a=7/10+7/10^2+7/10^3+...+7/10^2011
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các bn giúp mình làm câu này nhé:tính A
A= 7/10+7/10^2+7/10^3+...+7/10^2011
A=7/10+7/102+7/103+…+7/102011
Giải chi tiết hộ mình với !!!
Tính A=\(\frac{7}{10}\)+\(\frac{7}{10^2}\)+\(\frac{7}{10^3}\)+.....+\(\frac{7}{10^{2011}}\)
Giải giúp tôi câu này nhé!
Cho A= \(\frac{10^{2011+5}}{10^{2011}-2}\); B= \(\frac{10^{2011}}{10^{2011}-7}\). Hãy so sánh A và B
\(A=\frac{10^{2011}+5}{10^{2011}-2}=\frac{10^{2011}-2+7}{10^{2011}-2}=1+\frac{7}{10^{2011}-2}\)
\(B=\frac{10^{2011}}{10^{2011}-7}=\frac{10^{2011}-7+7}{10^{2011}-7}=1+\frac{7}{10^{2011}-7}\)
Vì \(\frac{7}{10^{2011}-2}< \frac{7}{10^{2011}-7}\Rightarrow1+\frac{7}{10^{2011}-2}< 1+\frac{7}{10^{2011}-7}\Rightarrow A< B\)
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Tính:
B = 1*2+2*3+3*4+...+2011*2012
C =1*50+2*49+3*48+...+49*2+50*1
D = 4*7+7*10+10*13+...+205*208
E = (2+4+6+8+..+2014)-(3+5+7+9+...+2011)
\(2011^{2011}.\left(7^{10}:7^8-3.2^4-2^{2011}:2^{2011}\right)\)
=2011^2011.(7^2-3.2^4-1)
=2011^2011.(49-3.16-1)
=2011^2011.(49-48-1)
=2011^2011.0
=0
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\(2011^{2011}.\left(7^{10}:7^8-3.2^4-2^{2011}:2^{2011}\right)\)
\(2011^{2011}.\left(7^{10}:7^8-3.2^4-2^{2011}:2^{2011}\right)\)
\(=2011^{2011}.\left(7^{10-8}-3.2^4-2^{2011-2011}\right)\)
\(=2011^{2011}.\left(7^2-3.2^4-2^0\right)\)
\(=2011^{2011}.\left(49-3.16-1\right)\)
\(=2011^{2011}.\left(49-48-1\right)\)
\(=2011^{2011}.\left(1-1\right)\)
\(=2011^{2011}.0\)
\(=0\)
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\(A=\left\{\frac{1999}{2011}-\frac{2011}{1999}\right\}-\left\{\frac{-12}{1999}-\frac{12}{2011}\right\}\)
\(B=\frac{2}{5}+\left(\frac{3}{11}+\frac{-2}{5}\right)\)
\(C=\frac{-5}{7}.\frac{4}{13}+\frac{-5}{7}.\frac{9}{13}+\frac{-2}{7}\)
\(D=\frac{-9}{10}.\frac{5}{14}+\frac{1}{10}.\left(\frac{-9}{2}\right)+\frac{1}{7}.\left(\frac{-9}{10}\right)\)
A=7/10+7/10^2+7/10^3+..............+7/10^2018