\frac{1}{4}\)
=> \(x-\frac{61}{8}=\frac{5}{4}\)
=> \(x=\frac{5}{4}+\frac{61}{8}\)
=> \(x=\frac{10}{8}+\frac{61}{8}=\frac{71}{8}=8\frac{7}{8}\)
\(b,x+7\frac{5}{8}=9\frac{1}{4}\)
=> \(x+\frac{43}{5}=\frac{37}{4}\)
=> \(x=\frac{37}{4}-\frac{43}{5}=\frac{13}{20}\)
\(c,\left[x-7\frac{5}{8}\right]:\frac{1}{2}=3\)
=> \(\left[x-\frac{61}{8}\right]=3\cdot\frac{1}{2}\)
=> \(\left[x-\frac{61}{8}\right]=\frac{3}{2}\)
=> \(x-\frac{61}{8}=\frac{3}{2}\)
=> \(x=\frac{3}{2}+\frac{61}{8}=\frac{12}{8}+\frac{61}{8}=\frac{73}{8}=9\frac{1}{8}\)
d, \(\frac{x}{1\cdot3}+\frac{x}{3\cdot5}+\frac{x}{5\cdot7}+...+\frac{x}{97\cdot99}=99\)
=> \(\frac{x}{2}\left[\frac{2}{1\cdot3}+\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+...+\frac{2}{97\cdot99}\right]=99\)
=> \(\frac{x}{2}\left[1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{97}-\frac{1}{99}\right]=99\)
=> \(\frac{x}{2}\left[1-\frac{1}{99}\right]=99\)
=> \(\frac{x}{2}\cdot\frac{98}{99}=99\)
=> \(\frac{98x}{198}=99\)
=> 98x = 99 . 198
=> 98x = 19602
=> x = 19602 : 98 = 9801/49
a) \(x-7\frac{5}{8}=1\frac{1}{4}\)
=> \(x=\frac{5}{4}+\frac{61}{8}\)
=> \(x=\frac{71}{8}\)
b) \(x+7\frac{5}{8}=9\frac{1}{4}\)
=> \(x=\frac{37}{4}-\frac{61}{8}\)
=> \(x=\frac{13}{8}\)
c) \(\left(x-7\frac{5}{8}\right):\frac{1}{2}=3\)
=> \(x-\frac{61}{8}=3.\frac{1}{2}\)
=> \(x-\frac{61}{8}=\frac{3}{2}\)
=> \(x=\frac{3}{2}+\frac{61}{8}\)
=> \(x=\frac{73}{8}\)
d) \(\frac{x}{1.3}+\frac{x}{3.5}+...+\frac{x}{97.99}=99\)
=> \(x.\frac{1}{2}.\left(\frac{2}{1.3}+\frac{2}{3.5}+...+\frac{2}{97.99}\right)=99\)
=> \(\frac{1}{2}x\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+....+\frac{1}{97}-\frac{1}{99}\right)=99\)
=> \(x\left(1-\frac{1}{99}\right)=99:\frac{1}{2}\)
=> \(x.\frac{98}{99}=198\)
=> \(x=198:\frac{98}{99}=\frac{9801}{49}\)
\(b,\text{ }x+7\frac{5}{8}=9\frac{1}{4}\)
\(x=9\frac{1}{4}-\left(7+\frac{5}{8}\right)\)
\(x=9+\frac{1}{4}-7-\frac{5}{8}\)
\(x=\left(9-7\right)+\left(\frac{1}{4}-\frac{5}{8}\right)\)
\(x=2+-\frac{3}{8}\)
\(x=2\frac{-3}{8}\)
Ai la nhanh minh tik cho nha
C = 5 va 9/10 ÷ 3/2-(2va1/3×4va1/2-2×2va 1/3) ÷ 7/4
"Va" la hon so nha cac ban
(x-1)nhan(y+10)=5
(x+2)nhan(y-3)=-3 tim y va x
Tim x biet:
a,10+x / x+17=3 / 4
b'40+x / 77-x=6/7
Lam nhanh va cach lam day du minh se tick
Giup minh nka:
1) So sanh:
A=10^2013+2/10^2013-1 va B=10^2013/10^2013-3
2) Tim x
a) 3^x-15.3^8=14.3^8
b)1/3+1/6+1/10+...+2/x(x+1)=49/50
Thank you, minh se chon cau tra li dau tien
giup mk nhanh voi minh can gap lam:tim x thuocZ biet:
10-x-|x+5|=0 va |x-7|+|x+3|=8
10 - x - |x - 5| = 0
=> x - |x - 5| = 10 - 0
=> x - |x - 5| = 10
=> |x - 5| = 10 - x
Điều kiện : 10 - x \(\ge\)0
Khi đó : |x - 5| = 10 - x
=> x - 5 = 10 - x
=> x + x = 10 + 5
=> 2x = 15
=> x = \(\frac{15}{2}\)( x \(\notin\)Z )
Vậy không tồn tại giá trị x.
3 va 1/11 x 27 va 27/46 x 1 va 6/17 x 2 va 4/9 = .....
giai giup minh voi minh gap qua
\(3\frac{3}{11}x27\frac{27}{46}x1\frac{6}{17}x2\frac{4}{9}=\frac{34x1269x23x22}{11x46x17x9}=\frac{2x17x141x9x23x2x11}{11x23x17x9}=282\)
Tim x, y va z, biet :
a) x/2 = y/3 = z/4 va x + y + z =18.
b) x/5 = y/-6 = z/7 va x + y - z =32.
c) x/5 = y/3 = z/2 va 2x + 3y + 4z =54.
d) x/2 = y/3 = z/6 va 3x - 2y + 2z = 24.
Ai biet thi chi giup minh nha. Cang nhanh cang tot ! Minh xin cam on.
X/2=y/2=z/4=x+y+z/9=18/9=2
X=2.2=4
Y=2.3=6
Z=2.4=8
a) x/2 = y/3 = z/4 va x + y + z =18.
Áp dụng tính chất của dãy tỉ số bằng nhau:
x/2 = y/3 = z/4 = x+y+z/2+3+4 = 18 /9 =2
=> x= 2*2 =4
y= 2* 3=6
z=2*4= 8
Vậy x=4; y=6; z=8.
b) x/5 = y/-6 = z/7 va x + y - z =32.
Áp dụng tính chất của dãy tỉ số bằng nhau:
x/5 = y/-6 =z/7 =x+y-z/ 5+(-6) -7 = 32/-8 =-4
=> x= -4 *5 = -20
y= -4* (-6)= 24
z= -4 * 7 = -28
Vậy x=-20 ; y= 24; x= -28.
c) x/5 = y/3 = z/2 va 2x + 3y + 4z =54.
x/5 = 2x/10
y/3 = 3y/9
z/2 = 4z/8
Áp dụng tính chất của dãy tỉ số bằng nhau:
2x/10 = 3y/9 = 4x/8 = 2x+3y+4z/10+9+8 = 54/27= 2
=> x= 2*5 = 10
y= 2*3 =6
x= 2*2 =4
Vậy x= 10; y=6; z=4
d) x/2 = y/3 = z/6 va 3x - 2y + 2z = 24.
x/2 =3x/6
y/3 = 2y/6
z/6 = 2z/12
Áp dụng tính chất của dãy tỉ số bằng nhau:
3x/6 = 2y/6 = 2z/12 = 3x- 2y +2z/6-6+12 = 24/12 =2
=> x= 2*2 =4
y= 2*3 =6
z= 2* 6 =12
Vậy x=4; y=6; z=12