tim BCNN ; UCLN va BC;UC cua 46;54;112
tim BCNN (8,12)
BCNN(5,7,8)
BCNN(12,16,48)
Biet rang : BCNN(a,b).UCLN(a,b)
a, BCNN cua hai so la 600, UCLN cua chung nho hon 10 lan BCNN. So thu 1 la 120, tim so thu 2.
b, UCLN cua hai so la 12, BCNN cua chung lon gap 6 lan UCLN . So t 1 la 24, tim so t 2
c, Tong cua hai so bang 60, tong giua UCLN va BCNN cua chung la 84. Tim hai so do.
tim BCNN(17,46,220)
Ta có : 17 = 17
46 = 2 . 23
220 = 22 . 5 . 11
=> BCNN ( 17,46,220 ) = 22 . 5 . 11 . 17. 23 = 86020
Tim BCNN(12,16)
12= 22*3
16= 24
BCNN(12,16) = 24*3= 48
Tk nha
Ta có
12=3.4
16=2^4
=>BCNN(12,16)=2^4.3.4=16.3.4=48.4=192
tim BCNN 12,64
Ta có: 12 = 22.3
64 = 26
BCNN(12;64) = 26.3 = 192
12 = 2^2*3
64 = 2^6
=> BCNN (12;64 ) = 2^6*3 = 192
tim UCLN (56,140)va BCNN (56,140)
tim BC (56.140)
UC (56,140)
Tim BCNN(22;24;32)
22=
24=
32=
BCNN(22;24;32)=…....
Ok
ta có :
22 = 2 . 11
24 = 23 . 3
32 = 25
=> BCNN(22;24;32)= 25 . 3 . 11 = 1056
vậy : BCNN(22;24;32)= 1056
Tim BCNN(22;24;32)
22 = 2.11
24 = 23.3
32 = 25
BCNN(22;24;32) = 25.11.3 = 1056
Tim BCNN(22;24;32)
22 = 2.11
24 = 23.3
32 = 25
BCNN(22;24;32) = 25.11.3 = 1056
tim BCNN cua 34;68
tim BCNN cua (16;34;240)
Ta có :
16=2^4
34=2.17
240=2^4.3.5
=>BCNN(16;34;240)=2^4.17.3.5=4080
Vay BCNN(16;34;240)=4080
dung thi k nhe neu sai bao mik thi mik xem lai
OK tks
16 = 24
34 = 2 . 17
240 = 24. 3 . 5
BCNN ( 16;34;240 ) = 24, 3.5.17 = 4080
Đáp án chính là 4080
ta co:16=2^4
34=2.17
240=2^4.3.5
suy ra BCNN cua (16,34,240)=2^4.4.3.5.17=16 320
tim BCNN cua 576;672va996
Vì 576= 26. 32
672= 25. 3.7
996=22. 3 . 83
=> BCNN(576;672;996)= 26 . 32 .7 . 83 = 334656
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