Tìm x: x0x04 + 40x0x + x040x=10101 x 11 x 2

Đáp án bằng X= 9 

biết rồi hỏi làm gì nữa

 X0X04+40X0X+X040X=20202×11
<= >10000 *X + 100 * X + 4 + 40000 + 100 * X + X + 10000 * X + 400 + X =20202×11
<=> 20202 * X + 40404 = 20202×11
<=> 20202 * X + 20202 * 2 = 20202×11
<=> 20202 * ( X + 2) = 20202×11
X + 2 = 11
X = 11 -2 = 9

                               Mình làm đại! Ai thấy đúng thì cho mình nhé! Thank you :)

x0x04+40x0x+x040x=yyyyyy

Thay số:40404+40404+40404=121212

vậy yyyyyy=121212

a)

\(\overline{ab}\times101=\overline{ab}\times\left(100+1\right)=\overline{ab00}+\overline{ab}=\overline{abab}\)

b)

\(\overline{ab}\times10101=\overline{ab}\times\left(10000+101\right)=\overline{ab0000}+\overline{abab}=\overline{ababab}\)

c)

\(\overline{abc}\times1001=\overline{abc}\times\left(1000+1\right)=\overline{abc000}+\overline{abc}=\overline{abcabc}\)

d)

\(\overline{ab}\times1001=\overline{ab}\times\left(1000+1\right)=\overline{ab000}+\overline{ab}=\overline{ab0ab}\)

a/ \(-\frac{81}{504}=-\frac{9}{56};-\frac{10101}{101010}=\frac{-1}{10}\)

b/ \(\frac{72\cdot5+72\cdot3}{144\cdot2+144\cdot6}=\frac{72\left(5+3\right)}{144\left(2+6\right)}=\frac{8}{2\cdot8}=\frac{1}{2}\)

\(\frac{-81}{504}=-\frac{81:9}{504:9}=-\frac{9}{56}\)

\(\frac{-10101}{101010}=\frac{-10101:10101}{101010:10101}=\frac{-1}{10}\)

\(\frac{72.5+72.3}{144.2+144.6}=\frac{72.\left(5+3\right)}{144\left(2+6\right)}=\frac{72.8}{144.8}=\frac{72.8}{72.2.8}=\frac{1}{2}\)

a. -9/56;-1/10

b 1/2

`@` `\text {Ans}`

`\downarrow`

`[ (100 - x)*2 - 2] = 40`

`=> (100-x)*2 - 2 = 40`

`=> (100 - x)*2 = 40 + 2`

`=> (100 - x)*2 = 42`

`=> 100 - x = 42 \div 2`

`=> 100 - x = 21`

`=> x = 100 - 21`

`=> x = 79`

Vậy, `x=79.`

\(\left[\left(100-x\right).2-2\right]=40\)

\(=>\left(100-x\right).2=40+2\)

\(=>\left(100-x\right).2=42\)

\(=>100-x=42:2\)

\(=>100-x=21\)

\(=>x=100-21\)

\(=>x=79\)

Chúc bạn học tốt

[ ( 100 - x ) . 2 - 2 ] = 40

<=> [ (200 - 2x) -2] = 40

<=> 198 - 2x = 40

<=> -2x = -158

<=> x = 79

3x+x3=121 =>x{3+3}=121 =>x9=121 =>sai 

đề sai

\(3x+3x=11\cdot11\)

\(6x=121\)

\(x=\frac{121}{6}\)

( x + 70 ) : 14 - 40 = (32 . 15 ) : 2

( x + 70 ) : 14 - 40 = 240

( x + 70 ) : 14 = 240 + 40 = 280

x + 70 = 280 x 14 = 3920

x = 3920 - 70 

x = 3850

Vậy x = 3850.

(x+70):14-40=(32.15):2

(x+70):14-40=480;2

(x+70):14-40=240

(x+70);14=240+40

(x+70):14=280

(x+70)=280.14

(x+70)=3360

x=3360-70

x=3290